JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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The dimensional formula for Reynold's number is

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Correct option: A

\left[\mathrm{L}^0 \mathrm{M}^0 \mathrm{~T}^0\right]

Option A (

\left[\mathrm{L}^0 \mathrm{M}^0 \mathrm{~T}^0\right]

) is correct because the Reynolds number is a dimensionless quantity, meaning it has no physical units and its dimensional formula is

\left[\mathrm{L}^0 \mathrm{M}^0 \mathrm{~T}^0\right]

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