NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Analyzing +4 | -1

Oxidation of allyl alcohol,

(\mathrm{C}{\mathrm{H}_2}

\mathrm{CH}

—

\mathrm{C}{\mathrm{H}_2}\mathrm{OH})

gives a mixture of oxalic acid and formic acid. If this oxidation is done in presence of bromine. One would expect only:

View answer and explanation

Correct option: D

Acrylic acid

Option D is correct because oxidation of allyl alcohol in the presence of bromine leads to the formation of acrylic acid.

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{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

\mathrm{O}_2

{\mathrm{P}_2}{\mathrm{S}_5}