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NEET • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Mixed difficulty

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Showing 181-210 of 347 questions

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181 Medium
181 of 347
Understanding +4 | -1
A body in equilibrium may not have
View answer and explanation
Correct option: C
Acceleration
Option C (Acceleration) is correct because a body in equilibrium has zero net force acting on it, which implies zero acceleration.
182 Medium
182 of 347
Remembering +4 | -1
A body is tided with a string and is given a circular motion with velocity v in radius r. The magnitude of the acceleration
View answer and explanation
Correct option: B
υ2r\frac{{{\upsilon ^2}}}{r}
The correct answer is B. The magnitude of the centripetal acceleration for a body in circular motion is given by the formula v2r\frac{v^2}{r}.
183 Medium
183 of 347
Analyzing +4 | -1
Assertion: For looping a vertical loop of radius, rr the minimum velocity at point should be 5gr\sqrt{5 g r}.

Reason: In this even the velocity at the highest point will be zero.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
The correct answer is C. The assertion is true because the minimum velocity at the lowest point to complete a vertical loop is 5gr\sqrt{5gr}. The reason is false because the velocity at the highest point is not zero, it is gr\sqrt{gr}.
184 Easy
184 of 347
Remembering +4 | -1
When two bodies stick after collision, the collision is known as
View answer and explanation
Correct option: D
Total inelastic
Option D (Total inelastic) is correct because in a totally inelastic collision, the two bodies stick together after the collision.
185 Medium
185 of 347
Analyzing +4 | -1
A ball is dropped from height 10 m. Ball is embedded in sand 1 m and stops, then
View answer and explanation
Correct option: A
Only momentum remains conserved
Option A (Only momentum remains conserved) is correct because during the impact with the sand, the system is not isolated, and external forces act, but momentum is transferred to the Earth.
186 Hard
186 of 347
Application +4 | -1
A chain of length L\text{L} and mass M\text{M} is held on a frictionless table with 1/nth\text{1/nth} of its length hanging over the edge. When the chain is released find the speed of chain while leaving the table is:
View answer and explanation
Correct option: A
v=gL(1−1n2)\mathrm{v}=\sqrt{\mathrm{gL}\left(1-\frac{1}{\mathrm{n}^2}\right)}
Option A (v=gL(1−1n2)\mathrm{v}=\sqrt{\mathrm{gL}\left(1-\frac{1}{\mathrm{n}^2}\right)}) is correct because the potential energy lost as the chain slides off the table is converted into kinetic energy. By equating the potential energy lost to the kinetic energy gained, we can solve for the speed of the chain.
187 Medium
187 of 347
Understanding +4 | -1
A stone of mass m is tied to a string of length l and rotated in a circle with a constant speed v. If the string is released, the stone flies
View answer and explanation
Correct option: C
Tangentially outwards
Option C is correct because when the string is released, the stone will move along the tangent to the circle at the point of release due to inertia.
188 Hard
188 of 347
Application +4 | -1
Toy cart tied to the end of an unstretched string of length a, when revolved moves in a horizontal circle of radius 2a with a time period T. Now the toy cart is speeded up until it moves in a horizontal circle of radius 3a with a period T′T'. If Hook’s law holds then
View answer and explanation
Correct option: A
T′=32  TT' = \sqrt {\frac{3}{2}} \;T
Option A is correct because it correctly relates the time periods to the radii of the circles using Hooke's law.
189 Easy
189 of 347
Application +4 | -1
If the kinetic energy of a body is 5 times its momentum its velocity is
View answer and explanation
Correct option: C
10 m/s
Option C (10 m/s) is correct because it is derived by equating kinetic energy to 5 times the momentum and solving for velocity.
190 Medium
190 of 347
Analyzing +4 | -1
A body of mass m having an initial velocity v, makes head on collision with a stationary body of mass M. After the collision, the body of mass m comes to rest and only the body having mass M moves. This will happen only when
View answer and explanation
Correct option: C
m=Mm = M
Option C (m=Mm = M) is correct because, in a perfectly elastic head-on collision where one mass comes to rest, the masses must be equal.
191 Easy
191 of 347
Understanding +4 | -1
In which type of collision, the momentum of system is conserved?
View answer and explanation
Correct option: D
All of these
Option D is correct because the momentum of the system is always conserved in all types of collisions (perfectly elastic, perfectly inelastic, and inelastic) as long as there are no external forces acting on the system.
192 Medium
192 of 347
Analyzing +4 | -1
A man is standing at a spring platform. Reading of spring balance is 60 kg wt. If man jumps outside platform, then reading of spring balance
View answer and explanation
Correct option: A
first increases then decreases to zero
Option A (first increases then decreases to zero) is correct because when the man jumps, the spring balance initially registers an increased force due to the downward acceleration, then decreases to zero as the man is no longer in contact.
193 Hard
193 of 347
Application +4 | -1
A heavy particle is tied to the end AA of a string of length 1.6 m1.6 \mathrm{~m}. Its other end OO is fixed. It revolves as a conical pendulum with the string making 60∘60^{\circ} with the vertical. Then:
View answer and explanation
Correct option: B
The tension in the string is double the weight of the particle
Option B (The tension in the string is double the weight of the particle) is correct because the vertical component of tension balances the weight, and with a 60-degree angle, the tension is twice the weight.
194 Medium
194 of 347
Understanding +4 | -1
Statement I: Both stretched and compressed springs possess potential energy.

