JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Application +4 | -1

\alpha, \beta, \gamma

are roots of equation

x^3-2 x^2-1=0

and

T_n=\alpha^n+\beta^n+\gamma^n

then the value of

\frac{T_{11}-T_8}{T_{10}}

is equal to

View answer and explanation

Correct option: B

Option B (2) is correct because by using the recurrence relation derived from the equation

x^3 - 2x^2 - 1 = 0

, we can express

T_{11}

in terms of

T_{10}

and

T_8

, and then simplify the given expression.

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