The product C in the following sequence of reaction, ${{\rm{C}}_2}{{\rm{H}}_5}{\rm{Br}}\xrightarrow{{{\rm{NaOH\;}}\left( {aq} \right)}}A\mathop \to \limits^{{\rm{Na}}} B\xrightarrow{{{\rm{C}}{{\rm{H}}_3}{\rm{I}}}}C$ is:

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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The product C in the following sequence of reaction,

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Br}\xrightarrow{{\mathrm{NaOH\;}\left( {aq} \right)}}A\mathop \to \limits^{\mathrm{Na}} B\xrightarrow{{\mathrm{C}{\mathrm{H}_3}\mathrm{I}}}C

is:

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Correct option: C

Methyl ethyl ether

Option C (Methyl ethyl ether) is correct because the reaction sequence involves converting ethyl bromide to ethanol, then to sodium ethoxide, and finally reacting with methyl iodide to form methyl ethyl ether (Williamson ether synthesis).

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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