NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

1 Hard

1 of 1

Analyzing +4 | -1

\mathrm{C}_4 \mathrm{H}_{10} \mathrm{O}(\mathrm{X}) \xrightarrow{\mathrm{KMnO}_4 / \mathrm{H}^{+}} \mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_2.

'X' can be

A) n-butyl alcohol

B)

2^\circ

butyl alcohol

C) Isobutyl alcohol

D)

3^\circ

butyl alcohol

View answer and explanation

Correct option: C

A and C only

Option C is correct because primary and secondary alcohols can be oxidized to carboxylic acids, while tertiary alcohols are resistant to oxidation under these conditions.

More Questions from ALCOHOLS & PHENOLS & ETHERS

Practice All Chapter MCQs →

Ethers are made free from peroxide linkage on distilling impure sample with: The product 'B' in the following reaction is

{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

Fenton’s reagent is: Assertion:- Isopropyl benzene reacts with

\mathrm{O}_2

and acid gives phenol.

Reason:- Initially isopropyl benzene converts into 2-phenyl propan-2-ol. When an ether is treated with

{\mathrm{P}_2}{\mathrm{S}_5}

we get: Physical properties of: