JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Application +4 | -1

\alpha, \beta, \gamma

are the roots of

2 x^3-x+1=0

then the value of

\alpha^3+\beta^3+\gamma^3

View answer and explanation

Correct option: C

-\frac{3}{2}

Option C (-

\frac{3}{2}

) is correct because by using Vieta's formulas and the given cubic equation, we can find the sum of the cubes of the roots.

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