NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Application +4 | -1

When

C{H_2} = CH - COOH

is reduced with

LiAl{H_4}

, the compound obtained will be

View answer and explanation

Correct option: B

C{H_2} = CH - C{H_2}OH

Option B (

C{H_2} = CH - C{H_2}OH

) is correct because

LiAlH_4

reduces the carboxylic acid group to a primary alcohol without affecting the alkene.

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{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

\mathrm{O}_2

{\mathrm{P}_2}{\mathrm{S}_5}