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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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Showing 211-240 of 384 questions

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211 Easy
211 of 384
Application +4 | -1
Applying the principle of homogeneity of dimensions, determine which one is correct. where T\mathrm{T} is time period, G\mathrm{G} is gravitational constant, M\mathrm{M} is mass, r\mathrm{r} is radius of orbit.
View answer and explanation
Correct option: C
T2=4π2r3GM\mathrm{T}^2=\frac{4 \pi^2 \mathrm{r}^3}{\mathrm{GM}}
Option C (T2=4π2r3GM\mathrm{T}^2=\frac{4 \pi^2 \mathrm{r}^3}{\mathrm{GM}}) is correct because it is the only equation that is dimensionally consistent, matching the dimensions of time squared.
212 Medium
212 of 384
Remembering +4 | -1
What is the use of thin strip at the back of Vernier caliper?
View answer and explanation
Correct option: B
For measuring depth of cylinder
Option B (For measuring depth of cylinder) is correct because the thin strip is designed for measuring depths.
213 Hard
213 of 384
Application +4 | -1
Expression for time in terms of G (universal gravitational constant), h (Plank’s constant) and c (speed of light) is proportional to
View answer and explanation
Correct option: C
Ghc5\sqrt {\frac{{Gh}}{{{c^5}}}}
Option C (Ghc5\sqrt {\frac{{Gh}}{{{c^5}}}}) is correct because it correctly relates time to G, h, and c using dimensional analysis.
214 Medium
214 of 384
Remembering +4 | -1
Size of universe is about
View answer and explanation
Correct option: D
10 million light years
Option D (10 million light years) is correct because the size of the observable universe is estimated to be around 10 million light years.
215 Easy
215 of 384
Application +4 | -1
The density of a material in CGS system is 2 g/cm32 \mathrm{~g} / \mathrm{cm}^3. In a system of units in which unit of length is 2 cm2 \mathrm{~cm} and unit of mass is 4 g4 \mathrm{~g}, what is the numerical value of the density of the material?
View answer and explanation
Correct option: A
4
Option A (4) is correct because it involves converting the density from CGS to the new system of units by adjusting for the changes in length and mass.
216 Medium
216 of 384
Understanding +4 | -1
Which is dimensionless?
View answer and explanation
Correct option: D
Energy/work
Option D (Energy/work) is correct because both energy and work have the same dimensions [ML²T⁻²], making their ratio dimensionless.
217 Hard
217 of 384
Analyzing +4 | -1
The liquid drop of density ρ,\rho , radius rr and surface tension σ\sigma oscillates with time period T. Which of the following expression for T2{T^2} is correct
View answer and explanation
Correct option: A
ρr3σ\frac{{\rho {r^3}}}{\sigma }
Option A (ρr3σ\frac{{\rho {r^3}}}{\sigma }) is correct because it gives the correct relationship between time period, density, radius, and surface tension based on dimensional analysis.
218 Medium
218 of 384
Application +4 | -1
A student measures the distance traversed in free fall of a body, initially at rest in a given time. He uses this data to estimate g, the acceleration due to gravity. If the maximum percentage errors in measurement of the distance and the time are e1{e_1} and e2{e_2} respectively, the percentage error in the estimation of g is
View answer and explanation
Correct option: B
e1+2e2{e_1} + 2{e_2}
Option B (e1+2e2{e_1} + 2{e_2}) is correct because the percentage error in g is the sum of the percentage error in distance and twice the percentage error in time.
219 Medium
219 of 384
Application +4 | -1
The specific resistance ρ of a circular wire of radius r. Resistance R and and length l is given by ρ=πr2Rl.\rho = \frac{{\mathrm{\pi }{r^2}R}}{l}. Given, r=0:(24±0.02)cm, R=(30±1)Ωr = 0:\left( {24 \pm 0.02} \right)cm,\,R = \left( {30 \pm 1} \right)\mathrm{\Omega } and l=(4.80±0.01)cm.l = \left( {4.80 \pm 0.01} \right)cm. The percentage error in ρ is nearly
View answer and explanation
Correct option: D
0.202
Option D (0.202) is correct because it involves calculating the percentage error in specific resistance using the given formula and error values for r, R, and l.
