JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

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Application +4 | -1

\alpha ,\beta

are roots of

a{x^2} + bx + c = 0,

then the equation

a{x^2} - bx\left( {x - 1} \right) + c{\left( {x - 1} \right)^2} = 0

has roots

View answer and explanation

Correct option: C

\frac{\alpha }{{\alpha + 1}},\frac{\beta }{{\beta + 1}}

Option C (

\frac{\alpha}{{\alpha + 1}},\frac{\beta}{{\beta + 1}}

) is correct because the roots of the transformed quadratic equation are related to the roots of the original equation in this specific way.

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