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JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Application +4 | -1
If α,  β,  γ\alpha ,\;\beta ,\;\gamma are the roots of x3+2x2−3x−1=0{x^3} + 2{x^2} - 3x - 1 = 0, then α−2+β−2+γ−2{\alpha ^{ - 2}} + {\beta ^{ - 2}} + {\gamma ^{ - 2}} is equal to
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Correct option: B
13
Option B (13) is correct because it is the value of the expression α−2+β−2+γ−2{\alpha ^{ - 2}} + {\beta ^{ - 2}} + {\gamma ^{ - 2}} calculated using Vieta's formulas.

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