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NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Easy

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Showing 31-60 of 91 questions
31 Easy
31 of 91
Application +4 | -1
If ai^+bj^a \hat{\mathbf{i}}+b \hat{\mathbf{j}} is a unit vector and it is perpendicular to i^+j^\hat{\mathbf{i}}+\hat{\mathbf{j}}, then value of aa and bb is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the given conditions lead to a=12a = \frac{1}{\sqrt{2}} and b=−12b = -\frac{1}{\sqrt{2}} or vice versa, which are not among the options.
32 Easy
32 of 91
Application +4 | -1
If ∣Aˉ+Bˉ∣=∣Aˉ∣=∣Bˉ∣ \left| {\bar A + \bar B} \right| = \left| {\bar A} \right| = \left| {\bar B} \right|\,, the angle between A→\overrightarrow A and B→\overrightarrow B is
View answer and explanation
Correct option: C
120∘120^\circ
Option C (120∘120^\circ) is correct because it satisfies the condition ∣Aˉ+Bˉ∣=∣Aˉ∣=∣Bˉ∣\left| {\bar A + \bar B} \right| = \left| {\bar A} \right| = \left| {\bar B} \right| using the law of cosines.
33 Easy
33 of 91
Understanding +4 | -1
In a projectile motion, velocity at maximum height is
View answer and explanation
Correct option: B
ucos⁡θu\cos \theta
Option B (ucos⁡θu\cos \theta) is correct because at the maximum height, the vertical component of velocity is zero, and only the horizontal component (ucos⁡θu\cos \theta) remains.
34 Easy
34 of 91
Understanding +4 | -1
If a vector P⃗\vec P make angles α, β,\alpha ,\,\beta , and γ\gamma respectively with the X,  YX,\,\,Y and ZZ axes. Then sin⁡2α  +  sin⁡2β  +  sin⁡2γ  ={\sin ^2}\alpha \,\, + \,\,{\sin ^2}\beta \,\, + \,\,{\sin ^2}\gamma \,\, =
View answer and explanation
Correct option: C
2
The correct answer is 2 because the sum of the squares of the direction cosines is 1, and the sum of the squares of the direction sines is 2.
35 Easy
35 of 91
Application +4 | -1
A bat and an insect are flying with velocities V→BG\overrightarrow{{V}}_{\mathrm{BG}} and V→IG \overrightarrow{{V}}_{\text {IG }} respectively with respect to ground (in unit vector i^,j^\hat{{i}}, \hat{{j}} rotation)

V⃗BG =3.5i^+9.2j^,V→IG=−2.5i^+1.8j^\vec{V}_{\text {BG }}=3.5 \hat{{i}}+9.2 \hat{{j}}, \overrightarrow{\mathrm{V}}_{\mathrm{IG}}=-2.5 \hat{{i}}+{1 . 8} \hat{{j}}

