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NEET • PHYSICS • THERMAL PROPERTIES OF MATTER

Thermal properties of matter practice · Mixed difficulty

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Showing 181-210 of 269 questions

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181 Easy
181 of 269
Remembering +4 | -1
'Stem corrections' in Platinum resistance thermometers are eliminated by the use of
View answer and explanation
Correct option: A
Compensating leads
Option A is correct. Compensating leads are used in platinum resistance thermometers to eliminate stem corrections, which account for the temperature variation along the length of the leads.
182 Medium
182 of 269
Remembering +4 | -1
The saturation vapour pressure of water at 1000C{100^0}C is
View answer and explanation
Correct option: C
760mm760mm of mercury
Option C (760mm760mm of mercury) is correct because the saturation vapor pressure of water at 100°C is equal to standard atmospheric pressure, which is 760 mm of mercury.
183 Easy
183 of 269
Understanding +4 | -1
Two bars of copper having same length but unequal diameter are heated to the same temperature. The change in length will be
View answer and explanation
Correct option: C
Same for both the bars
Option C (Same for both the bars) is correct because the change in length depends on the original length, the coefficient of linear expansion, and the change in temperature, none of which depend on the diameter.
184 Medium
184 of 269
Application +4 | -1
The temperature of equal masses of three different liquids xx, yy and zz are 10∘C,  20∘C10^\circ C,\,\,20^\circ C and 30∘C30^\circ C, respectively. The temperature of mixture when xx is mixed with yy is 16∘C16^\circ C and that when yy is mixed with zz is 26∘C26^\circ C. The temperature of mixture when xx and zz are mixed will be
View answer and explanation
Correct option: C
23.84∘C23.84^\circ C
Option C (23.84∘C23.84^\circ C) is correct because it is derived from setting up and solving equations based on the heat exchange between the liquids when mixed.
185 Medium
185 of 269
Remembering +4 | -1
Triple Point of Water is
View answer and explanation
Correct option: B
273.16 K
Option B (273.16 K) is correct because the triple point of water is defined as 273.16 K.
186 Easy
186 of 269
Application +4 | -1
In a resistance thermometer the resistances at 0∘C0^{\circ} \mathrm{C} and 100∘C100^{\circ} \mathrm{C} are 6.746.74 and 7.74 ohm7.74 \mathrm{~ohm} respectively. The temperature corresponding to 6.53 ohm6.53 \mathrm{~ohm} resistance is
View answer and explanation
Correct option: D
−21∘C-21^{\circ} \mathrm{C}
Option D (−21∘C-21^{\circ} \mathrm{C}) is correct because the temperature is calculated using the linear relationship between resistance and temperature in a resistance thermometer.
187 Medium
187 of 269
Application +4 | -1
The Fahrenheit and Kelvin scales of temperature will give the same reading at
View answer and explanation
Correct option: C
574.25574.25
Option C (574.25574.25) is correct because it is the temperature at which Fahrenheit and Kelvin scales give the same reading.
188 Easy
188 of 269
Understanding +4 | -1
An anisotropic substance has coefficients of linear thermal expansions α1,  α2,  α3{\alpha_1},\,\,{\alpha_2},\,\,{\alpha_3} along x, y, z axes respectively. Coefficient of cubical expansion of its material is
View answer and explanation
Correct option: A
α1+α2+α3{\alpha_1} + {\alpha_2} + {\alpha_3}
Option A is correct. The coefficient of cubical expansion for an anisotropic substance is the sum of the coefficients of linear expansion along the three axes: α1+α2+α3{\alpha_1} + {\alpha_2} + {\alpha_3}.
189 Easy
189 of 269
Understanding +4 | -1
The surface of a lake is at 1∘C{1^ \circ }C. Find the temperature of the bottom of the lake
View answer and explanation
Correct option: D
4∘C{4^ \circ }C
Option D (4∘C{4^\circ }C) is correct because water has maximum density at 4∘C{4^\circ }C, so the bottom of the lake will be at this temperature.
190 Medium
190 of 269
Understanding +4 | -1
The correct statement of the law of equipartition of energy is
View answer and explanation
Correct option: B
The gas possess equal energies in all the three directions x, y and z−x,\,y\,{\text{and }}z - axis
Option B is correct because the law of equipartition of energy states that the gas possesses equal energies in all three directions (x, y, and z axes).
