JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

1 of 1

Application +4 | -1

If the roots of

{x^3} - 3{x^2} - 6x + 8 = 0

are in arithmetic progression, then the roots of the equation are

View answer and explanation

Correct option: C

- 2,1,4

Option C (

-2, 1, 4

) is correct because the sum of these roots is 3, which matches the coefficient of the x² term in the given cubic equation.

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