NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Hard

1 of 1

Application +4 | -1

A body is projected with velocity ‘

u

’ so that the maximum height is thrice the horizontal range. Then the maximum height is

View answer and explanation

Correct option: A

\frac{{72{u^2}}}{{145g}}

Option A (

\frac{{72{u^2}}}{{145g}}

) is correct because it is derived by using the relationship between maximum height and horizontal range in projectile motion.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)