220 Medium
220 of 384
Remembering +4 | -1
The dimensions of power are
View answer and explanation
Correct option: A
M1L2T−3{M^1}{L^2}{T^{ - 3}}
Option A (M1L2T−3{M^1}{L^2}{T^{ - 3}}) is correct because power is work done per unit time, and its dimensions are derived from the dimensions of work and time.
221 Easy
221 of 384
Application +4 | -1
If the unit of length is 4 m and that of velocity is 6 ms−1,6\,m{s^{ - 1}}, the unit of time is (in second)
View answer and explanation
Correct option: A
2/32/3
Option A (2/3) is correct because time = length / velocity, so the unit of time is 4 m / 6 m/s = 2/3 s.
222 Medium
222 of 384
Analyzing +4 | -1
With the usual notations, the following equation St=u+12a(2t−1)  {S_t} = u + \frac{1}{2}a\left( {2t - 1} \right)\; is
View answer and explanation
Correct option: C
Both numerically and dimensionally correct
Option C (Both numerically and dimensionally correct) is correct because the equation represents the distance traveled in the t-th second, which is both numerically and dimensionally consistent.
223 Medium
223 of 384
Application +4 | -1
If S=13ft3,fS = \frac{1}{3}f{t^3},f has the dimensions of
View answer and explanation
Correct option: A
[M0L−1T3]\left[ {{\mathrm{M}^0}{\mathrm{L}^{ - 1}}{\mathrm{T}^3}} \right]
Option C ([M0L1T−3{\mathrm{M}^0}{\mathrm{L}^1}{\mathrm{T}^{ - 3}}]) is correct because it involves finding the dimensions of f from the equation S=13ft3S = \frac{1}{3}f{t^3}, where S is displacement and t is time. By rearranging the equation to solve for f and substituting the dimensions of S and t, we can find the dimensions of f.
224 Easy
224 of 384
Understanding +4 | -1
Identify the pair whose dimensions are equal.
View answer and explanation
Correct option: A
Torque and work
Option A (Torque and work) is correct because both torque and work are defined as force times distance, resulting in the same dimensions.
225 Medium
225 of 384
Understanding +4 | -1
We can reduce random errors by
View answer and explanation
Correct option: A
Taking large number of observations
Option A (Taking large number of observations) is correct because averaging a large number of observations reduces the impact of random errors.
226 Hard
226 of 384
Application +4 | -1
The least count of the main scale of a vernier callipers is 1 mm. Its vernier scale is divided into 10th division and coincide with 9th division of the main scale. When jaws are touching each other, the 7th division of vernier scale coincides with a division of main scale and the zero of vernier scale is lying right side of the zero of main scale. When this vernier is used to measure length of a cylinder the zero of the vernier scale lies between 3.1 cm and 3.2 cm and 4th VSD coincides with a main scale division. The length of the cylinder is (VSD is vernier scale division)
View answer and explanation
Correct option: C
3.07 cm
Option C (3.07 cm) is correct because the length is calculated by adding the main scale reading and the vernier scale reading, then correcting for the zero error.
227 Easy
227 of 384
Remembering +4 | -1
The dimensions of power are
View answer and explanation
Correct option: A
M1L2T−3{M^1}{L^2}{T^{ - 3}}
Option A (M1L2T−3{M^1}{L^2}{T^{ - 3}}) is correct because power is work done per unit time, and its dimensional formula is derived from that.
228 Easy
228 of 384
Application +4 | -1
If x=a−bx = a - b, then the maximum percentage error in the measurement of x will be
View answer and explanation
Correct option: A
(Δa+Δba−b)×100%\left( {\frac{{\Delta a + \Delta b}}{{a - b}}} \right) \times 100\%
Option A is correct because the maximum percentage error in subtraction is the sum of the absolute errors divided by the difference, expressed as a percentage.
229 Easy
229 of 384
Application +4 | -1
What are the units of K=1/4πε0K = 1/4\pi {\varepsilon _0}
View answer and explanation
Correct option: B
Nm2C−2N{m^2}{C^{ - 2}}
Option B (Nm2C−2Nm^2C^{-2}) is correct because K is the electrostatic constant in Coulomb's law, and its unit is derived from the formula F = k(q1q2/r²).
