NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Ethers are made free from peroxide linkage on distilling impure sample with:

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Correct option: B

Conc.

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

Option D (None of these) is correct because ethers are made free from peroxide linkage on distilling impure sample with aqueous ferrous salt solution.

More Questions from ALCOHOLS & PHENOLS & ETHERS

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The product 'B' in the following reaction is

{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

Fenton’s reagent is: Assertion:- Isopropyl benzene reacts with

\mathrm{O}_2

and acid gives phenol.

Reason:- Initially isopropyl benzene converts into 2-phenyl propan-2-ol. When an ether is treated with

{\mathrm{P}_2}{\mathrm{S}_5}

we get: Physical properties of: Find out product

(X)

Ph - CH = C{H_2}\xrightarrow[{\begin{array}{cccccccccccccccccccc} {\left(2 \right)\,HBr} \\ {\left(3 \right)\,Mg,{\text{ dry ether}}} \\ {\left(4 \right)\,HCHO} \end{array}}]{{\left(1 \right){B_2}{H_6}/{\text{THF/}}{H_2}{O_2}/O{H^ - }}}X\left( {{\text{major}}} \right)