NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Easy

1 of 1

Understanding +4 | -1

In a projectile motion, velocity at maximum height is

View answer and explanation

Correct option: B

u\cos \theta

Option B (

u\cos \theta

) is correct because at the maximum height, the vertical component of velocity is zero, and only the horizontal component (

u\cos \theta

) remains.

More Questions from MOTION IN PLANE

Practice All Chapter MCQs →

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)