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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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Showing 61-90 of 384 questions

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61 Medium
61 of 384
Analyzing +4 | -1
If speed (V)(V), acceleration (A)(A) and force (F)(F) are considered as fundamental units, the dimension of Young’s modulus will be
View answer and explanation
Correct option: D
[V−4A2F][{V^{ - 4}}{A^2}F]
Option D ([V−4A2F][{V^{ - 4}}{A^2}F]) is correct because it represents the dimensional formula of Young’s modulus in terms of velocity, acceleration, and force.
62 Easy
62 of 384
Understanding +4 | -1
The dimensions of time constant are
View answer and explanation
Correct option: B
[M0L0T]\left[ {{\mathrm{M}^0}{\mathrm{L}^0}\mathrm{T}} \right]
Option B ([M0L0T]) is correct because the time constant represents a characteristic time, hence its dimension is time.
63 Medium
63 of 384
Understanding +4 | -1
Two quantities A and B have different dimensions. Which mathematical operation given below is physically meaningful
View answer and explanation
Correct option: A
A/B
Option A (A/B) is correct because division is the only mathematically meaningful operation between quantities with different dimensions.
64 Medium
64 of 384
Remembering +4 | -1
The dimensions of Wien’s constant are
View answer and explanation
Correct option: B
[M0LT0K]\left[ {{M^0}L{T^0}K} \right]
Option B ([M⁰L¹T⁰K]) is correct because Wien's constant relates wavelength and temperature, resulting in dimensions of length times temperature.
65 Medium
65 of 384
Application +4 | -1
A dimensionally consistent relation for the volume V of a liquid of coefficient of viscosity η\eta flowing per second through a tube of radius r and length l and having pressure p across its end, is
View answer and explanation
Correct option: A
V=πpr48ηlV = \frac{{\pi p{r^4}}}{{8\eta l}}
Option A (V=πpr48ηlV = \frac{{\pi p{r^4}}}{{8\eta l}}) is correct because it is the only option that is dimensionally consistent with the volume flow rate.
66 Hard
66 of 384
Analyzing +4 | -1
Velocity of sound in a medium is given by A1/2 d−1/2{A^{1/2}}\,{d^{ - 1/2}} where dd is density of medium. Then AA represents
View answer and explanation
Correct option: A
Elastic constant
Option A (Elastic constant) is correct because dimensional analysis shows that A has the dimensions of an elastic constant (e.g., Young's modulus).
67 Easy
67 of 384
Understanding +4 | -1
No. of significant figures in 0.0241 is
View answer and explanation
Correct option: A
3
Option A (3) is correct because leading zeros are not significant, and the digits 2, 4, and 1 are significant.
68 Medium
68 of 384
Understanding +4 | -1
The dimensions of pressure are:
View answer and explanation
Correct option: C
[ML−1T−2]\left[ {M{L^{ - 1}}{T^{ - 2}}} \right]
Option C ([ML−1T−2]\left[ {M{L^{ - 1}}{T^{ - 2}}} \right]) is correct because pressure is defined as force per unit area, and its dimensions can be derived from the dimensions of force and area.
69 Medium
69 of 384
Analyzing +4 | -1
Which of the following pairs has same dimensions?
View answer and explanation
Correct option: C
Spring constant and surface energy
Option D (Spring constant and surface energy) is correct because both spring constant and surface energy have the same dimensional formula [MT⁻²].
70 Easy
70 of 384
Application +4 | -1
The pitch of the screw gauge is 0.5 mm. Its circular scale contains 50 divisions. The least count of the screw gauge is
View answer and explanation
Correct option: B
0.01 mm
Option B (0.01 mm) is correct because the least count of a screw gauge is calculated by dividing the pitch by the number of divisions on the circular scale.
71 Easy
71 of 384
Application +4 | -1
Taking into account the significant figures, what should be the value of 9.99 + 0.0099?
View answer and explanation
Correct option: D
10
Option B (10) is correct because when adding with significant figures, the result should be rounded to the least precise decimal place, which in this case is the ones place.
72 Easy
72 of 384
Application +4 | -1
Using mass (M)(M), length (L)(L), time (T)(T) and current (A)(A) as fundamental quantities, the dimensions of permeability are
View answer and explanation
Correct option: C
[MLT−2A−2]\left[\mathrm{MLT}^{-2} \mathrm{A}^{-2}\right]
Option C [MLT−2A−2]\left[\mathrm{MLT}^{-2} \mathrm{A}^{-2}\right] is correct because the permeability can be derived from the force between two parallel current-carrying wires.
73 Medium
73 of 384
Understanding +4 | -1
Planck’s constant has the dimensions (unit) of
View answer and explanation
Correct option: D
Angular momentum
Option D (Angular momentum) is correct because Planck's constant has the same dimensions as angular momentum, which is [ML²T⁻¹].
74 Medium
74 of 384
Understanding +4 | -1
Joule – Second is the unit of
View answer and explanation
Correct option: D
Angular Momentum
Option D (Angular Momentum) is correct because Joule-Second is the SI unit of angular momentum, derived from the product of moment of inertia and angular velocity.
75 Medium
75 of 384
Analyzing +4 | -1
Farad is not equivalent to
View answer and explanation
Correct option: B
qv2q{v^2}
Option B (qv2q{v^2}) is correct because it is not dimensionally equivalent to Farad, while the others are.
