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NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Easy

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61 Easy
61 of 91
Application +4 | -1
The angle made by the vector A=i^+j^A = \hat i + \hat j with x – axis is
View answer and explanation
Correct option: B
45∘45^\circ
Option B (45∘45^\circ) is correct because the vector has equal components along the x and y axes, indicating a 45-degree angle.
62 Easy
62 of 91
Understanding +4 | -1
Unit vector

I. has dimensions and a unit.

II. when multiplied by a scalar quantity, it results a scalar.

Which of the following statement(s) is/are incorrect?
View answer and explanation
Correct option: C
Both I and II
Option C is correct because a unit vector is dimensionless and unitless, and multiplying it by a scalar results in a vector.
63 Easy
63 of 91
Remembering +4 | -1
Identify the vector quantity among the following
View answer and explanation
Correct option: C
Angular momentum
Option C (Angular momentum) is correct because angular momentum is defined as a vector quantity, while distance, heat, and energy are scalar quantities.
64 Easy
64 of 91
Application +4 | -1
A particle is projected at an angle of 600{60^0} above the horizontal with a speed of 10  ms−110\mathrm{\;m}{\mathrm{s}^{ - 1}}. After some time the direction of its velocity makes an angle of 300{30^0} above the horizontal. The speed of the particle at this instant is
View answer and explanation
Correct option: D
103ms−1\frac{{10}}{{\sqrt 3 }}\mathrm{m}{\mathrm{s}^{ - 1}}
Option D (103  ms−1\frac{{10}}{{\sqrt 3 }}\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because the horizontal component of velocity remains constant, allowing us to solve for the final speed.
65 Easy
65 of 91
Analyzing +4 | -1
If A\mathbf{A} and B\mathbf{B} are two non-zero vectors having equal magnitude, the angle between the vectors A\mathbf{A} and A−B\mathbf{A}-\mathbf{B} is
View answer and explanation
Correct option: D
dependent on the orientation of A\mathrm{A} and B\mathrm{B}
Option D (dependent on the orientation of A and B) is correct because the angle between A\mathbf{A} and A−B\mathbf{A}-\mathbf{B} depends on the angle between A\mathbf{A} and B\mathbf{B}.
66 Easy
66 of 91
Application +4 | -1
If 13∣a⃗×b⃗∣=a→⋅b→\frac{1}{{\sqrt 3 }}\left| {\vec a \times \vec b} \right| = \overrightarrow a \cdot \overrightarrow b then angle between a→\overrightarrow a and b→\overrightarrow b is
View answer and explanation
Correct option: B
60∘60^\circ
Option B (60∘60^\circ) is correct because when 13∣a⃗×b⃗∣=a→⋅b→\frac{1}{{\sqrt 3 }}|{\vec a \times \vec b}| = \overrightarrow a \cdot \overrightarrow b, it implies that tan⁡θ=13\tan \theta = \frac{1}{{\sqrt 3 }}, which means θ=60∘\theta = 60^\circ.
67 Easy
67 of 91
Application +4 | -1
Two projectiles thrown at 30∘30^{\circ} and 45∘45^{\circ} with the horizontal respectively, reach the maximum height in same time. The ratio of their initial velocities is:
View answer and explanation
Correct option: C
2:1\sqrt{2}: 1
Option C (2:1\sqrt{2}: 1) is correct. The ratio of initial velocities is derived from the time to reach maximum height, which depends on the vertical component of velocity.
68 Easy
68 of 91
Application +4 | -1
The angle between the two vectors A⃗ = 5i^ + 5j^\vec A\, = \,5\hat i\, + \,5\hat j and B⃗ = 5i^ − 5j^\vec B\, = \,5\hat i\, - \,5\hat j will be
View answer and explanation
Correct option: C
90∘90^\circ
Option C is correct because the dot product of the two vectors is zero, indicating they are orthogonal (perpendicular).
69 Easy
69 of 91
Application +4 | -1
Given two vector Aˉ=2i+6j+4k\bar A = 2i + 6j + 4k and Bˉ=i−2j+8k\bar B = i - 2j + 8k. The magnitude of their resultant is
View answer and explanation
Correct option: D
13
Option D (13) is correct because it is the magnitude of the resultant vector obtained by adding the two given vectors.
70 Easy
70 of 91
Application +4 | -1
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is
View answer and explanation
Correct option: C
45∘45^\circ
Option C (45∘45^\circ) is correct because when the horizontal range is four times the maximum height, the angle of projection is 45 degrees.
71 Easy
71 of 91
Application +4 | -1
If 13∣a⃗×b⃗∣=a→⋅b→\frac{1}{{\sqrt 3 }}\left| {\vec a \times \vec b} \right| = \overrightarrow a \cdot \overrightarrow b then angle between a→\overrightarrow a and b→\overrightarrow b is
View answer and explanation
Correct option: B
60∘ 60^\circ \,
Option B (60∘ 60^\circ \,) is correct because when 13∣a⃗×b⃗∣=a→⋅b→\frac{1}{{\sqrt 3 }}|{\vec a \times \vec b}| = \overrightarrow a \cdot \overrightarrow b, solving for the angle yields 60 degrees.
72 Easy
72 of 91
Application +4 | -1
If vectors Aˉ=2i+3j+Pk\bar A = 2i + 3j + Pk and Bˉ=3iˉ−8jˉ+2kˉ\bar B = 3\bar i - 8\bar j + 2\bar k are perpendicular to each other. Then value of PP is
View answer and explanation
Correct option: D
9
If vectors Aˉ=2i+3j+Pk\bar A = 2i + 3j + Pk and Bˉ=3iˉ−8jˉ+2kˉ\bar B = 3\bar i - 8\bar j + 2\bar k are perpendicular to each other, then the value of PP is 9 because their dot product must be zero.
73 Easy
73 of 91
Application +4 | -1
If the magnitude of resultant of two vectors is equal to magnitude of either vectors, then angle between them is
View answer and explanation
Correct option: D
120∘120^\circ
Option D (120∘120^\circ) is correct because when the magnitude of the resultant of two vectors is equal to the magnitude of either vector, the angle between them is 120∘120^\circ.
74 Easy
74 of 91
Understanding +4 | -1
The component of a vector along any other direction is
View answer and explanation
Correct option: A
always less than its magnitude
Option A (always less than its magnitude) is correct because the component of a vector is the projection onto another direction, which can never exceed the vector's magnitude unless the angle is 0.
75 Easy
75 of 91
Understanding +4 | -1
The value of (Aˉ+Bˉ)×(Aˉ−Bˉ)\left( {\bar A + \bar B} \right) \times \left( {\bar A - \bar B} \right) is
View answer and explanation
Correct option: D
−2(Aˉ×Bˉ)- 2\left( {\bar A \times \bar B} \right)
The value of (Aˉ+Bˉ)×(Aˉ−Bˉ)(\bar A + \bar B) \times (\bar A - \bar B) is −2(Aˉ×Bˉ)-2(\bar A \times \bar B) after expanding the cross product and using the properties of the cross product.
76 Easy
76 of 91
Application +4 | -1
Angle (in rad) made by the vector 3i+j\sqrt 3 i + j with the x-axis is
View answer and explanation
Correct option: A
π6\frac{\pi }{6}
To get a unit vector along the x-axis, the y and z components of the resultant vector must be zero. Therefore, the vector B⃗\vec{B} must cancel out the y and z components of A⃗\vec{A}, making option A correct.
77 Easy
77 of 91
Application +4 | -1
Vector Aˉ=4i+2j−3k,  Bˉ=5iˉ+jˉ−2kˉ\bar A = 4i + 2j - 3k,\,\,\bar B = 5\bar i + \bar j - 2\bar k and Cˉ=3i−j+2k\bar C = 3i - j + 2k. Then Aˉ.(Bˉ×Cˉ)\bar A.\left( {\bar B \times \bar C} \right) is
View answer and explanation
Correct option: B
-8
Option B (-8) is correct because it is the scalar triple product of the three vectors.
78 Easy
78 of 91
Analyzing +4 | -1
Assertion If a particle is projected vertically upwards with velocity uu, the maximum height attained by the particle is h1h_1. The same particle is projected at angle 30∘30^{\circ} from horizontal with the same speed uu. Now the maximum height is h2h_2. Thus, h1=4h2h_1=4 h_2.

