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JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Application +4 | -1
If α,β,γ\alpha ,\beta ,\gamma are the roots of the equation x3+x+1=0{x^3} + x + 1 = 0, then the value of α3+β3+γ3{\alpha ^3} + {\beta ^3} + {\gamma ^3} is
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Correct option: C
−3- 3
Option C (−3-3) is correct because it is the value of α3+β3+γ3{\alpha ^3} + {\beta ^3} + {\gamma ^3} calculated using Vieta's formulas and the given cubic equation.

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