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NEET • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Medium

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61 Medium
61 of 157
Analyzing +4 | -1
Statement-I: A coin is placed on phonogram turn table. The motor is started, coin moves along the moving table.
Statement-II: The rotating table is providing necessary centripetal force to the coin.
View answer and explanation
Correct option: D
Both statements are false
Option D (Both statements are false) is correct because the coin moves due to friction (not centripetal force), and the table doesn't necessarily provide the required centripetal force.
62 Medium
62 of 157
Remembering +4 | -1
The moment of inertia (I)(I) and the angular momentum (L)(L) are related by the expression
View answer and explanation
Correct option: B
L=IωL=I \omega
Option B (L=IωL=I \omega) is correct because it represents the relationship between angular momentum, moment of inertia, and angular velocity.
63 Medium
63 of 157
Analyzing +4 | -1
Assertion: When a body dropped from a height explodes in mid air, its centre of mass keeps moving in vertically downward direction.
Reason: Explosion occur under internal forces only. External force is zero.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because the assertion and reason are both true, and the reason correctly explains why the center of mass continues its downward motion despite the explosion.
64 Medium
64 of 157
Remembering +4 | -1
If the body is moving in a circle of radius r with a constant speed v, its angular velocity is
View answer and explanation
Correct option: C
v/r
Option C (v/r) is correct because the angular velocity is defined as the linear velocity divided by the radius of the circular path, ω=v/r\omega = v/r.
65 Medium
65 of 157
Application +4 | -1
A 2 kg body and a 3 kg body are moving along the x-axis. At a particular instant the 2 kg body has a velocity of 3  ms−13\;m{s^{ - 1}} and the 3 kg body has the velocity of 2ms−12m{s^{ - 1}}. The velocity of the centre of mass at that instant is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the velocity of the center of mass is calculated as vcm=(m1v1+m2v2)/(m1+m2)=(2∗3+3∗2)/(2+3)=12/5=2.4m/sv_{cm} = (m_1v_1 + m_2v_2) / (m_1 + m_2) = (2*3 + 3*2) / (2+3) = 12/5 = 2.4 m/s, which is not any of the given options.
66 Medium
66 of 157
Understanding +4 | -1
A couple produces
View answer and explanation
Correct option: C
Purely rotational motion
Option C (Purely rotational motion) is correct because a couple consists of two equal and opposite forces that create a torque, resulting in rotation without translation.
67 Medium
67 of 157
Application +4 | -1
2 bodies of different masses of 2 kg and 4 kg are moving with velocities 20 m/s and 10 m/s towards each other due to mutual gravitational attraction. What is the velocity of their centre of mass
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because, in the absence of external forces, the velocity of the center of mass remains constant. Since the bodies were initially moving towards each other due to mutual gravitational attraction, the initial momentum of the system is zero, and thus the velocity of the center of mass is zero.
68 Medium
68 of 157
Understanding +4 | -1
If a force acts on a body at a point away from the centre of mass, then
View answer and explanation
Correct option: C
Both change
Option C (Both change) is correct because a force applied away from the center of mass causes both linear and angular acceleration.
69 Medium
69 of 157
Understanding +4 | -1
A drum of radius R and mass M, rolls down without slipping along an inclined plane of angle θ\theta. The frictional force
View answer and explanation
Correct option: A
Converts translational energy to rotational energy
Option A (Converts translational energy to rotational energy) is correct because friction provides the torque necessary for the drum to rotate as it rolls down the incline.
70 Medium
70 of 157
Analyzing +4 | -1
Assertion: When you lean behind over the hind legs of the chair, the chair falls back after a certain angle.

Reason: Centre of mass lying outside the system makes the system unstable.
View answer and explanation
Correct option: C
If Assertion is correct but Reason is incorrect.
Option C is correct. The assertion is correct; the chair tips when the center of mass goes beyond the support. However, the reason is incorrect because the center of mass doesn't necessarily have to lie outside the system to make it unstable; it's about its position relative to the support base.
71 Medium
71 of 157
Analyzing +4 | -1
Assertion: A judo fighter in order to throw his opponent on to the mat tries to initially bend his opponent and then rotate him around his hip.
Reason: As the mass of the opponent is brought closer to the fighter's hip, the force required to throw the opponent is reduced.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because the judo fighter uses rotational motion and leverage to reduce the force needed by bringing the opponent's mass closer to the hip.