Reason In first case, v=0v=0 at highest point and in second case, v≠0v \neq 0 at highest point.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct. The assertion is correct because h1=u2/2gh_1 = u^2/2g and h2=(usin⁡30)2/2g=u2/8gh_2 = (u \sin 30)^2/2g = u^2/8g, thus h1=4h2h_1 = 4h_2. The reason is also correct, but it doesn't explain the relationship between h1h_1 and h2h_2.
79 Easy
79 of 91
Application +4 | -1
Component of the vector A=2i^+3j^\mathbf{A}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}} along the vector B=(i^+j^)\mathbf{B}=(\hat{\mathbf{i}}+\hat{\mathbf{j}}) is
View answer and explanation
Correct option: A
52\frac{5}{\sqrt{2}}
Option A (52\frac{5}{\sqrt{2}}) is correct because it represents the magnitude of the projection of vector A onto vector B.
80 Easy
80 of 91
Analyzing +4 | -1
Assertion: The angle between the two vectors (i^+j^)(\hat{i}+\hat{j}) and (i^+k^)(\hat{i}+\hat{k}) is π3\frac{\pi}{3} radian.
Reason: Angle between two vectors A⃗\vec{A} and B⃗\vec{B} is given by θ=cos⁡−1(A⃗⋅B⃗AB)\theta=\cos ^{-1}\left(\frac{\vec{A} \cdot \vec{B}}{A B}\right).
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the angle between the vectors can be calculated using the formula provided in the Reason, and the calculated angle matches the assertion.
81 Easy
81 of 91
Application +4 | -1
Two bodies are projected with the same velocity. If one is projected at an angle of 30∘30^\circ and the other at angle of 60∘60^\circ to the horizontal, the ratio of the maximum heights reached is
View answer and explanation
Correct option: B
0.04375
Option A (0.125) is incorrect. The correct answer is 0.3333. The ratio of maximum heights is calculated using the formula for maximum height and the given angles.
82 Easy
82 of 91
Understanding +4 | -1
The resultant of A  ×  0A\,\, \times \,\,0 will be equal to
View answer and explanation
Correct option: C
Zero vector
Option C is correct because the cross product of any vector with the zero vector results in the zero vector.
83 Easy
83 of 91
Understanding +4 | -1
I. Displacing a vector parallel to itself leaves the vector unchanged.

