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NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Application +4 | -1
In the reaction, the products formed are:

(CH3)2CH2⋅CH2⋅O⋅CH2CH3+HI→Heated{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{C}{\mathrm{H}_2} \cdot \mathrm{C}{\mathrm{H}_2} \cdot \mathrm{O} \cdot \mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3} + \mathrm{HI}\xrightarrow{{\mathrm{Heated}}}
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Correct option: C
(CH3)2CHCH2OH+C2H5I{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CHC}{\mathrm{H}_2}\mathrm{OH} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{I}
Option C is correct because HI cleaves the ether at the less substituted side via SN1 or SN2 mechanism, forming an alcohol and an alkyl iodide.

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