72 Medium
72 of 157
Remembering +4 | -1
Angular momentum is conserved
View answer and explanation
Correct option: D
When external torque is absent
Option D (When external torque is absent) is correct because angular momentum is conserved when the net external torque acting on the system is zero.
73 Medium
73 of 157
Analyzing +4 | -1
Three identical sphere lie at rest along a line on a smooth horizontal surface. The separation between any two adjacent spheres is L. The first sphere is moved with a velocity u towards the second sphere at time t=0. The coefficient of restitution for collision between any two blocks is 1/3. Then choose the correct statement
View answer and explanation
Correct option: A
The third sphere will start moving at t=5L2ut = \frac{{5L}}{{2u}}
Option A (The third sphere will start moving at t=5L2ut = \frac{{5L}}{{2u}}) is correct because it accounts for the time taken for the collisions and the subsequent motion of the spheres with reduced velocities due to the coefficient of restitution.
74 Medium
74 of 157
Remembering +4 | -1
The centre of mass of a system of particles depends on
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the center of mass depends on the position, relative distance, and masses of the particles.
75 Medium
75 of 157
Analyzing +4 | -1
A rigid disc rolls without slipping on a fixed rough horizontal surface with uniform angular velocity. If the acceleration of lowest point on the disc aa and the velocity of the lowest point on the disc is vv, then
View answer and explanation
Correct option: C
a≠0,v=0a \neq 0, v=0
Option A (a=0,v=0a=0, v=0) is incorrect. Option B (a=0,v≠0a=0, v \neq 0) is incorrect. Option D (a≠0,v≠0a \neq 0, v \neq 0) is incorrect. Option C (a≠0,v=0a \neq 0, v=0) is correct because the velocity of the lowest point is zero (condition for rolling without slipping), but it does have centripetal acceleration.
76 Medium
76 of 157
Application +4 | -1
A wheel of moment of inertia 10 kg m2{m^2} is rotating at 10 rotations per minute. The work done in increasing its speed to 5 times its initial value, will be (P2  ≈  10)\left( {{P^2}\,\, \approx \,\,10} \right)
View answer and explanation
Correct option: B
133.3 Joule
Option B (133.3 Joule) is correct because it is the work done calculated from the change in rotational kinetic energy when the angular speed increases fivefold.
77 Medium
77 of 157
Understanding +4 | -1
When an external force is applied at the centre of mass of a rigid body at rest, then it undergoes
View answer and explanation
Correct option: A
Only translator motion
Option A is correct. When an external force is applied at the center of mass of a rigid body at rest, it undergoes only translational motion. There will be no rotational motion because the force is applied directly at the center of mass.
78 Medium
78 of 157
Application +4 | -1
A solid cylinder (SC) a hollow cylinder (HC) and a solid sphere (S) of the same mass and radius are released simultaneously from the same height of incline. The order in which these bodies reach the bottom of the incline is
View answer and explanation
Correct option: C
S, SC, HC
Option C (S, SC, HC) is correct because the solid sphere has the smallest moment of inertia, followed by the solid cylinder, and then the hollow cylinder, resulting in different accelerations down the incline.
79 Medium
79 of 157
Application +4 | -1
A man of 50 kg mass in standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5 kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floor will be
View answer and explanation
Correct option: C
10.1 m
Option C (10.1 m) is correct because the man moves upward due to conservation of momentum when he throws the stone downwards.
80 Medium
80 of 157
Understanding +4 | -1
In which case application of angular velocity is useful
View answer and explanation
Correct option: A
When a body is rotating
Option A (When a body is rotating) is correct because angular velocity describes the rate of rotation of a body around an axis.
81 Medium
81 of 157
Application +4 | -1
A cannon shell lands 2 km away from the cannon. A second shell, fired identically, breaks into two equal parts at the highest point. One part falls vertically. How far from the cannon will the other land ?
View answer and explanation
Correct option: B
3 km
Option B (3 km) is correct because after the explosion, one part falls vertically, and the other part travels an additional distance equal to the initial range due to conservation of momentum.
