JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Analyzing +4 | -1

x_1, x_2, x_3, \ldots, x_n

are the roots of the equation

x^n+a x+b=0

, the value of

\left(x_1-x_2\right)\left(x_1-x_3\right)\left(x_1-x_4\right) \ldots\left(x_1-x_n\right)

View answer and explanation

Correct option: C

n\left(x_1\right)^{n-1}+a

Option C (

n(x_1)^{n-1}+a

) is correct because it is the result of differentiating the polynomial and evaluating it at one of its roots.

More Questions from THEORY OF EQUATION

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{x^{2n}} - 1 = 0

\frac{1}{x}+\frac{1}{\sqrt{\left(1-x^2\right)}}=\frac{35}{12}

x^7+14 x^5+16 x^3+30 x-560=0

P(x)=k x^3+3 x^2-3

Q(x)=2 x^3-5 x+k

(x-4)

k

{\left( {x - 1} \right)^3}

{x^4} + a{x^3} + b{x^2} + cx - 1,

x^4-y^4=3789108