23 g of sodium react with ${\rm{C}}{{\rm{H}}_3}{\rm{OH}}$ to give:

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

1 Easy

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23 g of sodium react with

\mathrm{C}{\mathrm{H}_3}\mathrm{OH}

to give:

View answer and explanation

Correct option: B

1/2

mole of

{\mathrm{H}_2}

Option B (

1/2

mole of

{\mathrm{H}_2}

) is correct because 2 moles of sodium react with 2 moles of methanol to produce 1 mole of hydrogen gas.

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{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

\mathrm{O}_2

{\mathrm{P}_2}{\mathrm{S}_5}