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NEET • PHYSICS • THERMAL PROPERTIES OF MATTER

Thermal properties of matter practice · Mixed difficulty

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Showing 241-269 of 269 questions
241 Easy
241 of 269
Application +4 | -1
At 0∘C0^{\circ} \mathrm{C}, the densities of a cork and a liquid in which the cork floats are d1\mathrm{d}_1 and d2\mathrm{d}_2 respectively. The coefficients of expansion for the material of the cork and the liquid are γ\gamma and 100γ100 \gamma respectively. If the cork sinks when temperature of liquid is t∘C\mathrm{t}^{\circ} \mathrm{C}, then ratio (d2/d1)\left(\mathrm{d_2 / d}_1\right) is
View answer and explanation
Correct option: A
1+100γt1+γt\frac{1+100 \gamma \mathrm{t}}{1+\gamma \mathrm{t}}
Option A is correct because it represents the ratio of densities considering the thermal expansion of both the cork and the liquid.
242 Hard
242 of 269
Application +4 | -1
How many grams of ice at −14∘C-14^{\circ} \mathrm{C} are needed to cool 200 g200 \mathrm{~g} of water from 25∘C25^{\circ} \mathrm{C} to 10∘C10^{\circ} \mathrm{C} ? Take specific heat of ice =0.5cal/g/∘C=0.5 \mathrm{cal} / \mathrm{g} /{ }^{\circ} \mathrm{C} and latent heat of ice =80cal/g=80 \mathrm{cal} / \mathrm{g}.
View answer and explanation
Correct option: A
31
Option A (31) is correct because it calculates the mass of ice needed by equating the heat lost by the water to the heat gained by the ice to warm up and melt.
243 Medium
243 of 269
Remembering +4 | -1
During process of melting, thermal energy that is absorbed during process of melting is called:
View answer and explanation
Correct option: A
Latent heat of fusion
Option A (Latent heat of fusion) is correct because the thermal energy absorbed during melting is specifically called the latent heat of fusion.
244 Medium
244 of 269
Remembering +4 | -1
S.I. unit of universal gas constant is
View answer and explanation
Correct option: C
J  mol−1K−1J\;mo{l^{ - 1}}{K^{ - 1}}
Option C (J  mol−1K−1J\;mo{l^{ - 1}}{K^{ - 1}}) is correct because it represents the correct SI units for the universal gas constant.
245 Medium
245 of 269
Understanding +4 | -1
A composite rod made of copper (α=1.8×10−5K−1\alpha = 1.8 \times {10^{ - 5}}{\mathrm{K}^{ - 1}}) and steel (α=1.2×10−5K−1\mathrm{\alpha } = 1.2 \times {10^{ - 5}}{\mathrm{K}^{ - 1}}) is heated. Then
View answer and explanation
Correct option: A
It bends with steel on concave side
Option A (It bends with steel on concave side) is correct because steel has a lower coefficient of thermal expansion than copper, causing it to be on the concave side when heated.
246 Medium
246 of 269
Analyzing +4 | -1
(A): It is hotter over the top of a fire than at the same distance on the sides.
(R): Air surrounding the fire conducts more heat upwards.
View answer and explanation
Correct option: C
If A is true but R is false
Option C (If A is true but R is false) is correct because it is hotter over the top of a fire due to convection, not conduction.
247 Medium
247 of 269
Understanding +4 | -1
When two ends of a rod wrapped with cotton are maintained at different temperatures and after same time every point of the rod attains a constant temperature, then
View answer and explanation
Correct option: D
Each point of the rod is giving heat to its neighbour at the same rate at which it is receiving heat
Option D (Each point of the rod is giving heat to its neighbour at the same rate at which it is receiving heat) is correct because at a constant temperature distribution, the heat flow into each point must equal the heat flow out, maintaining a steady state.
248 Easy
248 of 269
Remembering +4 | -1
The lower and upper fixed points in Reaumur scale is
View answer and explanation
Correct option: A
0∘R,   80∘R0^\circ R,\,\,\,80^\circ R
Option A (0∘R,   80∘R0^\circ R,\,\,\,80^\circ R) is correct because the Reaumur scale defines the freezing point of water as 0 °R and the boiling point of water as 80 °R.
249 Medium
249 of 269
Understanding +4 | -1
When a rod is heated but prevented from expanding, the stress developed is independent of
View answer and explanation
Correct option: C
Length of rod
Option C (Length of rod) is correct because the stress developed in a rod prevented from expanding depends on the material, rise in temperature, and Young's modulus, but not the length of the rod.
