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NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

1 Hard
1 of 1
Analyzing +4 | -1
Find out product (X)(X)
Ph−CH=CH2→(2) HBr(3) Mg, dry ether(4) HCHO(1)B2H6/THF/H2O2/OH−X(major)Ph - CH = C{H_2}\xrightarrow[{\begin{array}{cccccccccccccccccccc} {\left(2 \right)\,HBr} \\ {\left(3 \right)\,Mg,{\text{ dry ether}}} \\ {\left(4 \right)\,HCHO} \end{array}}]{{\left(1 \right){B_2}{H_6}/{\text{THF/}}{H_2}{O_2}/O{H^ - }}}X\left( {{\text{major}}} \right)
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Correct option: D
Ph−CH2−CH2−CH2−OH{Ph}-{CH}_2-{CH}_2-{CH}_2-{OH}
Option D (Ph−CH2−CH2−CH2−OH{Ph}-{CH}_2-{CH}_2-{CH}_2-{OH}) is correct because the hydroboration-oxidation of styrene gives 2-phenylethanol, which then reacts with HBr to give 1-bromo-2-phenylethane. This reacts with Mg to form a Grignard reagent, which then reacts with formaldehyde to give 3-phenylpropan-1-ol.

More Questions from ALCOHOLS & PHENOLS & ETHERS

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Ethers are made free from peroxide linkage on distilling impure sample with: The product 'B' in the following reaction is
CH3CH2OH→PCCA→(ii) H2O/H+(i) HCNB{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}} Fenton’s reagent is: Assertion:- Isopropyl benzene reacts with O2\mathrm{O}_2 and acid gives phenol.

Reason:- Initially isopropyl benzene converts into 2-phenyl propan-2-ol. When an ether is treated with P2S5{\mathrm{P}_2}{\mathrm{S}_5} we get: Physical properties of:
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