JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Analyzing +4 | -1

The sum of all the real roots of the equation

({e^{2x}} - 4)(6{e^{2x}} - 5{e^x} + 1) = 0

View answer and explanation

Correct option: B

- {\log _e}3

Option B (

- \log_e 3

) is correct because it is the sum of the real roots obtained by solving the given equation.

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{x^{2n}} - 1 = 0

\frac{1}{x}+\frac{1}{\sqrt{\left(1-x^2\right)}}=\frac{35}{12}

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x^n+a x+b=0

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P(x)=k x^3+3 x^2-3

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