$R-{\rm{COOH}} \to R{\rm{C}}{{\rm{H}}_2}{\rm{OH}}$. This mode of reduction can be effected only by:

NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

1 Easy

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Understanding +4 | -1

R-\mathrm{COOH} \to R\mathrm{C}{\mathrm{H}_2}\mathrm{OH}

. This mode of reduction can be effected only by:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because

\mathrm{LiAl}{\mathrm{H}_4}

Na\mathrm{ } + \mathrm{ }Alcohol

, and

\mathrm{NaB}{\mathrm{H}_4}

can all reduce carboxylic acids to primary alcohols, although

\mathrm{LiAl}{\mathrm{H}_4}

is the most common and powerful reducing agent for this transformation.

Practice All Chapter MCQs →

{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

\mathrm{O}_2

{\mathrm{P}_2}{\mathrm{S}_5}