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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Medium

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Showing 181-210 of 210 questions
181 Medium
181 of 210
Application +4 | -1
If 1 g cm s−1=x{\mathrm{s}^{ - 1}} = x newton-second, then the number x is equal to
View answer and explanation
Correct option: C
1×10−51 \times {10^{ - 5}}
Option C (1×10−51 \times {10^{ - 5}}) is correct because it involves converting 1 g cm s−1{\mathrm{s}^{ - 1}} to newton-seconds using the conversion factors 1 g = 10-3 kg and 1 cm = 10-2 m.
182 Medium
182 of 210
Understanding +4 | -1
The dimensional formula for impulse is same as the dimensional formula for
View answer and explanation
Correct option: A
Momentum
Option A (Momentum) is correct because impulse is the change in momentum, hence having the same dimensions as momentum.
183 Medium
183 of 210
Analyzing +4 | -1
Which of the following is the most accurate instrument for measuring length?
View answer and explanation
Correct option: D
A screw gauge of least count 0.001 mm0.001 {~mm}
Option D (A screw gauge of least count 0.001 mm) is the most accurate because it has the smallest least count, allowing for the most precise measurement.
184 Medium
184 of 210
Application +4 | -1
In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree (=0.5∘),\left( { = 0.5^\circ } \right), then the least count of the instrument is
View answer and explanation
Correct option: A
One minute
Option A (One minute) is correct because the least count is calculated by dividing the smallest division of the main scale by the total number of divisions on the vernier scale.
185 Medium
185 of 210
Application +4 | -1
If v=At+Bt2+Ct3v = \frac{A}{t} + B{t^2} + C{t^3} , where vv is velocity, t is time and A,B and C are constants, then the dimensional formula of B is
View answer and explanation
Correct option: D
[M0LT−3]\left[ {{\mathrm{M}^0}\mathrm{L}{\mathrm{T}^{ - 3}}} \right]
Option D ([M0LT−3]\left[ {{\mathrm{M}^0}\mathrm{L}{\mathrm{T}^{ - 3}}} \right]) is correct because each term in the equation must have the same dimensions as velocity (LT⁻¹). Therefore, Bt2Bt^2 must have dimensions of LT⁻¹, implying B has dimensions of LT−3LT^{-3}.
186 Medium
186 of 210
Remembering +4 | -1
One shake is equal to
View answer and explanation
Correct option: B
10−810^{-8} seconds
Option B (10−810^{-8} seconds) is correct because one shake is defined as 10−810^{-8} seconds, a unit often used in nuclear physics.
187 Medium
187 of 210
Understanding +4 | -1
Dimensions of coefficient of viscosity are
View answer and explanation
Correct option: C
ML−1T−1M{L^{ - 1}}{T^{ - 1}}
Option C (ML−1T−1M{L^{ - 1}}{T^{ - 1}}) is correct because it is derived from the formula for viscous force.
188 Medium
188 of 210
Understanding +4 | -1
A spherometer has 100 equal divisions marked along the periphery of its disc and one full rotation of the disc advances on the main scale by 0.01 cm0.01 \mathrm{~cm}. The least count of this system is
View answer and explanation
Correct option: B
10−4 cm10^{-4} \mathrm{~cm}
Option B (10−4 cm10^{-4} \mathrm{~cm}) is correct because the least count is calculated by dividing the main scale division by the number of divisions on the circular scale.
189 Medium
189 of 210
Analyzing +4 | -1
From the dimensional consideration, which of the following equation is correct
View answer and explanation
Correct option: A
T=2πrR3GM  T = 2\pi r\sqrt {\begin{array}{cccccccccccccccccccc} {\frac{{{R^3}}}{{GM}}}\\ \; \end{array}}
Option A (T=2πrR3GMT = 2\pi r\sqrt {\begin{array}{cccccccccccccccccccc} {\frac{{{{{R^3}}}}}{{{{GM}}}}}\\ \\ \end{array}}) is correct because it is dimensionally incorrect. The correct equation should be T=2πR3GMT = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}}
190 Medium
190 of 210
Remembering +4 | -1
To measure the distance of a planet from the Earth, ______ method is used.
View answer and explanation
Correct option: C
Parallax
Option C (Parallax) is correct because the parallax method is specifically designed for measuring distances to stars and planets.
191 Medium
191 of 210
Analyzing +4 | -1
Given that :y=Asin⁡[(2πλ)  (ct−x)]:y = A\sin \left[ {\left( {\frac{{2\pi }}{\lambda }} \right)\;\left( {ct - x} \right)} \right] where, y and x are measured in metre. Which of the following statements is true?
