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JEE Main · Part 3 of 4

JEE Main Physics and Chemistry: make calculations reliable

Check the model, units and approximation before trying to improve your speed.

Concept guide · About 4 min to read

TopAll Editorial · Source check: 19 October 2026

Published: 18 October 2026 · Updated: 20 October 2026

What you will take away

  • Fast calculation is useful after the correct physical or chemical model is chosen.
  • Keep units attached until the final answer.
  • Approximate relations need an approximation label and their assumptions.

Start here if: Know Ohm’s law and basic unit conversion.

Jump to a section

Use the actual numerical-answer instructions

For JEE Main 2025, the bulletin specifies negative marking for numerical questions and tells candidates how to round the answer. Read that rule with the question’s supplied constants. It does not assign every Chemistry numerical to one branch of Chemistry or promise a particular score in a fixed number of minutes.

Sources: NTA JEE Main 2025 information bulletin.

A useful practice log distinguishes selecting the wrong model, using inconsistent units, arithmetic slips and answer-entry mistakes. Only the last two are repaired mainly by faster calculation practice.

Make the assumptions visible

For a circuit, identify which elements are connected in series or parallel and whether the battery or conductor model is ideal. For a chemical calculation, name the concentration, temperature or reaction assumptions. Write the relation before inserting the values.

Sources: NCERT Physics, Current Electricity, NCERT Chemistry, Electrochemistry.

Start with one familiar topic if you are building confidence. If you already know the equations, vary one condition at a time and predict the direction of the result before computing it. This makes a plausible-looking wrong answer easier to catch.

Work through this example

Original teaching example. Two resistors of 2 Ω and 4 Ω are in series across an ideal 12 V supply. The equivalent resistance is 6 Ω, so the current is 12/6 = 2 A. Total power is VI = 24 W. The 4 Ω resistor dissipates I²R = 16 W; the 2 Ω resistor dissipates 8 W. Their sum is 24 W, providing an independent check.

Label an approximation correctly

For a first-order decay model, the fraction remaining after ten half-lives is (1/2)10 = 1/1024, about 0.09766%. Thus about 99.90234% has decayed. Ten half-lives is a close approximation to 99.9% completion, not an exact identity. Solving 2−n = 0.001 gives n = log2(1000), about 9.966.

In your next task, write one model, one unit conversion and one check beside each solution. The linked Current Electricity practice is a place to rehearse that routine. Keep Chemistry revision in a separate short session if switching subjects makes your error review superficial.

Check your understanding

In the series circuit example, can each resistor have the full 12 V across it?

Show the reasoning

No. The same current passes through both; the voltage drops are 4 V and 8 V, adding to 12 V. Giving both the full supply voltage would describe a different connection.

Your next study session

Practise, then review your mistakes

Suggested task: choose 10 available chapter questions, allowing about 15 minutes plus error review. Adjust the pace if you are learning the concept for the first time.

  1. Answer ten available questions without notes. This is a suggested task, not a separately filtered ten-question paper.
  2. For each error, record the concept, the step you missed and a short correction.
  3. Return to the same concept after a break and explain the correction before trying a new question.
Open chapter practice →

Sources and method

Historical examination facts use the cited official documents and exact page locators. Study routines and teaching examples are original editorial suggestions. No question-share percentage or future score, rank or admission guarantee is inferred. Current NCERT reprints support concepts, not historical wording.

  1. NTA JEE Main 2025 information bulletin

    2025 · PDF pages 17–21, Paper 1 pattern, marking and duration · Checked 2026-10-19

  2. NCERT Physics, Current Electricity

    2026–27 reprint · Sections 3.4 and 3.5, Ohm’s law, resistivity and resistance · Checked 2026-10-19

  3. NCERT Chemistry, Electrochemistry

    2026–27 reprint · Cell potential and the relation between Gibbs energy and electrical work · Checked 2026-10-19

Frequently asked questions

Start with your question. Open an answer, then choose one study task to try.

How can I check the series-circuit answer independently?

The 2 Ω and 4 Ω resistors total 6 Ω, so a 12 V ideal supply gives 2 A. Their powers are 8 W and 16 W, adding to the total 24 W from VI. Agreement gives a useful check.

Is ten half-lives exactly 99.9% completion?

No. The fraction remaining is 1/1024, about 0.09766%, so about 99.90234% has decayed in the stated first-order model. Ten half-lives is a close approximation to 99.9%, not an exact equality.

What should I write before entering a numerical answer?

Write the physical or chemical model, compatible units and one independent check. Then apply the question and paper’s own rounding or answer-entry directions; do not replace them with a memorised habit.

What should I try in my next study session?

Solve a numerical question with a visible chain of reasoning and a plausibility check. Work through the example, use the linked chapter practice and write one correction for each mistake before moving on.

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