Statement II: Work done against restoring force is stored as potential energy.
View answer and explanation
Correct option: A
If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I
The correct answer is A because both statements are true, and Statement II correctly explains Statement I. Stretched and compressed springs store potential energy due to the work done against the restoring force.
195 Medium
195 of 347
Analyzing +4 | -1
Assertion(A): A spring of force constant kk is cut into two pieces having lengths in the ratio 1:21: 2. The force constant of series combination of the two parts is 3k/23 k / 2.

Reason(R): The spring connected in series are represented by k=k1+k2k=k_1+k_2.
View answer and explanation
Correct option: D
Both Assertion and Reason are incorrect.
Option C (Velocity) is correct because both bodies experience the same acceleration due to gravity, and since they are dropped from the same height, they will have the same velocity at any given point.
196 Medium
196 of 347
Application +4 | -1
When a belt moves horizontally at a constant speed of 1.5ms−11.5\mathrm{ }m{s^{ - 1}} , gravel is falling on it at 5kgs−15\mathrm{ }kg{s^{ - 1}}. Then the extra power needed to drive the belt is
View answer and explanation
Correct option: D
11.25 W
Option D (11.25 W) is correct because the extra power needed is the rate at which kinetic energy is imparted to the gravel.
197 Hard
197 of 347
Application +4 | -1
A spring of constant 5×103 N/m5 \times {10^3}\,N/m is stretched initially by 5 cm from the constracted position. The work required to stretch further by another 5 cm is
View answer and explanation
Correct option: A
18.75 J
Option A (18.75 J) is correct because the work required is the difference in potential energy between the two stretched positions.
198 Medium
198 of 347
Application +4 | -1
A ball is thrown with a velocity of 6m/s vertically downwards from a height H=3.2m above a horizontal floor. If it rebounds back to same height then coefficient of restitution e is [g=10m/s2]\left[ {g = 10\mathrm{ }m/{s^2}} \right]
View answer and explanation
Correct option: D
0.8
Option D (0.8) is correct because the coefficient of restitution is the ratio of the final and initial velocities, which can be calculated from the given heights.
199 Medium
199 of 347
Understanding +4 | -1
A man pushes a wall and falls to displace it. He does
View answer and explanation
Correct option: C
No work at all
Option C (No work at all) is correct because work is defined as force times displacement, and if the wall doesn't move, there is no displacement, hence no work is done.
200 Medium
200 of 347
Application +4 | -1
The position x of a particle of mass 2 kg moving along straight line is given as x=(t−2)2x = {\left( {t - 2} \right)^2}, where t is in second and x is in metre. The work done by the force in first 2s is
View answer and explanation
Correct option: B
-16 J
Option B (-16 J) is correct because the work done is equal to the change in kinetic energy, calculated from the initial and final velocities.
201 Medium
201 of 347
Analyzing +4 | -1
A particle is moving in a circular path of radius a under the action of an attractive potential U=−k2r2U = - \frac{k}{{2{r^2}}} Its total energy is
View answer and explanation
Correct option: C
Zero
The correct answer is C (Zero) because for a particle moving in a circular path under the given potential, the kinetic energy equals half the magnitude of the potential energy, resulting in a total energy of zero.
202 Easy
202 of 347
Understanding +4 | -1
When a body moves in a circular path, no work is done by the force since,
View answer and explanation
Correct option: C
Force and displacement are perpendicular to each other
