JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

1 of 1

Application +4 | -1

\alpha ,\beta ,\gamma

are the roots of the equation

2{x^3} - 3{x^2} + 6x + 1 = 0

, then

{\alpha ^2} + {\beta ^2} + {\gamma ^2}

is equal to

View answer and explanation

Correct option: A

- \frac{{15}}{4}

Option A (

\frac{{ - 15}}{4}

) is correct because it is the result of applying Vieta's formulas and algebraic manipulation to find the sum of the squares of the roots.

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