${\rm{C}} - {\rm{O}} - {\rm{C}}$angle would be maximum in

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CH}} - {\rm{O}} - {\rm{CH}}{\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}$

${\rm{C}}{{\rm{H}}_3} - {\rm{O}} - {\rm{C}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_3} - {\rm{O}} - {{\rm{C}}_2}{{\rm{H}}_5}$

${{\rm{C}}_2}{{\rm{H}}_5} - {\rm{O}} - {{\rm{C}}_2}{{\rm{H}}_5}$

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

1 Easy

1 of 1

Analyzing +4 | -1

\mathrm{C} - \mathrm{O} - \mathrm{C}

angle would be maximum in

View answer and explanation

Correct option: D

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CH} - \mathrm{O} - \mathrm{CH}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}

Option D (

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CH} - \mathrm{O} - \mathrm{CH}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}

) is correct because the bulky isopropyl groups attached to the oxygen atom experience greater steric repulsion, leading to a larger bond angle.