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NEET • CHEMISTRY • ALCOHOLS & PHENOLS & ETHERS

Alcohols & phenols & ethers practice · Mixed difficulty

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Showing 1-30 of 180 questions
1 Easy
1 of 180
Remembering +4 | -1
Ethers are made free from peroxide linkage on distilling impure sample with:
View answer and explanation
Correct option: B
Conc. H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}
Option D (None of these) is correct because ethers are made free from peroxide linkage on distilling impure sample with aqueous ferrous salt solution.
2 Hard
2 of 180
Application +4 | -1
The product 'B' in the following reaction is
CH3CH2OH→PCCA→(ii) H2O/H+(i) HCNB{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}
View answer and explanation
Correct option: D
Both (2) and (3)
Option D (Both (2) and (3)) is correct because the reaction sequence involves oxidation of ethanol to ethanal, followed by reaction with HCN to form a cyanohydrin, which upon hydrolysis yields α\alpha-Hydroxy propionic acid, also known as Lactic acid.
3 Easy
3 of 180
Remembering +4 | -1
Fenton’s reagent is:
View answer and explanation
Correct option: B
H2O2+FeSO4{\mathrm{H}_2}{\mathrm{O}_2} + \mathrm{FeS}{\mathrm{O}_4}
Option B (H2O2+FeSO4{\mathrm{H}_2}{\mathrm{O}_2} + \mathrm{FeS}{\mathrm{O}_4}) is correct because Fenton's reagent is a solution of hydrogen peroxide and ferrous sulfate, used for oxidation.
4 Hard
4 of 180
Analyzing +4 | -1
Assertion:- Isopropyl benzene reacts with O2\mathrm{O}_2 and acid gives phenol.

Reason:- Initially isopropyl benzene converts into 2-phenyl propan-2-ol.
View answer and explanation
Correct option: D
If both Assertion & reason are False
Option D is correct because isopropyl benzene reacts with oxygen in the presence of a catalyst to give phenol and acetone. The initial product is cumene hydroperoxide, not 2-phenylpropan-2-ol.
5 Hard
5 of 180
Understanding +4 | -1
When an ether is treated with P2S5{\mathrm{P}_2}{\mathrm{S}_5} we get:
View answer and explanation
Correct option: C
Thio-ether
Option C (Thio-ether) is correct because P2S5{\mathrm{P}_2}{\mathrm{S}_5} replaces oxygen with sulfur in ethers, forming thioethers.
6 Medium
6 of 180
Understanding +4 | -1
Physical properties of:
View answer and explanation
Correct option: A
Alcohols lie between alkanes and H2O{\mathrm{H}_2}\mathrm{O}
Option A (Alcohols lie between alkanes and H2O{\mathrm{H}_2}\mathrm{O}) is correct because alcohols have intermediate polarity due to the presence of both alkyl and hydroxyl groups, resulting in physical properties between those of nonpolar alkanes and highly polar water.
7 Hard
7 of 180
Analyzing +4 | -1
Find out product (X)(X)
Ph−CH=CH2→(2) HBr(3) Mg, dry ether(4) HCHO(1)B2H6/THF/H2O2/OH−X(major)Ph - CH = C{H_2}\xrightarrow[{\begin{array}{cccccccccccccccccccc} {\left(2 \right)\,HBr} \\ {\left(3 \right)\,Mg,{\text{ dry ether}}} \\ {\left(4 \right)\,HCHO} \end{array}}]{{\left(1 \right){B_2}{H_6}/{\text{THF/}}{H_2}{O_2}/O{H^ - }}}X\left( {{\text{major}}} \right)
View answer and explanation
Correct option: D
Ph−CH2−CH2−CH2−OH{Ph}-{CH}_2-{CH}_2-{CH}_2-{OH}
Option D (Ph−CH2−CH2−CH2−OH{Ph}-{CH}_2-{CH}_2-{CH}_2-{OH}) is correct because the hydroboration-oxidation of styrene gives 2-phenylethanol, which then reacts with HBr to give 1-bromo-2-phenylethane. This reacts with Mg to form a Grignard reagent, which then reacts with formaldehyde to give 3-phenylpropan-1-ol.
8 Easy
8 of 180
Analyzing +4 | -1
An organic liquid AA containing C, H and O has a pleasant odour with a b.p. of 78∘C{78^ \circ }C. On boiling AA with conc. H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} a colourless gas is produced which decolourises bromine water and alkaline KMnO4\mathrm{KMn}{\mathrm{O}_4}. One mole of this gas also takes one mole of H2{\mathrm{H}_2}. The organic liquid A is:
View answer and explanation
Correct option: D
C2H5OH{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}
Option D (C2H5OH{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}) is correct because ethanol dehydrates to ethene, which decolourises bromine water and alkaline KMnO4\mathrm{KMn}{\mathrm{O}_4}.
9 Medium
9 of 180
Analyzing +4 | -1
CH3OC2H5{CH}_3 {OC}_2 {H}_5 and (CH3)3C−OCH3\left({CH}_3\right)_3 {C}-{OCH}_3 are treated with hydroiodic acid. The fragments obtained after reactions are
View answer and explanation
Correct option: A
CH3I+HOC2H5;(CH3)3Cl+HOCH3{CH}_3 {I}+{HOC}_2 {H}_5 ;\left({CH}_3\right)_3 {Cl}+{HOCH}_3
Option A (CH3I+HOC2H5;(CH3)3Cl+HOCH3{CH}_3 {I}+{HOC}_2 {H}_5 ;\left({CH}_3\right)_3 {Cl}+{HOCH}_3) is correct because HI cleaves ethers, with the iodide attacking the less hindered alkyl group. In the case of tert-butyl methyl ether, the reaction proceeds via SN1S_N1 mechanism due to the stability of the tert-butyl carbocation.
10 Hard
10 of 180
Application +4 | -1
When benzene sulphonic acid and p−p -nitrophenol are treated with NaHCO3\mathrm{NaHC}{\mathrm{O}_3}, the gases released respectively are:
View answer and explanation
Correct option: D
NO2,  CO2\mathrm{N}{\mathrm{O}_2},\mathrm{\;C}{\mathrm{O}_2}
The correct answer is D (NO2,  CO2\mathrm{N}{\mathrm{O}_2},\mathrm{\;C}{\mathrm{O}_2}) because benzene sulfonic acid is a strong acid that doesn't react with NaHCO3 to release CO2, while p-nitrophenol is acidic enough to react with NaHCO3 to release CO2.
11 Hard
11 of 180
Application +4 | -1
Among the following, the number of compounds which will not give positive iodoform reaction is

