${{\rm{C}}_6}{{\rm{H}}_5}{\rm{OH}}$

${\rm{C}}{{\rm{H}}_3}{\rm{COOH}}$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{COOH}}$

${\rm{C}} - {\rm{O}} - {\rm{C}}$angle would be maximum in

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CH}} - {\rm{O}} - {\rm{CH}}{\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}$

${\rm{C}}{{\rm{H}}_3} - {\rm{O}} - {\rm{C}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_3} - {\rm{O}} - {{\rm{C}}_2}{{\rm{H}}_5}$

${{\rm{C}}_2}{{\rm{H}}_5} - {\rm{O}} - {{\rm{C}}_2}{{\rm{H}}_5}$

Which one can differentiate between ${{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}$ and ${\rm{C}}{{\rm{H}}_3}{\rm{OH}}$?

${\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3} + {\rm{\;}}{{\rm{I}}_2}$

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NEET • CHEMISTRY • ALCOHOLS & PHENOLS & ETHERS

Alcohols & phenols & ethers practice · Easy

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1 Easy

1 of 65

Remembering +4 | -1

Ethers are made free from peroxide linkage on distilling impure sample with:

View answer and explanation

Correct option: B

Conc.

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

Option D (None of these) is correct because ethers are made free from peroxide linkage on distilling impure sample with aqueous ferrous salt solution.

2 Easy

2 of 65

Remembering +4 | -1

Fenton’s reagent is:

View answer and explanation

Correct option: B

{\mathrm{H}_2}{\mathrm{O}_2} + \mathrm{FeS}{\mathrm{O}_4}

Option B (

{\mathrm{H}_2}{\mathrm{O}_2} + \mathrm{FeS}{\mathrm{O}_4}

) is correct because Fenton's reagent is a solution of hydrogen peroxide and ferrous sulfate, used for oxidation.

3 Easy

3 of 65

Analyzing +4 | -1

An organic liquid

A

containing C, H and O has a pleasant odour with a b.p. of

{78^ \circ }C

. On boiling

A

with conc.

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

a colourless gas is produced which decolourises bromine water and alkaline

\mathrm{KMn}{\mathrm{O}_4}

. One mole of this gas also takes one mole of

{\mathrm{H}_2}

. The organic liquid A is:

View answer and explanation

Correct option: D

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

Option D (

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

) is correct because ethanol dehydrates to ethene, which decolourises bromine water and alkaline

\mathrm{KMn}{\mathrm{O}_4}

4 Easy

4 of 65

Analyzing +4 | -1

Which of the following statements regarding phenols is not correct?

View answer and explanation

Correct option: C

Phenols are soluble in both aqueous

\mathrm{NaOH}

and aqueous

\mathrm{NaHC}{\mathrm{O}_3}

Option C (Phenols are soluble in both aqueous

\mathrm{NaOH}

and aqueous

\mathrm{NaHC}{\mathrm{O}_3}

) is not correct because phenols are soluble in aqueous NaOH due to the formation of sodium phenoxide, but they are not soluble in aqueous NaHCO3 because they are weaker acids than carbonic acid.

5 Easy

5 of 65

Understanding +4 | -1

R-\mathrm{COOH} \to R\mathrm{C}{\mathrm{H}_2}\mathrm{OH}

. This mode of reduction can be effected only by:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because

\mathrm{LiAl}{\mathrm{H}_4}

Na\mathrm{ } + \mathrm{ }Alcohol

, and

\mathrm{NaB}{\mathrm{H}_4}

can all reduce carboxylic acids to primary alcohols, although

\mathrm{LiAl}{\mathrm{H}_4}

is the most common and powerful reducing agent for this transformation.

6 Easy

6 of 65

Application +4 | -1

3 moles of ethanol react with one mole of phosphorus tribromide to form 3 moles of bromoethane and one mole of

{X}

. Which of the following is

{X}

View answer and explanation

Correct option: D

{H}_3 {PO}_3

Option D (

{H}_3 {PO}_3

) is correct because the reaction of ethanol with phosphorus tribromide produces bromoethane and phosphorous acid (

{H}_3 {PO}_3

7 Easy

7 of 65

Application +4 | -1

The product C in the following sequence of reaction,

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Br}\xrightarrow{{\mathrm{NaOH\;}\left( {aq} \right)}}A\mathop \to \limits^{\mathrm{Na}} B\xrightarrow{{\mathrm{C}{\mathrm{H}_3}\mathrm{I}}}C

is:

View answer and explanation

Correct option: C

Methyl ethyl ether

Option C (Methyl ethyl ether) is correct because the reaction sequence involves converting ethyl bromide to ethanol, then to sodium ethoxide, and finally reacting with methyl iodide to form methyl ethyl ether (Williamson ether synthesis).