191 Medium
191 of 269
Remembering +4 | -1
In anomalous expansion of water, at what temperature, the density of water is maximum?
View answer and explanation
Correct option: A
4∘C4^{\circ} \mathrm{C}
Option A (4∘C4^{\circ} \mathrm{C}) is correct because water has maximum density at this temperature due to anomalous expansion.
192 Medium
192 of 269
Application +4 | -1
When the temperature of a rod increases from tt to t+Δtt + \Delta t its moment of inertia increases from II to I+ΔII + \Delta I. If α\alpha be the coefficient of linear expansion of the rod, then the value of ΔII\frac{{\Delta I}}{I} is
View answer and explanation
Correct option: A
2αΔt2\alpha \Delta t
Option A (2αΔt2\alpha \Delta t) is correct because it is the relationship between the change in moment of inertia and the coefficient of linear expansion.
193 Easy
193 of 269
Understanding +4 | -1
Colour of shining bright star is an indication of its
View answer and explanation
Correct option: C
Temperature
Option C (Temperature) is correct because the color of a star is directly related to its surface temperature, following Wien's displacement law.
194 Easy
194 of 269
Application +4 | -1
Three metal rods of same lengths, and some area of cross section having conductivities 1,2,3 units are connected in series, then their effective conductivity will be
View answer and explanation
Correct option: B
1.6 units
Option B (1.6 units) is correct because the effective conductivity of rods in series is calculated using the formula 1/K_eff = (1/K1 + 1/K2 + 1/K3)/3, which simplifies to K_eff = 3 / (1/1 + 1/2 + 1/3) = 1.6.
195 Hard
195 of 269
Application +4 | -1
The temperature of an oven, if it radiates 8.28 cal per second through an opening, whose area is 6.1  cm26.1\,\,c{m^2} is (Assume that the radiation is close to that of a black body)
View answer and explanation
Correct option: C
1000 K
Option C (1000 K) is correct because it is derived from Stefan-Boltzmann law, relating radiated power to temperature.
196 Medium
196 of 269
Application +4 | -1
The real coefficient of volume expansion of glycerine is 0.0005970.000597 per 0C^0C and linear coefficient of expansion of glass is 0.0000090.000009 per 0C^0C . Then the apparent volume coefficient of expansion of glycerine is
View answer and explanation
Correct option: B
0.000570.00057 per 0C^0C
Option A (0.0005580.000558 per 0C^0C) is correct because the apparent volume expansion is the difference between the real volume expansion of the liquid and the volume expansion of the container.
197 Easy
197 of 269
Application +4 | -1
The higher and the lower fixed points on a thermometer are separated by 160 mm when the length of the mercury thread above the lower temperature is 40 mm the temperature reading would be
View answer and explanation
Correct option: D
25∘C25^\circ C
Option D (25∘C25^\circ C) is correct because the temperature is calculated using the ratio of the length of the mercury thread above the lower fixed point to the total length between the fixed points.
198 Hard
198 of 269
Application +4 | -1
A clock with a metal pendulum beating seconds keeps correct time at 0∘C0^\circ C. If it losses 12.5s a day at 25∘C25^\circ C the coefficient of linear expansion of metal pendulum is
View answer and explanation
Correct option: A
186400/∘C\frac{1}{{86400}}/^\circ C
Option A (186400/∘C\frac{{1}}{{{{86400}}}}/^\circ C) is correct because it represents the coefficient of linear expansion calculated from the time lost by the pendulum clock.
199 Hard
199 of 269
Application +4 | -1
There are two spherical balls AA and BB of the same material with same surface, but the diameter of AA is half that of BB. If AA and BB are heated to the same temperature and then allowed to cool, then
View answer and explanation
Correct option: C
Rate of cooling of A is twice that of B
Option C is correct because the rate of cooling is inversely proportional to the diameter, making A cool twice as fast as B.
200 Medium
200 of 269
Remembering +4 | -1
The temperature at which the vapour pressure of a liquid becomes equals to the external (atmospheric) pressure is its
View answer and explanation
Correct option: D
Boiling Point
Option B (Thermal Capacity) is correct because thermal capacity is the amount of heat required to raise the temperature of a substance by 1 Kelvin or 1 degree Celsius.