(i) 1- Phenylbutane-2-one

(ii) 2-Methylbutan-2-ol

(iii) 3-Methylbutan-2-ol

(iv) 1-Phenylethanol

(v) 3,3-Dimethylbutan-2-one

(vi) 1-Phenylpropan-2-ol
View answer and explanation
Correct option: A
2
The correct answer is 2. Compounds that do NOT give a positive iodoform test are those lacking a methyl ketone or a secondary alcohol that can be oxidized to a methyl ketone.
12 Easy
12 of 180
Analyzing +4 | -1
Which of the following statements regarding phenols is not correct?
View answer and explanation
Correct option: C
Phenols are soluble in both aqueous NaOH\mathrm{NaOH} and aqueous NaHCO3\mathrm{NaHC}{\mathrm{O}_3}
Option C (Phenols are soluble in both aqueous NaOH\mathrm{NaOH} and aqueous NaHCO3\mathrm{NaHC}{\mathrm{O}_3}) is not correct because phenols are soluble in aqueous NaOH due to the formation of sodium phenoxide, but they are not soluble in aqueous NaHCO3 because they are weaker acids than carbonic acid.
13 Easy
13 of 180
Understanding +4 | -1
R−COOH→RCH2OHR-\mathrm{COOH} \to R\mathrm{C}{\mathrm{H}_2}\mathrm{OH}. This mode of reduction can be effected only by:
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because LiAlH4\mathrm{LiAl}{\mathrm{H}_4}, Na+AlcoholNa\mathrm{ } + \mathrm{ }Alcohol, and NaBH4\mathrm{NaB}{\mathrm{H}_4} can all reduce carboxylic acids to primary alcohols, although LiAlH4\mathrm{LiAl}{\mathrm{H}_4} is the most common and powerful reducing agent for this transformation.
14 Easy
14 of 180
Application +4 | -1
3 moles of ethanol react with one mole of phosphorus tribromide to form 3 moles of bromoethane and one mole of X{X}. Which of the following is X{X} ?
View answer and explanation
Correct option: D
H3PO3{H}_3 {PO}_3
Option D (H3PO3{H}_3 {PO}_3) is correct because the reaction of ethanol with phosphorus tribromide produces bromoethane and phosphorous acid (H3PO3{H}_3 {PO}_3).
15 Hard
15 of 180
Understanding +4 | -1
Diethyl ether and n-propyl methyl ether are
View answer and explanation
Correct option: A
Metamers
Option A (Metamers) is correct because diethyl ether (CH3CH2OCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{O}{\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}}) and n-propyl methyl ether (CH3OCH2CH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{O}{\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}}) have the same molecular formula but different alkyl groups attached to the oxygen atom.
16 Easy
16 of 180
Application +4 | -1
The product C in the following sequence of reaction,
C2H5Br→NaOH  (aq)A→NaB→CH3IC{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Br}\xrightarrow{{\mathrm{NaOH\;}\left( {aq} \right)}}A\mathop \to \limits^{\mathrm{Na}} B\xrightarrow{{\mathrm{C}{\mathrm{H}_3}\mathrm{I}}}C is:
View answer and explanation
Correct option: C
Methyl ethyl ether
Option C (Methyl ethyl ether) is correct because the reaction sequence involves converting ethyl bromide to ethanol, then to sodium ethoxide, and finally reacting with methyl iodide to form methyl ethyl ether (Williamson ether synthesis).
17 Easy
17 of 180
Analyzing +4 | -1
Among the following, which is least acidic?
View answer and explanation
Correct option: B
oo-cresol
Option B (oo-cresol) is correct because the methyl group is electron-donating, destabilizing the phenoxide ion and thus decreasing acidity compared to phenol and halogens/nitro groups which are electron withdrawing.
18 Medium
18 of 180
Understanding +4 | -1
Phenol, pp-methylphenol, mm-nitrophenol and pp-nitrophenol follows order of increasing strength as
View answer and explanation
Correct option: B
pp-methylphenol, pheol, mm-nitrophenol, pp-nitrophenol
Option B (pp-methylphenol, phenol, mm-nitrophenol, pp-nitrophenol) is correct because electron-donating groups decrease acidity, while electron-withdrawing groups increase acidity, and nitro groups are stronger electron-withdrawing groups than methyl groups are electron-donating.
19 Medium
19 of 180
Application +4 | -1
2 mole of ethanol are burnt. The amount of CO2\mathrm{C}{\mathrm{O}_2} obtained will be:
View answer and explanation
Correct option: C
176 g
Option C (176 g) is correct because 2 moles of ethanol produce 4 moles of CO2, which corresponds to 176 g.
20 Medium
20 of 180
Analyzing +4 | -1
Assertion: Hydroquinone is more acidic than resorcinol.