8 Easy

8 of 65

Analyzing +4 | -1

Among the following, which is least acidic?

View answer and explanation

Correct option: B

o

-cresol

Option B (

o

-cresol) is correct because the methyl group is electron-donating, destabilizing the phenoxide ion and thus decreasing acidity compared to phenol and halogens/nitro groups which are electron withdrawing.

9 Easy

9 of 65

Analyzing +4 | -1

Phenol can be distinguished from ethanol by the following reagents except

View answer and explanation

Correct option: A

Sodium

Option A (Sodium) is correct because both phenol and ethanol react with sodium to liberate hydrogen gas, so it cannot be used to distinguish between them.

10 Easy

10 of 65

Understanding +4 | -1

Which is not an alcohol?

View answer and explanation

Correct option: D

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}

Option D (

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}

) is correct because it represents phenol, where the OH group is directly attached to the benzene ring, making it an aromatic alcohol (phenol) rather than an aliphatic alcohol.

11 Easy

11 of 65

Analyzing +4 | -1

Which of the following is most acidic?

View answer and explanation

Correct option: C

p -

nitrophenol

Option C (

p -

nitrophenol) is correct because the nitro group is a strong electron-withdrawing group, which stabilizes the phenoxide ion after deprotonation, making it the most acidic.

12 Easy

12 of 65

Application +4 | -1

When

C{H_2} = CH - COOH

is reduced with

LiAl{H_4}

, the compound obtained will be

View answer and explanation

Correct option: B

C{H_2} = CH - C{H_2}OH

Option B (

C{H_2} = CH - C{H_2}OH

) is correct because

LiAlH_4

reduces the carboxylic acid group to a primary alcohol without affecting the alkene.

13 Easy

13 of 65

Application +4 | -1

Sodium ethoxide and ethyl chloride on heating will give:

View answer and explanation

Correct option: A

Ether

Option A (Ether) is correct because sodium ethoxide reacts with ethyl chloride via the Williamson ether synthesis to form diethyl ether.

14 Easy

14 of 65

Understanding +4 | -1

The compound which does not react with sodium is:

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{H}_3}-\mathrm{O}-\mathrm{C}{\mathrm{H}_3}

Option B (

\mathrm{C}{\mathrm{H}_3}-\mathrm{O}-\mathrm{C}{\mathrm{H}_3}

) is correct because ethers do not have acidic hydrogens and therefore do not react with sodium metal.

15 Easy

15 of 65

Remembering +4 | -1

Dialkyl sulphides are known as:

View answer and explanation

Correct option: C

Thioethers

Option C (Thioethers) is correct because dialkyl sulfides are also known as thioethers, analogous to ethers where oxygen is replaced by sulfur.

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16 Easy

16 of 65

Analyzing +4 | -1

Which compound will have highest boiling point?

View answer and explanation

Correct option: C

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

Option C (

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

) has the highest boiling point because it has stronger intermolecular hydrogen bonding compared to the other options.

17 Easy

17 of 65

Application +4 | -1

23 g of sodium react with

\mathrm{C}{\mathrm{H}_3}\mathrm{OH}

to give:

View answer and explanation

Correct option: B

1/2

mole of

{\mathrm{H}_2}

Option B (

1/2

mole of

{\mathrm{H}_2}

) is correct because 2 moles of sodium react with 2 moles of methanol to produce 1 mole of hydrogen gas.

18 Easy

18 of 65

Application +4 | -1

Compound A reacts with

PC{l_5}

to produce B which on treatment with

KCN

following by hydrolysis produce propionic acid. Compound ‘A’ is

View answer and explanation

Correct option: A

{C_2}{H_5}OH

Option A (

{C_2}{H_5}OH

) is correct because ethanol reacts with

PCl_5

to form ethyl chloride, which reacts with KCN to form ethyl cyanide, which hydrolyzes to propionic acid.

19 Easy

19 of 65

Analyzing +4 | -1

How many substituent will increase the acidity of alchol?