76 Easy
76 of 384
Application +4 | -1
Dimension of mass, in the dimensional formula of magnetic flux is
View answer and explanation
Correct option: A
1
Option A (1) is correct because the dimensional formula for magnetic flux is ML2T−2A−1ML^2T^{-2}A^{-1}, which has a mass dimension of 1.
77 Easy
77 of 384
Remembering +4 | -1
The dimensions of force are
View answer and explanation
Correct option: C
[MLT−2]\left[\mathrm{MLT}^{-2}\right]
Option C ([MLT-2]) is correct because force is mass times acceleration, and acceleration is length divided by time squared.
78 Medium
78 of 384
Application +4 | -1
The dimensions of a rectangular block measured with calipers having least count of 0.01 cm are 5 mm ×\times 10 mm ×\times 5 mm. The maximum percentage error in the measurement of the volume of the block is
View answer and explanation
Correct option: A
0.05
Option D (0.05) is correct because the maximum percentage error is calculated by dividing the least count by the smallest measurement.
79 Easy
79 of 384
Application +4 | -1
The dimensions of RL\frac{R}{L} are
[here, R=electric resistance, L=self inductance]
View answer and explanation
Correct option: B
[T−1]\left[ {{\mathrm{T}^{ - 1}}} \right]
Option B ([T−1]\left[ {{\mathrm{T}^{ - 1}}} \right]) is correct because R/L is the inverse of the time constant in an RL circuit, which has dimensions of inverse time.
80 Hard
80 of 384
Application +4 | -1
The expression for centripetal force depends upon mass of body, speed of the body and the radius of circular path. Find the expression for centripetal force
View answer and explanation
Correct option: B
F=mv2rF = \frac{{m{v^2}}}{r}
Option B (F=mv2rF = \frac{{m{v^2}}}{r}) is correct because it represents the standard formula for centripetal force.
81 Easy
81 of 384
Application +4 | -1
If L and R are respectively the inductance and resistance, then the dimensions of LR\frac{L}{R} will be
View answer and explanation
Correct option: C
M  0L0TM{\;^0}{L^0}T
Option C (M  0L0TM{\;^0}{L^0}T) is correct because the dimensions of L/R represent time, as seen in the context of LR circuits.
82 Medium
82 of 384
Analyzing +4 | -1
Given that 2lmT2l\sqrt {\frac{m}{T}}, where l is the length of a string of linear density m, under tension T has the same dimensional formula as that of
View answer and explanation
Correct option: B
Time
Option B (Time) is correct because dimensional analysis of the given expression results in the dimensions of time.
83 Medium
83 of 384
Analyzing +4 | -1
The quantity X=ε0LVt:ε0X = \frac{{{\varepsilon _0}LV}}{t}:{\varepsilon _0} is the permittivity of free space, L is length, V is potential difference and t is time. The dimensions of X are same as that of
View answer and explanation
Correct option: D
Current
Option D (Current) is correct because the dimensions of X are the same as that of current.
84 Medium
84 of 384
Understanding +4 | -1
A physicist performs an experiment and takes 200 readings. He repeats the same experiment and now takes 800 readings. By doing so the probable error
View answer and explanation
Correct option: D
Is reduced by a factor of 1/4
Option D is correct because the probable error is inversely proportional to the square root of the number of readings.
85 Hard
85 of 384
Application +4 | -1
A resistor of 4 kΩ with tolerance 10% is connected in parallel with a resistor of 6 kW with tolerance 100%. The tolerance of the parallel combination is nearly
View answer and explanation
Correct option: C
0.3
Option C (0.3) is correct because the tolerance of the parallel combination is calculated by considering the individual tolerances and resistances.
86 Medium
86 of 384
Understanding +4 | -1
In a slide calliper, nn divisions of vernier scale coincides with (n−1)(n-1) divisions of main scale. The least count of the instrument is
View answer and explanation
Correct option: A
1nMSD\frac{1}{n} \mathrm{MSD}
Option A is correct because the least count is calculated as the difference between one main scale division and one vernier scale division.
87 Medium
87 of 384
Understanding +4 | -1
In a metre bridge experiment, we try to obtain the null point at the middle. This:
View answer and explanation
Correct option: A
Reduces systematic error as well as random error
Option B (Reduces systematic error but not the random error) is correct because obtaining the null point at the middle of a meter bridge primarily reduces systematic errors due to end corrections.
88 Medium
88 of 384
Understanding +4 | -1
In which of the following instruments used in the lab there exists an error of random category known as back lash error?
(i) Screw gauge
(ii) Spherometer
(iii) Searle's apparatus
(iv) Vernier callipers
View answer and explanation
Correct option: B
(i), (ii) and (iii) only
Option B is correct because backlash error, a type of random error, occurs in instruments with screws and gears like screw gauges, spherometers, and Searle's apparatus.
89 Medium
89 of 384
Remembering +4 | -1
Oersted is a unit of
View answer and explanation
Correct option: B
Magnetic intensity
Option B (Magnetic intensity) is correct because Oersted is the CGS unit of magnetic field strength, also known as magnetic intensity.
90 Medium
90 of 384
Application +4 | -1
If E,m,J and G represent energy, mass, angular momentum and gravitational constant respectively, then the dimensional formula of EJ2/m5G2E{J^2}/{m^5}{G^2} is
View answer and explanation
Correct option: D
Dimensionless
Option D (Dimensionless) is correct because when the dimensions of each quantity are substituted and simplified, the resulting expression is dimensionless.
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