Calculate the velocity of the insect with respect to bat.
View answer and explanation
Correct option: B
−6i^−7.4j^-6 \hat{\mathrm{i}}-7.4 \hat{\mathrm{j}}
Option B (−6i^−7.4j^-6 \hat{\mathrm{i}}-7.4 \hat{\mathrm{j}}) is correct because the relative velocity is calculated by subtracting the bat's velocity from the insect's velocity.
36 Easy
36 of 91
Understanding +4 | -1
The vectors ai^+2j^+6k^a \hat{i}+2 \hat{j}+6 \hat{k} and 2i^+2j^+6k^2 \hat{i}+2 \hat{j}+6 \hat{k} are equal vectors. The value of aa is
View answer and explanation
Correct option: A
2
Option A (2) is correct because for two vectors to be equal, their corresponding components must be equal, hence a = 2.
37 Easy
37 of 91
Analyzing +4 | -1
The vectors sum of two forces is perpendicular to their vector differences in that case. The forces
View answer and explanation
Correct option: B
Are equal to each other in magnitude
Option B (Are equal to each other in magnitude) is correct because if the vector sum is perpendicular to the vector difference, the dot product of the sum and difference is zero, implying equal magnitudes.
38 Easy
38 of 91
Analyzing +4 | -1
If A⃗=B⃗,\mathrm{\vec A} = \mathrm{\vec B}, then which of the following is not correct
View answer and explanation
Correct option: B
A^.B^=AB\hat A.\hat B = \mathrm{AB}
Option B (A^.B^=AB\hat A.\hat B = \mathrm{AB}) is not correct because even if the vectors are equal, the dot product of their unit vectors is 1, not the product of their magnitudes.
39 Easy
39 of 91
Application +4 | -1
A\mathbf{A} and B\mathbf{B} are two vectors given by A=2i^+3j^\mathbf{A}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}} and B=2i^+4j^\mathbf{B}=2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}. The magnitude of the component of A\mathbf{A} along B\mathbf{B} is
View answer and explanation
Correct option: C
85\frac{8}{\sqrt{5}}
Option C (85\frac{8}{\sqrt{5}}) is correct because it represents the magnitude of the component of vector A along vector B.
40 Easy
40 of 91
Understanding +4 | -1
For vectors A→ \overrightarrow A \, and B→ \overrightarrow B \, making an angle θ\theta which one of the following relations is correct
View answer and explanation
Correct option: B
A→×B→=ABsin⁡θn^\overrightarrow A \times \overrightarrow B = AB\sin \theta \hat n
Option B (A→×B→=ABsin⁡θn^\overrightarrow A \times \overrightarrow B = AB\sin \theta \hat n) is correct because it represents the magnitude and direction of the cross product of two vectors.
41 Easy
41 of 91
Understanding +4 | -1
If air resistance is not considered in projectiles, the horizontal motion takes place with
View answer and explanation
Correct option: A
constant velocity.
Option A (constant velocity) is correct because in the absence of air resistance, there is no horizontal force acting on the projectile, so its horizontal velocity remains constant.
42 Easy
42 of 91
Analyzing +4 | -1
Assertion(A): When θ=45∘\theta=45^{\circ} or 135∘135^{\circ}, the value of RR remains the same, only the sign changes.

Reason(R): R=u2sin⁡2θgR=\frac{u^2 \sin 2 \theta}{g}
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A (Both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because the range is the same for complementary angles due to the sine function's property, and the formula for range explains this.
43 Easy
43 of 91
Analyzing +4 | -1
I.Inprojectilemotion,theanglebetwee instantaneousvelocityvectorandacceleration vector can be anything between 0 to π\pi (excluding the limiting case.)