View answer and explanation
Correct option: A
The unit of λ\lambda is same as that of x and A
Option A (The unit of λ\lambda is same as that of x and A) is correct because in the given equation, y, x, and λ\lambda all represent lengths and thus have the same unit.
192 Medium
192 of 210
Application +4 | -1
The concorde is the fastest airlines used for commercial service. It can cruise at 1450 mile per hour (about two times the speed of sound or in other words mach 2). What is it in m/s?
View answer and explanation
Correct option: A
644.4m/s
Option A (644.4m/s) is correct because 1 mile is approximately 1609.34 meters and 1 hour is 3600 seconds. Converting 1450 miles per hour to meters per second yields approximately 644.4 m/s.
193 Medium
193 of 210
Analyzing +4 | -1
S=A(1−e−Bxt)S = A(1 - {e^{ - Bxt}}) where S is speed and x is displacement. Then unit of B is
View answer and explanation
Correct option: A
m−1s−1{m^{ - 1}}{s^{ - 1}}
Option A (m−1s−1{m^{ - 1}}{s^{ - 1}}) is correct because the exponent must be dimensionless, making the units of B the inverse of x and t.
194 Medium
194 of 210
Analyzing +4 | -1
If C,R,L and I denote capacity, resistance, inductance and electric current respectively, the quantities having the same dimensions of time are (1) CR,  (2) LR ,  (3) LC  (4) LI2\left( 1 \right)\,CR,\,\,\left( 2 \right)\,\frac{L}{R}\,,\,\,\left( 3 \right)\,\sqrt {LC} \,\,\left( 4 \right)\,L{I^2}
View answer and explanation
Correct option: D
(1), (2) and (3) only
Option D ((1), (2) and (3) only) is correct because CR, L/R, and √(LC) all have the dimensions of time.
195 Medium
195 of 210
Application +4 | -1
In a new system of units, unit f mass is 10 kg, unit of length is 1 km and unit of time is 1 min. The value of 1 joule in this new hypothertical system is
View answer and explanation
Correct option: A
3.6×10−4 3.6\mathrm{ } \times {10^{ - 4}}\, new units
Option A (3.6×10−4 3.6\mathrm{ } \times {10^{ - 4}}\,) is correct because it represents the conversion of 1 Joule into the new system of units.
196 Medium
196 of 210
Remembering +4 | -1
The dimensional formula for impulse is
View answer and explanation
Correct option: B
MLT−1ML{T^{ - 1}}
Option B (MLT−1ML{T^{ - 1}}) is correct because impulse is the change in momentum, and momentum's dimensional formula is [MLT-1].
197 Medium
197 of 210
Remembering +4 | -1
Unit of magnetic moment is
View answer and explanation
Correct option: A
Ampere−metre  2Ampere - metre{\;^2}
Option A (Ampere−metre  2Ampere - metre{\;^2}) is correct because magnetic moment is defined as current times area, hence Ampere-meter².
198 Medium
198 of 210
Analyzing +4 | -1
The equation which is dimensionally correct among the following is
View answer and explanation
Correct option: C
s=ut+at2s = ut + a{t^2}
Option C (s=ut+at2s = ut + a{t^2}) is dimensionally correct because each term has the dimension of length [L].
199 Medium
199 of 210
Understanding +4 | -1
Dimension of R is
View answer and explanation
Correct option: B
ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}
Option B (ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}) is correct because it represents the dimensions of resistance derived from Ohm's law and the definition of power.
200 Medium
200 of 210
Analyzing +4 | -1
A quantity X is given by ε0LΔVΔt,  {\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;, where ε0{\varepsilon _0} is the permittivity of free space, L is a length, ΔV{\Delta V} is a potential difference and Δt{\Delta t} is a time interval. The dimensional formula for X is the same as that of
View answer and explanation
Correct option: D
Electric current
Option D (Electric current) is correct because the given expression is dimensionally equivalent to current, as it represents the displacement current in a capacitor.
201 Medium
201 of 210
Understanding +4 | -1
The unit of physical quantity obtained by the line intergral of electric field is
View answer and explanation
Correct option: C
JC−1\mathrm{J}{\mathrm{C}^{ - 1}}
Option C (JC−1\mathrm{J}{\mathrm{C}^{ - 1}}) is correct because the line integral of the electric field represents the electric potential difference, which is measured in Volts (J/C).