Option C is correct because work done is zero when force and displacement are perpendicular, as in uniform circular motion where the centripetal force is always perpendicular to the velocity.
203 Medium
203 of 347
Application +4 | -1
A car is moving on a circular horizontal track of radius 20m with a constant speed of 20 m/s. A simple pendulum of length 50cm hangs from the roof of the car. The angle made by the string of pendulum with the vertical is
View answer and explanation
Correct option: D
tan⁡−1(2){\tan ^{ - 1}}\left( 2 \right)
The correct answer is D (tan⁡−1(2){\tan ^{ - 1}}( 2 )) because the angle is determined by the ratio of centripetal acceleration to gravitational acceleration.
204 Medium
204 of 347
Understanding +4 | -1
In stable equilibrium position, a body has
View answer and explanation
Correct option: B
Minimum potential energy
The correct answer is B. In a stable equilibrium position, a body has minimum potential energy because any displacement from this position increases the potential energy, causing the body to return to its original position.
205 Easy
205 of 347
Application +4 | -1
A person of mass 50 kg carrying a load of 20 kg walks up a stair case. If the width and height of each step are 0.25 m and 0.2 m respectively, the work done by the man in walking up 20 steps is
View answer and explanation
Correct option: D
2800 J
The correct answer is D. The work done is calculated by finding the total height climbed and then using the formula W=mghW = mgh, where m is the total mass and h is the total height.
206 Easy
206 of 347
Application +4 | -1
Two spheres whose radii are in the ratio 1:2 are moving with velocities in the ratio 3:4. If their densities are in the ratio 3:2, the ratio of their kinetic energies is,
View answer and explanation
Correct option: C
27 : 256
Option C (27 : 256) is correct because it is calculated by using the formula for kinetic energy and substituting the given ratios for radii, velocities, and densities.
207 Hard
207 of 347
Application +4 | -1
A ball is bouncing down a flight of stairs. The coefficient of restitution is ee. The height of each step is dd and the ball descends one step each bounce. After each bounce it rebounds to a height hh above the next lower step. The height is large enough compared with the width of step so that the impacts are effectively headon. Find the relationship between hh and dd.
View answer and explanation
Correct option: A
h=d1−e2h=\frac{d}{1-e^2}
Option A (h=d1−e2h=\frac{d}{1-e^2}) is correct because the height gained after each bounce is related to the height lost (d) by the coefficient of restitution.
208 Medium
208 of 347
Analyzing +4 | -1
The vessels AA and BB of equal volume and weight are immersed in water to depth hh. The vessel AA has an opening at the bottom through which water can enter. If the work done in immersing AA and BB are WAW_A and WBW_B respectively, then
View answer and explanation
Correct option: B
WA>WBW_A>W_B
Option B is correct because the work done in immersing A is greater than B, as water enters A, increasing the effective weight and thus the force required.
209 Medium
209 of 347
Understanding +4 | -1
A projectile is fired at 30∘30^{\circ} with momentum p. Neglecting friction, the change in kinetic energy when it returns to the ground will be
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because, neglecting friction, the projectile returns to its initial height, so its kinetic energy is the same as its initial kinetic energy.
210 Medium
210 of 347
Understanding +4 | -1
For a particle moving in vertical circle, the total energy at different positions along the path
View answer and explanation
Correct option: A
is conserved
Option A is correct because in a vertical circle, if only gravity is acting, the total mechanical energy (kinetic + potential) remains constant.
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