${\rm{HBr}}$ reacts with${\rm{C}}{{\rm{H}}_2}$=${\rm{CH}}$—${\rm{OC}}{{\rm{H}}_3}$ under anhydrous conditions at room temperature to give:

${{\rm{H}}_3}{\rm{C}}$—${\rm{CHBr}}$—${\rm{OC}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_3}{\rm{CHO}}$ and C${\rm{C}}{{\rm{H}}_3}{\rm{CHO}}$

${\rm{BrC}}{{\rm{H}}_2}{\rm{CHO}}$ and ${\rm{C}}{{\rm{H}}_3}{\rm{OH}}$

${\rm{BrC}}{{\rm{H}}_2}$—${\rm{C}}{{\rm{H}}_2}$—${\rm{OC}}{{\rm{H}}_3}$

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NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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\mathrm{HBr}

reacts with

\mathrm{C}{\mathrm{H}_2}

\mathrm{CH}

—

\mathrm{OC}{\mathrm{H}_3}

under anhydrous conditions at room temperature to give:

View answer and explanation

Correct option: D

{\mathrm{H}_3}\mathrm{C}

—

\mathrm{CHBr}

—

\mathrm{OC}{\mathrm{H}_3}

The correct answer is D (

{\mathrm{H}_3}\mathrm{C}

—

\mathrm{CHBr}

—

\mathrm{OC}{\mathrm{H}_3}

) because the reaction follows Markovnikov's rule, where the hydrogen adds to the carbon with more hydrogens and the bromine adds to the other carbon.

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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