The reaction of ${\rm{C}}{{\rm{H}}_3}{\rm{O}}{{\rm{C}}_2}{{\rm{H}}_5}$ with ${\rm{HI}}$ gives:

${\rm{C}}{{\rm{H}}_3}{\rm{I}} + {{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}$

${\rm{C}}{{\rm{H}}_3}{\rm{I}}$ only

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}$ only

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{I}} + {\rm{C}}{{\rm{H}}_3}{\rm{OH}}$

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

1 Medium

1 of 1

Understanding +4 | -1

The reaction of

\mathrm{C}{\mathrm{H}_3}\mathrm{O}{\mathrm{C}_2}{\mathrm{H}_5}

with

\mathrm{HI}

gives:

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{H}_3}\mathrm{I} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

Option C (

\mathrm{C}{\mathrm{H}_3}\mathrm{I} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

) is correct because HI cleaves the ether bond, with the smaller alkyl group forming the iodide and the larger forming the alcohol.