-\mathrm{NO}_2,-\mathrm{CH}_3,-\mathrm{O}-\mathrm{CH}_3,-\mathrm{Br},-\mathrm{CHO}

View answer and explanation

Correct option: A

Option A (3) is correct because electron-withdrawing groups like

-\mathrm{NO}_2

-\mathrm{Br}

, and

-\mathrm{CHO}

increase acidity.

20 Easy

20 of 65

Understanding +4 | -1

Which of the following is simple ether?

View answer and explanation

Correct option: D

\mathrm{MeOMe}

Option D (MeOMe) is correct because MeOMe (dimethyl ether) is the simplest ether, consisting of two methyl groups bonded to an oxygen atom.

21 Easy

21 of 65

Remembering +4 | -1

Carbolic acid is

View answer and explanation

Correct option: D

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}

Option D is correct because the chemical formula for carbolic acid (phenol) is C6H5OH.

22 Easy

22 of 65

Remembering +4 | -1

The formula of phenoxy benzene is:

View answer and explanation

Correct option: B

{\mathrm{C}_6}{\mathrm{H}_5} - \mathrm{O} - {\mathrm{C}_6}{\mathrm{H}_5}

Option B (

{\mathrm{C}_6}{\mathrm{H}_5} - \mathrm{O} - {\mathrm{C}_6}{\mathrm{H}_5}

) is correct because phenoxybenzene is an ether where an oxygen atom is bonded to two phenyl groups.

23 Easy

23 of 65

Analyzing +4 | -1

Assertion (A): Phenoxide ion is more stable than carboxylate ion.
Reason (R): The –ve charge is delocalized over two electronegative atoms in carboxylate ion.

View answer and explanation

Correct option: B

Both A & R are correct and not correct explanation

Option B (Both A & R are correct and not correct explanation) is correct because while both the assertion and the reason are true, the reason does not fully explain why the phenoxide ion is more stable.

24 Easy

24 of 65

Analyzing +4 | -1

\mathrm{C} - \mathrm{O} - \mathrm{C}

angle would be maximum in

View answer and explanation

Correct option: D

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CH} - \mathrm{O} - \mathrm{CH}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}

Option D (

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CH} - \mathrm{O} - \mathrm{CH}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}

) is correct because the bulky isopropyl groups attached to the oxygen atom experience greater steric repulsion, leading to a larger bond angle.

25 Easy

25 of 65

Analyzing +4 | -1

Which one can differentiate between

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

and

\mathrm{C}{\mathrm{H}_3}\mathrm{OH}

View answer and explanation

Correct option: B

\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3} + \mathrm{\;}{\mathrm{I}_2}

Option B (

{\mathrm{N}_2}\mathrm{C}{\mathrm{O}_3} + \mathrm{\;}{\mathrm{I}_2}

) is correct because it can be used in the iodoform test, which differentiates between ethanol and methanol.

26 Easy

26 of 65

Remembering +4 | -1

Phthalein test is characteristics of ….and is given by it.

View answer and explanation

Correct option: B

Phenols

Option B is correct because the phthalein test is a characteristic reaction of phenols.

27 Easy

27 of 65

Remembering +4 | -1

The alcohol manufactured from water gas is

View answer and explanation

Correct option: A

\mathrm{C}{\mathrm{H}_3}\mathrm{OH}

Option A (

\mathrm{C}{\mathrm{H}_3}\mathrm{OH}

) is correct because methanol is manufactured from water gas (CO + H₂).

28 Easy

28 of 65

Remembering +4 | -1

Picric acid is a yellow coloured compound. Its chemical name is:

View answer and explanation

Correct option: B

2,4,6-trinitrophenol

Option B is correct because picric acid is 2,4,6-trinitrophenol.

29 Easy

29 of 65

Application +4 | -1

To prepare an ether by Williamson’s synthesis, the reactants needed are

View answer and explanation

Correct option: C

Sodium tertiary butoxide and ethyl bromide

Option C (Sodium tertiary butoxide and ethyl bromide) is correct because it follows the Williamson ether synthesis which requires a primary alkyl halide (ethyl bromide) and an alkoxide (sodium tert-butoxide).

30 Easy

30 of 65

Analyzing +4 | -1

\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}

and

\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}

can be distinguished by

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because each of the listed reagents can be used to distinguish between ethanol and phenol due to their different chemical properties and reactivity.

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Key Takeaways

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