NEET UG CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Analyzing +4 | -1

{CH}_3 {OC}_2 {H}_5

and

\left({CH}_3\right)_3 {C}-{OCH}_3

are treated with hydroiodic acid. The fragments obtained after reactions are

View answer and explanation

Correct option: A

{CH}_3 {I}+{HOC}_2 {H}_5 ;\left({CH}_3\right)_3 {Cl}+{HOCH}_3

Option A (

{CH}_3 {I}+{HOC}_2 {H}_5 ;\left({CH}_3\right)_3 {Cl}+{HOCH}_3

) is correct because HI cleaves ethers, with the iodide attacking the less hindered alkyl group. In the case of tert-butyl methyl ether, the reaction proceeds via

S_N1

mechanism due to the stability of the tert-butyl carbocation.

More Questions from ALCOHOLS & PHENOLS & ETHERS

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Ethers are made free from peroxide linkage on distilling impure sample with: The product 'B' in the following reaction is

{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{OH}}\xrightarrow{{{\text{PCC}}}}{\text{A}}\xrightarrow[{\left( {{\text{ii}}} \right){\text{ }}{{\text{H}}_2}{\text{O/}}{{\text{H}}^ + }}]{{\left( {\text{i}} \right){\text{ HCN}}}}{\text{B}}

Fenton’s reagent is: Assertion:- Isopropyl benzene reacts with

\mathrm{O}_2

and acid gives phenol.

Reason:- Initially isopropyl benzene converts into 2-phenyl propan-2-ol. When an ether is treated with

{\mathrm{P}_2}{\mathrm{S}_5}

we get: Physical properties of: