The compound $B\;$ formed in the following sequence of reactions, ${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_2}{\rm{OH}}\xrightarrow{{{\rm{PC}}{{\rm{l}}_5}}}A\xrightarrow{{{\rm{Alc}}.{\rm{\;NaOH}}}}B$ will be:

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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The compound

B\;

formed in the following sequence of reactions,

\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}\xrightarrow{{\mathrm{PC}{\mathrm{l}_5}}}A\xrightarrow{{\mathrm{Alc}.\mathrm{\;NaOH}}}B

will be:

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Correct option: B

Propene

Option B (Propene) is correct because the reaction sequence involves converting an alcohol to an alkyl halide, followed by elimination to form an alkene.

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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