230 Easy
230 of 384
Remembering +4 | -1
Ampere-hour is a unit of
View answer and explanation
Correct option: A
Quantity of electricity
Option A (Quantity of electricity) is correct because Ampere-hour is the unit of charge, which represents the quantity of electricity.
231 Medium
231 of 384
Application +4 | -1
If error in radius is 3%, what is error in volume of sphere?
View answer and explanation
Correct option: C
0.09
Option C (0.09) is correct because the error in volume is three times the error in radius for a sphere.
232 Medium
232 of 384
Remembering +4 | -1
The dimensional formula for impulse is
View answer and explanation
Correct option: A
[MLT−1]\left[ {\mathrm{ML}{\mathrm{T}^{ - 1}}} \right]
Option A ([MLT−1][\mathrm{ML}{\mathrm{T}^{ - 1}}]) is correct because impulse is the change in momentum, and momentum's dimensional formula is [MLT-1].
233 Medium
233 of 384
Remembering +4 | -1
Which of the following is the smallest unit
View answer and explanation
Correct option: C
Fermi
Option C (Fermi) is correct because 1 Fermi is the smallest unit among the given options.
234 Medium
234 of 384
Remembering +4 | -1
Instrumental error can be caused due to
View answer and explanation
Correct option: A
Faulty construction of instrument
Option A (Faulty construction of instrument) is correct because it is a systematic error inherent in the instrument itself.
235 Easy
235 of 384
Analyzing +4 | -1
A physical quantity T=abc2 d3e1/6\mathrm{T}=\frac{\sqrt{\mathrm{abc}^2}}{\mathrm{~d}^3 \mathrm{e}^{1 / 6}} is determined by measuring a, b, c, d, e separately with the percentage error of 1%,2%,3%,4%,3%1 \%, 2 \%, 3 \%, 4 \%, 3 \% respectively. Minimum amount of error is contributed by the measurement of :
View answer and explanation
Correct option: C
a, e
Option C (a, e) is correct because the percentage errors of a and e contribute the least to the overall error in the calculated quantity T.
236 Medium
236 of 384
Analyzing +4 | -1
The physical quantity having the dimensions [M−1L−3A2T3]\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right] is
View answer and explanation
Correct option: C
Electrical conductivity
Option C (Electrical conductivity) is correct because its dimensional formula matches the given dimensions.
237 Hard
237 of 384
Analyzing +4 | -1
Three identical spheres of mass 'm', are placed at the vertices of an equilateral triangle of length 'a'. When released, they interact only through gravitational force and collide after a time T = 4 seconds. If the sides of the triangle are increased to length '2a' and also the masses of the spheres are made '2m', then they will collide after _____ seconds.
View answer and explanation
Correct option: A
8
Option A (8) is correct because the time of collision is proportional to the side length of the triangle when the masses are scaled proportionally.
238 Hard
238 of 384
Application +4 | -1
The velocity v of water waves may depend on their wavelength (λ\lambda), the density of water (ρ\rho) and the acceleration due to gravity (g). The method of dimensions gives the relation between these quantities as
View answer and explanation
Correct option: B
v2∝gλ{v^2} \propto \mathrm{g}\lambda
Option B (v2∝gλ{v^2} \propto \mathrm{g}\lambda) is correct because it correctly relates the velocity of water waves to gravity and wavelength using dimensional analysis.
239 Medium
239 of 384
Application +4 | -1
A spectrometer gives the following reading when used to measure the angle of a prism Main scale reading : 58.5 degree Vernier scale reading : 09 divisions Given that 1 division on main scale corresponds to 0.5 degree. Total divisions on the vernier scale is 30 and match with 29 divisions of the main scale. The angle of the prism from the above data
View answer and explanation
Correct option: C
58.65 Degree
Option C (58.65 Degree) is correct because the angle of the prism is calculated by adding the main scale reading and the vernier scale reading.
240 Medium
240 of 384
Understanding +4 | -1
The number of significant figures in the numbers 4.8000×1044.8000 \times {10^4} and 48000.50 are respectively
View answer and explanation
Correct option: B
5 and 7
Option B (5 and 7) is correct because in 4.8000×1044.8000 \times {10^4} all digits are significant, and in 48000.50 all digits are significant.
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