NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Hard

1 of 1

Application +4 | -1

A stone projected with a velocity

u

at angle

\theta

with the horizontal reaches a maximum height. When it is projected with velocity

u

at an angle

\left( {\pi /2 - \theta } \right)

with the horizontal range of the projectile

{H_1}

and

{H_2}

View answer and explanation

Correct option: A

R = 4\sqrt {{H_1}{H_2}}

Option A (

R = 4\sqrt {{H_1}{H_2}}

) is correct because it relates the range to the maximum heights achieved at complementary angles.

More Questions from MOTION IN PLANE

Practice All Chapter MCQs →

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)