II. Three equal vectors cannot add upto zero.

Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: A
Only I
Option A is correct. Displacing a vector parallel to itself doesn't change it, but three equal vectors can add up to zero if they are oriented at 120 degrees to each other.
84 Easy
84 of 91
Application +4 | -1
If two vectors A‾=2i→−2j→+k→\overline A = 2\overrightarrow i - 2\overrightarrow j + \overrightarrow k, and B‾=2i→+6j→−mk→\overline B = 2\overrightarrow i + 6\overrightarrow j - m\overrightarrow k are perpendicular to each other than the value of mm is
View answer and explanation
Correct option: C
-8
If two vectors A‾=2i→−2j→+k→\overline A = 2\overrightarrow i - 2\overrightarrow j + \overrightarrow k and B‾=2i→+6j→−mk→\overline B = 2\overrightarrow i + 6\overrightarrow j - m\overrightarrow k are perpendicular to each other, then the value of mm is -8 because their dot product must be zero.
85 Easy
85 of 91
Application +4 | -1
The position vector rˉ\bar r of a particle is given by rˉ=(Asin⁡ωt)i+(Acos⁡ωt)j\bar r = \left( {A\sin \omega t} \right)i + \left( {A\cos \omega t} \right)j. If vv is velocity of particle. Then vˉ. rˉ=\bar v.\,\bar r =
View answer and explanation
Correct option: A
Zero
The horizontal component of a force is given by Fcos⁡θF \cos \theta. Knowing the horizontal component and the angle, we can find the magnitude of the force. Then, the vertical component is Fsin⁡θF \sin \theta, which gives us 87 N, making option C correct.
86 Easy
86 of 91
Understanding +4 | -1
When a projectile is fired at an angle θ\theta wrt. horizontal with velocity uu, then its vertical component
View answer and explanation
Correct option: C
goes on decreasing with height.
Option C (goes on decreasing with height) is correct because the vertical component of velocity decreases due to the effect of gravity as the projectile rises.
87 Easy
87 of 91
Application +4 | -1
If two directional cosine of a vectors are 12\frac{1}{{\sqrt 2 }} and 13\frac{1}{{\sqrt 3 }} then the value of third directional cosine is
View answer and explanation
Correct option: A
16\frac{1}{{\sqrt 6 }}
Option A (16\frac{1}{{\sqrt 6 }}) is correct because the sum of the squares of the directional cosines must equal 1.
88 Easy
88 of 91
Application +4 | -1
Two forces of 12 N and 8 N act upon a body. The resultant forces on the body has maximum value of
View answer and explanation
Correct option: C
20 N
Option C (20 N) is correct because the maximum resultant force occurs when the two forces act in the same direction, and their magnitudes add up.
89 Easy
89 of 91
Application +4 | -1
The two forces are in the ratio of 2:5 maximum and minimum of their resultant are in the ratio of
View answer and explanation
Correct option: C
0.29375
Option C (0.29375) is correct because it represents the ratio of the maximum and minimum resultant forces calculated from the given ratio of the two forces.
90 Easy
90 of 91
Understanding +4 | -1
Which of the following not a vector quantity?
View answer and explanation
Correct option: D
Potential energy
Option D is correct because potential energy is a scalar quantity, while weight, nuclear spin, and momentum are vector quantities.
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