JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

1 of 1

Application +4 | -1

\alpha ,\;\beta ,\gamma

are the roots of

{x^3} + 2{x^2} - 3x - 1 = 0

, then

{\alpha ^{ - 2}} + {\beta ^{ - 2}} + {\gamma ^{ - 2}}

is equal to

View answer and explanation

Correct option: B

Option B (13) is correct because by using Vieta's formulas and manipulating the expressions, we can find the value of the given expression.

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