202 Medium
202 of 210
Understanding +4 | -1
The respective number of significant figures for the numbers 23.023, 0.0003 and 2.1×10−32.1 \times {10^{ - 3}} are
View answer and explanation
Correct option: A
5, 1, 2
Option A (5, 1, 2) is correct because 23.023 has 5 significant figures, 0.0003 has 1, and 2.1×10−32.1 \times 10^{-3} has 2.
203 Medium
203 of 210
Analyzing +4 | -1
The quantities x=1μ0ε0,  y=EBx = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }},\,\,y = \frac{E}{B} and z=lCRz = \frac{l}{{CR}} are defined, where CC is capacitance, RR is resistance, ll is length, EE is electric field, BB is magnetic field, ε0{\varepsilon _0} is free space permittivity and μ0{\mu _0} is permeability, respectively. Then,
View answer and explanation
Correct option: A
x, y and z have the same dimension
x, y and z have the same dimension because all three represent velocity.
204 Medium
204 of 210
Understanding +4 | -1
In   S=a+bt+ct2\mathrm{\;S} = a + bt + c{t^2}. S is measured in metre and t in second. The unit of c is
View answer and explanation
Correct option: D
ms−2m{s^{ - 2}}
Option D (ms−2m{s^{ - 2}}) is correct because in the equation S=a+bt+ct2S = a + bt + ct^2, each term must have the same dimensions as S (which is in meters). Therefore, ct2ct^2 must have dimensions of meters, implying c has units of m/s2m/s^2.
205 Medium
205 of 210
Application +4 | -1
In an experiment, the following observation’s were recorded: L=2.820  mL = 2.820\;m, M=3.00 kg,l=0.087 cm, diameter D=0.041 cm. Taking g=9.81 m/s2m/{s^2} using the formula,
Y=4MgLπD2lY = \frac{{4MgL}}{{\pi {D^2}l}}, the maximum permissible error in Y is
View answer and explanation
Correct option: C
0.065
Option C (0.065) is correct because the maximum permissible error in Y is calculated by summing the percentage errors of each component, weighted by their exponents in the formula.
206 Medium
206 of 210
Analyzing +4 | -1
The Vander Waal’s equation of state for real gases is given as (P+aV2)(V−b)=nRT\left( {P + \frac{a}{{{V^2}}}} \right)\left( {V - b} \right) = nRT which of the following terms has dimensions different from that of energy
View answer and explanation
Correct option: B
aV2\frac{a}{{{V^2}}}
Option B (aV2\frac{a}{{{V^2}}}) is correct because it has dimensions of pressure, not energy. The other options have dimensions of energy.
207 Medium
207 of 210
Analyzing +4 | -1
Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge in 5 mm and there are 50 total divisions on circular scale, then least count of screw gauge is 0.002 cm.
Reason R: Least count = Pitch  Total divisions on circular scale =\frac{\text { Pitch }}{\text { Total divisions on circular scale }}
View answer and explanation
Correct option: C
Both A and R are true and R is the correct explanation of A
Option C (Both A and R are true and R is the correct explanation of A) is correct because the assertion's least count calculation is accurate and the reason correctly states the formula for least count.
208 Medium
208 of 210
Analyzing +4 | -1
A student performs an experiment for determination of g=4π2lT2g = \frac{{4{\pi ^2}l}}{{{T^2}}} and he commits an error of ∆l. For that he takes the time of n oscillations with the stop watch of least count Δ\DeltaT and he commits a human error of 0.1 sec. For which of the following data, the measurement of g will be most accurate Δl  ΔT  n  Ampli.of oscill\Delta l\,\,\Delta T\,\,n\,\,Ampli.of\,oscill
View answer and explanation
Correct option: D
1 mm 0.1sec 50 1mm
Option D (1 mm 0.1sec 50 1mm) is correct because it minimizes the errors in length and time measurements by having a smaller least count and a larger number of oscillations.
209 Medium
209 of 210
Remembering +4 | -1
1 Parsec is equal to
View answer and explanation
Correct option: B
3.26 ly
Option B (3.26 ly) is correct because 1 parsec is approximately equal to 3.26 light-years.
210 Medium
210 of 210
Understanding +4 | -1
[ML2T−2]\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 2}}} \right] are dimensions of
View answer and explanation
Correct option: B
Moment of force
Option B (Moment of force) is correct because the moment of force (torque) is calculated as force times distance, which has the given dimensions.
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