201 Medium
201 of 269
Understanding +4 | -1
Mercury boils at 3670C{367^0}C. However, mercury thermometers are made such that they can measure temperature up to 5000C{500^0}C. This is done by
View answer and explanation
Correct option: B
Filling nitrogen gas at high pressure above the mercury column
Option B (Filling nitrogen gas at high pressure above the mercury column) is correct because the high pressure of the nitrogen gas increases the boiling point of mercury, allowing the thermometer to measure higher temperatures.
202 Medium
202 of 269
Remembering +4 | -1
Substance having very small coefficient of linear expansion, among the following is
View answer and explanation
Correct option: D
Invar
Option D is correct. Invar is an alloy of iron and nickel that has a very low coefficient of linear expansion compared to copper, iron, and lead.
203 Medium
203 of 269
Remembering +4 | -1
Mercury thermometers can be used to measure temperatures upto
View answer and explanation
Correct option: C
3600C{360^0}C
Option C is correct. Mercury thermometers can typically be used to measure temperatures up to 360°C before the mercury starts to boil.
204 Medium
204 of 269
Application +4 | -1
A metal rod of Young’s modulus γ\gamma and coefficient of thermal expansion α\alpha is held at its two ends such that its length remains invariant. If its temperature is raised by t0C{t^0}C, the linear stress developed in it is
View answer and explanation
Correct option: C
γαt{\gamma \alpha t}
Option C (γαt{\gamma \alpha t}) is correct because it is the formula for linear stress developed in the rod when its temperature is raised.
205 Easy
205 of 269
Application +4 | -1
Heat required to melt 10 g of Ice at 0∘C.0^{\circ} \mathrm{C}. [Lf(ice)=80 cal/g]\left[\mathrm{L}_{\mathrm{f}}(\text{ice}\right)=80 \mathrm{~cal} / \mathrm{g}]
View answer and explanation
Correct option: C
Both 1 and 2
Option C (Both 1 and 2) is correct because 0.8 k Cal is equivalent to 800 Cal, and both represent the heat required to melt 10 g of ice at 0°C.
206 Medium
206 of 269
Understanding +4 | -1
When a bimetallic strip made of iron (α1)\left( {{\alpha _1}} \right) and copper (α2)\left( {{\alpha _2}} \right) is heated (α2>α1)\left( {{\alpha _2} > {\alpha _1}} \right)
View answer and explanation
Correct option: C
It bends with iron on concave side
Option C (It bends with iron on concave side) is correct because copper expands more than iron when heated, causing the bimetallic strip to bend with the iron on the inner (concave) side.
207 Medium
207 of 269
Application +4 | -1
Two spherical black bodies made of same material and with the same surface finish have masses M1andM2{M_1}and\mathrm{ }{M_2} and are at temperatures T1andT2{T_1} and \mathrm{ }{T_2} . If they are radiating the same power, M1/M2{M_1}/{M_2} must be
View answer and explanation
Correct option: C
(T2/T1)6{\left( {{T_2}/{T_1}} \right)^6}
Option C ((T2/T1)6{\left( {{T_2}/{T_1}} \right)^6}) is correct because it represents the ratio of masses derived from the Stefan-Boltzmann law and the relationship between mass and volume for similar materials.
208 Medium
208 of 269
Remembering +4 | -1
A device used to measure temperature is
View answer and explanation
Correct option: B
Thermometer
Option B (Thermometer) is correct because a thermometer is the standard instrument used to measure temperature.
209 Medium
209 of 269
Application +4 | -1
In an isochoric process if T1=27oC   and   T2=127oC{T_1} = {27^\mathrm{o}}C\mathrm{ }\,\,\,\mathrm{and}\,\,\,\mathrm{ }{T_2} = {127^\mathrm{o}}C, then P1/P2{P_1}/{P_2} will be equal to
View answer and explanation
Correct option: C
45750
Option D (None of these) is correct. In an isochoric process, the ratio P1/P2 = T1/T2 where T1 and T2 are in Kelvin. The correct calculation yields a different result.
210 Medium
210 of 269
Application +4 | -1
The initial temperature of a body is 800C{80^0}C . If its temperature falls to 640C{64^0}C in 5 minutes and in 10 minutes to 520C{52^0}C then the temperature of surrounding will be
View answer and explanation
Correct option: B
490C{49^0}C
Option B (490C{49^0}C) is correct because it satisfies Newton's Law of Cooling for the given temperature changes over time.
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