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NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Hard

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Showing 31-36 of 36 questions
31 Hard
31 of 36
Application +4 | -1
A man can swim with a speed of 4  kmh−14\,\,km{h^{ - 1}} in still water. He crosses a river 1 km wider that flows steadily at 3  kmh−13\,\,km{h^{ - 1}} If he makes his strokes normal to the river current how far down the river does he go when he reaches the other bank?
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Correct option: C
750 m
Option C is correct because the distance drifted downstream is calculated by multiplying the river's velocity by the time taken to cross the river.
32 Hard
32 of 36
Understanding +4 | -1
A vector a\mathbf{a} is turned without a change in its length through a small angles dθd \theta. The value of ∣Δa∣|\Delta \mathbf{a}| and Δa\Delta a are, respectively.
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Correct option: B
a⋅dθ,0a \cdot d \theta, 0
Option B (a⋅dθ,0a \cdot d \theta, 0) is correct because the magnitude of the change in the vector is adθa d\theta and the change in the magnitude of the vector is 0 since the length remains constant.
33 Hard
33 of 36
Application +4 | -1
If the equation of motion of a projectile is y=3x−18x2y = 3x - \frac{1}{8}{x^2} the range and maximum height are respectively (yy and xx are in metres)
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Correct option: B
24m  and  18m24m\,\,\mathrm{and}\,\,18m
Option B (24m  and  18m24m\,\,\mathrm{and}\,\,18m) is correct because it is obtained by comparing the given equation with the standard trajectory equation of a projectile.
34 Hard
34 of 36
Application +4 | -1
A boat travels 4 hr upstream and 2 hr down the stream for covering the same distance. The ratio of velocity of boat to the water in river
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Correct option: B
3:13:1
Option B is correct because the ratio of boat velocity to water velocity is 3:1, derived from equating upstream and downstream distances.
35 Hard
35 of 36
Application +4 | -1
If A⃗=3i^+4j^, B⃗=7i^+24j^\vec A = 3\hat i + 4\hat j,\,\vec B = 7\hat i + 24\hat j then the vector having the same magnitude as B⃗\vec B and parallel to A⃗\vec A is
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Correct option: B
15i^+20j^15\hat i + 20\hat j
Option B (15i^+20j^15\hat i + 20\hat j) is correct because it has the same magnitude as B⃗\vec B and is parallel to A⃗\vec A.
36 Hard
36 of 36
Application +4 | -1
If a=i^+j^+k^,b=i^+j^,c=i^\mathbf{a}=\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+\hat{\mathbf{j}}, \mathbf{c}=\hat{\mathbf{i}} and (a×b)×c=λa+μb(\mathbf{a} \times \mathbf{b}) \times \mathbf{c}=\lambda \mathbf{a}+\mu \mathrm{b}, then λ+μ\lambda+\mu is equal to
View answer and explanation
Correct option: A
0
Option A (0) is correct because after calculating the triple product and comparing it to the given equation, we find that λ + μ = 0.
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