NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Analyzing +4 | -1

Decreasing order of reactivity in Williamson's ether synthesis of the following.

I.

{Me}_3 {CCH}_2 {Br}

II.

{CH}_3 {CH}_2 {CH}_2 {Br}

III.

{CH}_2={CHCH}_2 {Cl}

IV.

{CH}_3 {CH}_2 {CH}_2 {CH}_2 {Cl}

View answer and explanation

Correct option: D

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III

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Option B (III

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I) is correct because the reactivity in Williamson's ether synthesis depends on the substrate's ability to undergo SN2 reaction. Allylic halides (III) are most reactive, followed by primary alkyl halides (II and IV), and then sterically hindered halides (I).

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Ethers are made free from peroxide linkage on distilling impure sample with: The product 'B' in the following reaction is

{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

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{\mathrm{P}_2}{\mathrm{S}_5}

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