NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Physical properties of:

View answer and explanation

Correct option: A

Alcohols lie between alkanes and

{\mathrm{H}_2}\mathrm{O}

Option A (Alcohols lie between alkanes and

{\mathrm{H}_2}\mathrm{O}

) is correct because alcohols have intermediate polarity due to the presence of both alkyl and hydroxyl groups, resulting in physical properties between those of nonpolar alkanes and highly polar water.

More Questions from ALCOHOLS & PHENOLS & ETHERS

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Ethers are made free from peroxide linkage on distilling impure sample with: The product 'B' in the following reaction is

{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

Fenton’s reagent is: Assertion:- Isopropyl benzene reacts with

\mathrm{O}_2

and acid gives phenol.

Reason:- Initially isopropyl benzene converts into 2-phenyl propan-2-ol. When an ether is treated with

{\mathrm{P}_2}{\mathrm{S}_5}

we get: Find out product

(X)

Ph - CH = C{H_2}\xrightarrow[{\begin{array}{cccccccccccccccccccc} {\left(2 \right)\,HBr} \\ {\left(3 \right)\,Mg,{\text{ dry ether}}} \\ {\left(4 \right)\,HCHO} \end{array}}]{{\left(1 \right){B_2}{H_6}/{\text{THF/}}{H_2}{O_2}/O{H^ - }}}X\left( {{\text{major}}} \right)