82 Medium
82 of 157
Application +4 | -1
A body of mass 1 kg thrown with a velocity of 10  ms−110\;\mathrm{m}{\mathrm{s}^{ - 1}} at an angle of 600{60^0} with the horizontal. Its momentum at the highest point is
View answer and explanation
Correct option: D
5  kg  ms−15\mathrm{\;kg\;m}{\mathrm{s}^{ - 1}}
Option D (5  kg  ms−15\mathrm{\;kg\;m}{\mathrm{s}^{ - 1}}) is correct because the momentum at the highest point is only due to the horizontal component of the initial velocity.
83 Medium
83 of 157
Application +4 | -1
Two bodies of mass 10 kg and 2 kg are moving with velocities (2i^−7j^+3k^) m/s\left( {2\hat i - 7\hat j + 3\hat k} \right)\,m/s and (−10i^+35j^−3k^) m/s\left( { - 10\hat i + 35\hat j - 3\hat k} \right)\,m/s respectively. The velocity of their centre of mass is
View answer and explanation
Correct option: B
2k^ m/s2\hat k{\mkern 1mu} m/s
Option B (2k^ m/s2\hat k{\mkern 1mu} m/s) is correct because the velocity of the center of mass is calculated using the formula vcm=(m1v1+m2v2)/(m1+m2)v_{cm} = (m_1v_1 + m_2v_2) / (m_1 + m_2).
84 Medium
84 of 157
Analyzing +4 | -1
A particle of mass m moving with a velocity (3i^+2j^)ms−1\left( {3\hat i + 2\hat j} \right)m{s^{ - 1}} collides with a stationary body mass M and finally moves with a velocity (−2i^+j^)ms−1. If mM=113,\left( { - 2\hat i + \hat j} \right)\mathrm{m}{\mathrm{s}^{ - 1}}.\,If\,\frac{m}{M} = \frac{1}{{13}}, then
View answer and explanation
Correct option: D
All the above are correct
Option D (All the above are correct) is correct because the impulse, velocity of M, and coefficient of restitution are all consistent with the conservation of momentum and the given conditions.
85 Medium
85 of 157
Analyzing +4 | -1
A tank filled with water is connected to another empty tank lying to the right side of the first tank. Until the level of water in the tanks become same
a) Centre of mass of water shifts down at constant rate
b) Centre of mass of water shifts down and rate of change of shift in centre of mass decreases gradually and becomes zero
c) Centre of mass shifts towards right as well
View answer and explanation
Correct option: B
Only b and c are correct
Option B (Only b and c are correct) is correct because as water flows to the right tank, the rate of change of the shift in the center of mass decreases and the center of mass shifts towards the right.
86 Medium
86 of 157
Remembering +4 | -1
The moment of inertia of a straight thin rod of mass M and length L about an axis perpendicular to its length and passing through one end is
View answer and explanation
Correct option: B
ML23\frac{{M{L^2}}}{{3}}
Option B (ML²/3) is correct because the moment of inertia of a rod about one end is ML²/3.
87 Medium
87 of 157
Understanding +4 | -1
Two particles move towards each other from rest under a mutual force of attraction. At the instant, when the speed of A is V, the speed of B is V/2. The speed of centre of mass of the system is
View answer and explanation
Correct option: D
zero
Option D is correct. Since the particles move under mutual attraction and start from rest, there are no external forces. Therefore, the velocity of the center of mass of the system is zero.
88 Medium
88 of 157
Analyzing +4 | -1
A solid sphere rolls down two different inclined planes of same length, but of different inclinations. In both cases
View answer and explanation
Correct option: B
Speed will be same, but time of descent will be different
Option B (Speed will be same, but time of descent will be different) is correct because the final speed depends only on the height, while the time of descent depends on the inclination of the plane.
89 Medium
89 of 157
Application +4 | -1
Two points of a rod move with velocities 3v and v perpendicular to the rod and in the same direction separated by a distance 'r'. The angular velocity of the rod is
View answer and explanation
Correct option: D
2Vr\frac{{2V}}{r}
Option D (2V/r) is correct because the angular velocity is the difference in velocities divided by the distance between the points.
90 Medium
90 of 157
Application +4 | -1
A flywheel of mass 50 kg and radius of gyration about its axis of rotation of 0.5m is acted upon by a constant torque of 12.5 Nm. Its angular velocity at t=5s is
View answer and explanation
Correct option: B
5 rad/s
Option B (5 rad/s) is correct because the angular velocity is calculated using the formula ω=αt\omega = \alpha t, where α\alpha is the angular acceleration and t is the time.
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