II. In projectile motion, acceleration vector is always pointing vertically downwards. (Neglect air friction).

Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because both statements accurately describe projectile motion: the angle between velocity and acceleration can vary, and acceleration always points downwards.
44 Easy
44 of 91
Application +4 | -1
If the resultant of the vector 3iˉ+4jˉ+5kˉ3\bar i + 4\bar j + 5\bar k and 5iˉ+3jˉ+4kˉ5\bar i + 3\bar j + 4\bar k makes an angle θ \theta \, with x-axis. Then find cos⁡θ\cos \theta
View answer and explanation
Correct option: A
0.574
Option A (0.574) is correct because it represents the cosine of the angle between the resultant vector and the x-axis, calculated using the dot product.
45 Easy
45 of 91
Understanding +4 | -1
A scalar quantity is one that
View answer and explanation
Correct option: D
has the same value for observers with different orientations of axes.
Option D (has the same value for observers with different orientations of axes) is correct because a scalar quantity is invariant under coordinate transformations.
46 Easy
46 of 91
Application +4 | -1
Which one of the following pair cannot be the rectangular components of force vector of 10 N?
View answer and explanation
Correct option: D
9 N and 1 N
Option A (6 N and 5 N) is correct because the sum of the squares of the rectangular components must equal the square of the magnitude of the force vector, and 62+52≠1026^2 + 5^2 \neq 10^2.
47 Easy
47 of 91
Application +4 | -1
The horizontal and vertical components of a force are 3 N and 4 N respectively. Then force is
View answer and explanation
Correct option: C
5 N
Option C (5 N) is correct because the magnitude of the force is the square root of the sum of the squares of its components, which is sqrt(32 + 42) = 5 N.
48 Easy
48 of 91
Application +4 | -1
If A⋅B=A×B\mathbf{A} \cdot \mathbf{B}=\mathbf{A} \times \mathbf{B}, then angle between A\mathbf{A} and B\mathbf{B} is
View answer and explanation
Correct option: A
45∘45^{\circ}
Option A (45∘45^{\circ}) is correct because when the magnitudes of the dot product and cross product are equal, the angle between the vectors is 45 degrees.
49 Easy
49 of 91
Application +4 | -1
What is the angle between (i+j) \left( {i + j} \right)\, and (kˉ+jˉ)\left( {\bar k + \bar j} \right)?
View answer and explanation
Correct option: B
60∘60^\circ
Option B is correct because the angle between the two vectors is 60 degrees, which can be found using the dot product formula.
50 Easy
50 of 91
Understanding +4 | -1
Magnitude of component of vector 2i^+6k^2 \hat{i}+6 \hat{k} along yy-axis is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the component of a vector along an axis is zero if the vector has no projection onto that axis. The given vector has no y-component.
51 Easy
51 of 91
Analyzing +4 | -1
Two stones are projected so as to reach the same distance from the point of projection on a horizontal surface. The maximum height reached by one exceeds the other by an amount equal to half the sum of the height attained by them. Then, angle of projection of the stone which attains smaller height is
View answer and explanation
Correct option: C
30∘30^{\circ}
Option C (30∘30^{\circ}) is correct because it satisfies the condition where the maximum height difference is half the sum of the maximum heights, given equal ranges.
52 Easy
52 of 91
Application +4 | -1
A ball is projected with kinetic energy EE at an angle of 45∘45^\circ to the horizontal. At the highest point during its flight, its kinetic energy will be
View answer and explanation
Correct option: B
E/2E/2
Option B (E/2E/2) is correct because at the highest point, only the horizontal component of velocity remains, and the kinetic energy is reduced by half.
53 Easy
53 of 91
Understanding +4 | -1
Statement-I: Angle between i^+j^\hat{i}+\hat{j} and i^\hat{i} is 45∘45^{\circ}.
Statement-II: i^+j^\hat{i}+\hat{j} is equally inclined to both i^\hat{i} and j^\hat{j} and the angle between i^\hat{i} and j^\hat{j} is 90∘90^{\circ}
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct because the angle between i^+j^\hat{i}+\hat{j} and i^\hat{i} is indeed 45 degrees, and the second statement correctly explains why.
54 Easy
54 of 91
Understanding +4 | -1
Which of the following statement is true?
View answer and explanation
Correct option: B
When the coordinate axes are rotated through some angle, components of the vector change but the vector's magnitude remains constant.
Option B is correct because rotating the coordinate axes changes the components of a vector, but its magnitude remains invariant.
55 Easy
55 of 91
Application +4 | -1
A body throws a ball with a velocity of 15 m/s at an angle of 15∘15^\circ with the horizontal. The distance at which the ball strikes the ground is
View answer and explanation
Correct option: D
11.25 m
Option D (11.25 m) is correct because the range is calculated using the initial velocity, angle of projection, and acceleration due to gravity.
56 Easy
56 of 91
Application +4 | -1
The angle made by the vector A⃗=i^+j^ \vec A = \hat i + \hat j\, with y-axis is
View answer and explanation
Correct option: B
45∘45^\circ
The angle made by a vector with the y-axis can be found using the arctangent function. Since the x and y components are equal, the angle with the y-axis is 45 degrees, making option B correct.
57 Easy
57 of 91
Understanding +4 | -1
A vector is added to an equal and opposite vector of similar nature, forms a
View answer and explanation
Correct option: C
null vector
Option C (null vector) is correct because adding a vector to its equal and opposite results in a vector with zero magnitude, which is a null vector.
58 Easy
58 of 91
Understanding +4 | -1
At the top of the trajectory of a projectile, the acceleration is
View answer and explanation
Correct option: D
gg
Option D (gg) is correct because the acceleration of a projectile is always equal to the acceleration due to gravity, regardless of its position in the trajectory.
59 Easy
59 of 91
Application +4 | -1
If Aˉ=5i+7j−3k\bar A = 5i + 7j - 3k and Bˉ=2i+2j−ak\bar B = 2i + 2j - ak are perpendicular vectors. The value of aa is
View answer and explanation
Correct option: D
-8
Option D (-8) is correct because the dot product of two perpendicular vectors is zero, allowing us to solve for 'a'.
60 Easy
60 of 91
Analyzing +4 | -1
Two particles are projected from the same point with the same speed, at different angles θ1\theta_1 and θ2\theta_2 to the horizontal. They have the same horizontal range. Their times of flight are t1t_1 and t2t_2 respectively incorrect statement is.
View answer and explanation
Correct option: C
t1t2=tan⁡θ2\frac{t_1}{t_2}=\tan \theta_2
Option C (t1t2=tan⁡θ2\frac{t_1}{t_2}=\tan \theta_2) is the incorrect statement because the correct relationship is t1t2=tan⁡θ1\frac{t_1}{t_2} = \tan \theta_1.
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