JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

1 of 1

Analyzing +4 | -1

2+3 i

is one of the roots of the equation

2 x^{3}-9 x^{2}+k x-13

=0, \mathrm{k} \in \mathrm{R}

, then the real root of this equation :

View answer and explanation

Correct option: B

exists and is equal to

\frac{1}{2}

Option B exists and is equal to

\frac{1}{2}

is correct because the product of the roots can be used to find the real root.

More Questions from THEORY OF EQUATION

Practice All Chapter MCQs →

{x^{2n}} - 1 = 0

\frac{1}{x}+\frac{1}{\sqrt{\left(1-x^2\right)}}=\frac{35}{12}

x^7+14 x^5+16 x^3+30 x-560=0

x_1, x_2, x_3, \ldots, x_n

x^n+a x+b=0

\left(x_1-x_2\right)\left(x_1-x_3\right)\left(x_1-x_4\right) \ldots\left(x_1-x_n\right)

P(x)=k x^3+3 x^2-3

Q(x)=2 x^3-5 x+k

(x-4)

k

{\left( {x - 1} \right)^3}

{x^4} + a{x^3} + b{x^2} + cx - 1,