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JEE MATHEMATICS MCQ: THEORY OF EQUATION

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If the functions f(x)=x33+2bx+ax22f(x)=\frac{x^3}{3}+2 b x+\frac{a x^2}{2} and g(x)=x33+ax+bx2,a≠2bg(x)=\frac{x^3}{3}+a x+b x^2, a \neq 2 b have a common extreme point, then a+2b+7a+2 b+7 is equal to
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Correct option: C
6
The correct answer is 6 because the common extreme point implies that the derivatives of the two functions have a common root, which allows us to solve for a + 2b + 7.

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