250 Medium
250 of 269
Analyzing +4 | -1
Statement-I: The linear coefficients of expansion of a crystal along three perpendicular axes are α,−α2,α5.\alpha, \frac{-\alpha}{2}, \frac{\alpha}{5}. Its volume coefficient is 7α10\frac{7 \alpha}{10}
Statement-II: For anisotropic solids γ=αx+αy+αz\gamma=\alpha_x+\alpha_y+\alpha_z.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Statement-I is true and statement-II is true is the correct answer because the volume coefficient of expansion is the sum of the linear coefficients of expansion along three perpendicular axes for anisotropic solids, and the calculation in Statement-I is correct.
251 Medium
251 of 269
Application +4 | -1
A steel wire of uniform area 2  mm22\,\,m{m^2} is heated up to 500C{50^0}C and is stretched by tying its ends rigidly. The change in tension when the temperature falls from 500C{50^0}C to 300C{30^0}C is (Take Y=2×1011Nm−2,α=1.1×10−50C−1)Y = 2 \times {10^{11}}N{m^{ - 2}},\alpha = 1.1 \times {10^{ - 5}}^0{C^{ - 1}})
View answer and explanation
Correct option: C
88N88N
Option C (88N) is correct because it calculates the change in tension due to thermal stress using Young's modulus and the coefficient of linear expansion.
252 Medium
252 of 269
Analyzing +4 | -1
A 30.0 cm30.0 \mathrm{~cm} long metal rod expands by 0.0650 cm0.0650 \mathrm{~cm} when its temperature is raised from 0∘C0^{\circ} \mathrm{C} to 100∘C100^{\circ} \mathrm{C}. A second rod of different metal and of the same length expands by 0.0350 cm0.0350 \mathrm{~cm} for the same rise in temperature. A third composite rod, also 30.0 cm30.0 \mathrm{~cm} long, is made-up of pieces of each of the above metals placed end to end and expands by 0.0580 cm0.0580 \mathrm{~cm} when temperature is increased from 0∘C0^{\circ} \mathrm{C} to 100∘C100^{\circ} \mathrm{C}. Find the length of the smaller portion of the composite bar (in cm\mathrm{cm}) at 0∘C0^{\circ} \mathrm{C}.
View answer and explanation
Correct option: A
7
Option A (7 cm) is correct. It is found by setting up equations for the total expansion of the composite rod based on the individual expansions and solving for the length of the smaller portion.
253 Easy
253 of 269
Application +4 | -1
The maximum wavelength in the energy distribution spectrum of sun is 4753  A∘4753\,\,\mathop {\text{A}}\limits^ \circ and its temperature is 6050 K6050 \mathrm{~K}. The temperature of star whose energy distribution shows a maximum at 9506  A∘9506\,\,\mathop {\text{A}}\limits^ \circ is
View answer and explanation
Correct option: A
3025 K3025 \mathrm{~K}
Option A (3025 K3025 \mathrm{~K}) is correct because it is the temperature of the star calculated using Wien's displacement law.
254 Hard
254 of 269
Application +4 | -1
A metal sphere of radius rr and specific heat cc is rotated about an axis passing through its centre at a speed of nn rotations per second. It is suddenly stopped and 50% of its energy is used in increasing its temperature. Then the rise in temperature of the sphere is
View answer and explanation
Correct option: A
25π2n2r2c\frac{2}{5}\frac{{{\pi ^2}{n^2}{r^2}}}{c}
Option A (25π2n2r2c\frac{2}{5}\frac{{{\pi ^2}{n^2}{r^2}}}{c}) is correct because the rotational kinetic energy is converted into heat, and the temperature rise is calculated using the specific heat.
255 Medium
255 of 269
Application +4 | -1
A metallic solid sphere is routing about its diameter as axis of rotation. If the temperature is increased by 200℃, the percentage in its moment of inertia is (Coefficient of linear expansion of the metal=10−50C−1= {10^{ - 5}}^0{C^{ - 1}})
View answer and explanation
Correct option: D
0.4%0.4\%
Option D (0.4%) is correct because it calculates the percentage change in moment of inertia based on the coefficient of linear expansion and temperature change.
256 Medium
256 of 269
Understanding +4 | -1
Ice, water and steam co-exist at triple point temperature 273.16K and pressure 4.6mm Hg. In a system in which the triple point conditions of temperature and pressure exist, the pressure is increased a little while keeping the temperature constant, then the system contains
View answer and explanation
Correct option: B
water only
Option B (water only) is correct because increasing the pressure at the triple point while keeping the temperature constant will cause the ice and steam to convert into water.
257 Medium
257 of 269
Understanding +4 | -1
Two metal strips that constitute a thermostat must necessarily differ in their
View answer and explanation
Correct option: D
Coefficient of linear expansion
Option D (Coefficient of linear expansion) is correct because a thermostat relies on the different expansion rates of two metals to bend and break a circuit.
