JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Application +4 | -1

Let

f(x)=a x^3+b x^2+c x+41

be such that

f(1)=40, f^{\prime}(1)=2

and

f^{\prime\prime}(1)=4

. Then

a^2+b^2+c^2

is equal to:

View answer and explanation

Correct option: D

Option D (51) is correct because it is the sum of squares of a, b, and c, where a, b, and c are coefficients found by using the given conditions and derivatives.

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