JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Analyzing +4 | -1

\alpha ,\;\beta ,\;\gamma

are the roots of

{x^3} + 4x + 1 = 0

, then the equation whose roots are

\frac{{{\alpha ^2}}}{{\beta + \gamma }},\;\frac{{{\beta ^2}}}{{\alpha + \gamma }},\;\frac{{{\gamma ^2}}}{{\alpha + \beta }}

View answer and explanation

Correct option: C

{x^3} + 4x - 1 = 0

Option D (None of these) is correct because the determinant simplifies to 0, regardless of the values of

\alpha

and

\beta

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