Reason: OHOH shows −I-I effect
View answer and explanation
Correct option: D
If both the Assertion and Reason are incorrect.
Option D (If both the Assertion and Reason are incorrect) is correct because hydroquinone is less acidic than resorcinol, and the -I effect of OH is not the primary reason for the difference in acidity.
21 Medium
21 of 180
Remembering +4 | -1
A diazonium chloride reacts with ϕOH\phi \mathrm{OH} to give an azodye. The reaction is called
View answer and explanation
Correct option: C
Coupling
Option C is correct because the reaction of a diazonium chloride with phenol to form an azodye is called a coupling reaction.
22 Medium
22 of 180
Remembering +4 | -1
The organic compound present in tincture of iodine is:
View answer and explanation
Correct option: A
Alcohol
Option A is correct because tincture of iodine is a solution of iodine in alcohol.
23 Easy
23 of 180
Analyzing +4 | -1
Phenol can be distinguished from ethanol by the following reagents except
View answer and explanation
Correct option: A
Sodium
Option A (Sodium) is correct because both phenol and ethanol react with sodium to liberate hydrogen gas, so it cannot be used to distinguish between them.
24 Hard
24 of 180
Understanding +4 | -1
Diethyl ether is decomposed on heating with:
View answer and explanation
Correct option: D
HI\mathrm{HI}
Option D (HI) is correct because HI cleaves ethers to form alkyl halides and alcohols.
25 Easy
25 of 180
Understanding +4 | -1
Which is not an alcohol?
View answer and explanation
Correct option: D
C6H5OH{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}
Option D (C6H5OH{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}) is correct because it represents phenol, where the OH group is directly attached to the benzene ring, making it an aromatic alcohol (phenol) rather than an aliphatic alcohol.
26 Medium
26 of 180
Application +4 | -1
Which of the following compounds when heated with CO at 150∘C^ \circ C and 500 atm pressure in presence of BF3\mathrm{B}{\mathrm{F}_3} forms ethyl propionate?
View answer and explanation
Correct option: C
C2H5OC2H5{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{O}{\mathrm{C}_2}{\mathrm{H}_5}
Option C (C2H5OC2H5{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{O}{\mathrm{C}_2}{\mathrm{H}_5}) is correct because diethyl ether reacts with CO in the presence of BF3 to form ethyl propionate.
27 Easy
27 of 180
Analyzing +4 | -1
Which of the following is most acidic?
View answer and explanation
Correct option: C
p−p -nitrophenol
Option C (p−p -nitrophenol) is correct because the nitro group is a strong electron-withdrawing group, which stabilizes the phenoxide ion after deprotonation, making it the most acidic.
28 Hard
28 of 180
Analyzing +4 | -1
Assertion:- Dehydration of alcohols always take place in basic medium.

Reason:- OH\mathrm{OH} - is a good leaving group
View answer and explanation
Correct option: D
If both Assertion & reason are False
Option D is correct because dehydration of alcohols typically occurs in acidic medium, and OH- is a poor leaving group.
29 Hard
29 of 180
Understanding +4 | -1
Name the reagent used to convert bromoethane to ethoxy ethane
View answer and explanation
Correct option: A
Sodium ethoxide
Option A (Sodium ethoxide) is correct because sodium ethoxide reacts with bromoethane via Williamson ether synthesis to form ethoxyethane.
30 Hard
30 of 180
Application +4 | -1
To prepare 3-ethylpentane-3-ol, the reactants needed are:
View answer and explanation
Correct option: C
CH3CH2MgBr+CH3CH2COCH2CH3\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{MgBr}+\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COCH}_2 \mathrm{CH}_3
Option C is correct because the reaction of ethyl magnesium bromide with 3-pentanone will produce 3-ethylpentan-3-ol after hydrolysis.
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