258 Medium
258 of 269
Remembering +4 | -1
A perfect black body is one whose emissive power is
View answer and explanation
Correct option: C
Unity
Option A (Maximum) is incorrect. Option C (Unity) is correct because a perfect black body absorbs all incident radiation, meaning its absorptivity is 1. Since emissivity equals absorptivity for a body in thermal equilibrium, its emissive power is also maximum, but it's more accurate to say its emissivity is unity.
259 Hard
259 of 269
Application +4 | -1
If the volume of a block of metal changes by 0.12%0.12 \%, when it is heated through 20∘C20^{\circ} {C}, then the coefficient of areal expansion is :
View answer and explanation
Correct option: A
4×10−5∘C−14 \times 10^{-5}{ }^{\circ} {C}^{-1}
Option A (4×10−5∘C−14 \times 10^{-5}{ }^{\circ} {C}^{-1}) is correct because the coefficient of areal expansion is two-thirds of the coefficient of volume expansion.
260 Medium
260 of 269
Analyzing +4 | -1
Statement-I: Two rods of the same material have the same lengths but diameter are in the ratio of 1:2.1:2. If 1000cal1000 \mathrm{cal} of heat is supplied to the two rods separately the ratio of their linear expansion is 4:1.4:1.
Statement-II: The linear expansion e=lαΔte=l \alpha \Delta t
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option C (If (A) is true but (R) is false) is correct because brass has a higher coefficient of linear expansion than iron, causing it to be on the convex side when heated.
261 Easy
261 of 269
Understanding +4 | -1
The standard fixed point for temperature measurements in use today is
View answer and explanation
Correct option: C
At which ice, liquid water and water vapour coexist
Option C (At which ice, liquid water and water vapour coexist) is correct because the triple point of water is a precisely defined temperature and pressure where all three phases coexist in equilibrium.
262 Medium
262 of 269
Application +4 | -1
A centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers 1400{140^0}. What is the fall in temperature as registered by the Centigrade thermometer
View answer and explanation
Correct option: B
400{40^0}
Option B (400{40^0}) is correct because it represents the fall in temperature on the Celsius scale corresponding to the given fall on the Fahrenheit scale.
263 Medium
263 of 269
Analyzing +4 | -1
Identify the pair of physical quantities which have different dimensions.
View answer and explanation
Correct option: D
Specific heat capacity and Latent heat
Option D (Specific heat capacity and Latent heat) is correct because they have different dimensional formulas.
264 Medium
264 of 269
Analyzing +4 | -1
A metal ball immersed in alcohol weighs W1{W_1} at 0∘C{0^ \circ }C and W2{W_2} at 59∘C{59^ \circ }C. The coefficient of cubical of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that
View answer and explanation
Correct option: B
W1<W2{W_1} < {W_2}
Option B (W1<W2{W_1} < {W_2}) is correct because as temperature increases, the density of alcohol decreases more than the density of the metal, resulting in a smaller buoyant force and a larger apparent weight.
265 Medium
265 of 269
Remembering +4 | -1
In the relation n=PVRT,n=n = \frac{{PV}}{{RT}},n =
View answer and explanation
Correct option: D
Number of Moles
Option D (Number of Moles) is correct because the variable 'n' in the ideal gas law equation PV=nRTPV = nRT represents the number of moles.
266 Medium
266 of 269
Understanding +4 | -1
Colour of shinning bright star is an indication of its
View answer and explanation
Correct option: C
Temperature
Option C (Temperature) is correct because the color of a star is directly related to its surface temperature, following Wien's displacement law.
267 Medium
267 of 269
Analyzing +4 | -1
A metal ball immersed in water weights w1  at  0∘Cand  w2  {w_1}\;\mathrm{at}\;{0^ \circ }\mathrm{C and}\;{w_2}\; at 50∘C^ \circ C. The coefficient of cubical expansion of metal is less than that water. Then
View answer and explanation
Correct option: A
w1<w2{w_1} < {w_2}
Option B (w1>w2{w_1} > {w_2}) is correct because as the temperature increases, the density of water decreases more than the density of the metal, leading to a smaller buoyant force and thus a smaller apparent weight at 50°C.
268 Hard
268 of 269
Application +4 | -1
Two black bodies at 327∘C  and  627∘C327^\circ C\,\,\mathrm{and}\,\,627^\circ C are suspended in an environment at 27∘C.27^\circ C. The ratio of their emissive powers is
View answer and explanation
Correct option: C
0.136111111
Option D (0.136111111) is correct because it calculates the ratio of emissive powers using Stefan's law, considering the ambient temperature.
269 Medium
269 of 269
Understanding +4 | -1
A gas in an airtight container is heated from 250C{25^0}C to 900C{90^0}C The density of the gas will
View answer and explanation
Correct option: C
Remain the same
Option C (Remain the same) is correct because the density of a gas in a closed container remains constant when heated, as mass and volume are constant.
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