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NEET • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Mixed difficulty

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Showing 151-177 of 177 questions
151 Medium
151 of 177
Analyzing +4 | -1
Two rods of copper and steel having same area of cross - section but different lengths l1l_{1} and l2l_{2} respectively are connected to each other. The combined length of two rods fits between two walls without any stress on walls. If α1\alpha_{1} and α2\alpha_{2} are their coefficient of linear expansion, Y1Y_{1} and Y2Y_{2} are their Young's modulus respectively, then (There is no buckling of rods while heating) With increase in temperature:
View answer and explanation
Correct option: D
combined length remains l1+l2l_{1}+l_{2} while length of one rod increases and that of other decreases
The combined length remains l1+l2l_{1}+l_{2} while length of one rod increases and that of other decreases because the system is constrained between two walls, leading to compressive stress in one rod and tensile stress in the other.
152 Medium
152 of 177
Application +4 | -1
In above question, the work done in the two wires is
View answer and explanation
Correct option: A
0.5 J, 0.03 J
Option A (0.5 J, 0.03 J) is the correct answer, representing the work done in the two wires respectively.
153 Medium
153 of 177
Application +4 | -1
A wire is stretched 1mm1\mathrm{ }mm by a force of 1kN1\mathrm{ }k\mathrm{ }N. How far would a wire of the same material and length but of four times that diameter be stretched by the same force ?
View answer and explanation
Correct option: D
116  mm\frac{1}{{16}}\,\,\mathrm{mm}
Option D (116 mm\frac{1}{{16}}\,\mathrm{mm}) is correct because the elongation is inversely proportional to the square of the diameter, so quadrupling the diameter reduces the elongation by a factor of 16.
154 Easy
154 of 177
Understanding +4 | -1
The Young's modulus of a wire is numerically equal to the stress which will
View answer and explanation
Correct option: B
double the length of the wire
Option B (double the length of the wire) is correct because when stress equals Young's modulus, strain equals 1, meaning the length doubles.
155 Medium
155 of 177
Application +4 | -1
Forces of 100 N each are applied in opposite directions on the upper and lower faces of a cube of side 20 cm20\,cm. The upper face is shifted parallel to itself by 0.25 cm0.25\,cm. If the side of the cube were 10 cm, then the displacement would be
View answer and explanation
Correct option: B
0.5 cm0.5\,cm
Option B (0.5 cm0.5\,cm) is correct because the displacement is inversely proportional to the side of the cube for a constant force.
156 Easy
156 of 177
Application +4 | -1
A steel wire is 1 m1 \mathrm{~m} long and 1 mm21 \mathrm{~mm}^2 in area of crosssection. If it takes 200 N200 \mathrm{~N} to stretch this wire by 1 mm1 \mathrm{~mm}, how much force will be required to stretch a wire of the same material as well diameter from its normal length of 10 m10 \mathrm{~m} to a length of 1002 cm1002 \mathrm{~cm} ?
View answer and explanation
Correct option: A
400
The correct answer is 400 because the force required is proportional to the change in length and inversely proportional to the original length.
157 Medium
157 of 177
Understanding +4 | -1
A steel wire is stretched with a definite load. If the Young’s modulus of the wire is YY. For decreasing the value of YY
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because Young's modulus is a material property and does not depend on the dimensions of the wire.
158 Easy
158 of 177
Application +4 | -1
Two forces F1F_1 and F2F_2 are applied on two rods PP and QQ of same materials such that elongation in rods are same. If ratio of their radii is xx : yy and ratio of length is m:nm: n, then ratio of F1:F2F_1: F_2 is
View answer and explanation
Correct option: B
(xy)2⋅nm\left(\frac{x}{y}\right)^2 \cdot \frac{n}{m}
Option B is correct. The ratio of forces is derived from the Young's modulus formula, considering the same elongation and different radii and lengths of the rods.
159 Medium
159 of 177
Understanding +4 | -1
Mark the wrong statement
View answer and explanation
Correct option: C
It is difficult to twist a long rod as compared to small rod
Option C (It is difficult to twist a long rod as compared to small rod) is the wrong statement because it's easier to twist a long rod compared to a short rod, given the same torque.
160 Medium
160 of 177
Application +4 | -1
Two spring PP and QQ of force constants kp{k_p} and kQ(kQ=kp2){k_Q}\left( {{k_Q} = \frac{{{k_p}}}{2}} \right) are stretched by applying forces of equal magnitude if the energy stored in QQ is EE, then the energy stored in PP is
View answer and explanation
Correct option: D
E2\frac{E}{2}
Option D (E2\frac{E}{2}) is correct because the energy stored in a spring is inversely proportional to the spring constant when the applied force is the same.
161 Medium
161 of 177
Application +4 | -1
Two wires of same material and radius have their lengths in ratio 1:21:2. If these wires are stretched by the same force, the strain produced in the two wires will be in the ratio
View answer and explanation
Correct option: C
1:21:2
Option C (1:21:2) is correct because strain is directly proportional to the length when the material, radius, and force are the same.
162 Medium
162 of 177
Understanding +4 | -1
Assertion: From the relation Y=FlAΔl,Y=\frac{F l}{A \Delta l}, we can say that, if length of a wire is doubled, its Young's modulus of elasticity will also becomes two times.

Reason: Modulus of elasticity is a material property.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true
Option D (If Assertion is false but the Reason is true) is correct because Young's modulus is a material property and does not change with length.
163 Medium
163 of 177
Understanding +4 | -1
Statement-I: Rigidity modulus of a liquid is infinity
Statement-II: For a ductile material yield point and breaking point are separated by larger distance than for brittle materials on the stress-strain curve.
View answer and explanation
Correct option: C
Statement I is false and statement II is true
Option C (Statement I is false and statement II is true) is correct because rigidity modulus of a liquid is zero, and ductile materials have a larger separation between yield and breaking points.
164 Medium
164 of 177
Understanding +4 | -1
Which statement is true for a metal
View answer and explanation
Correct option: C
Y>ηY > \eta
Option C (Y>ηY > \eta) is correct. Young's modulus (Y) and shear modulus (η\eta) are material properties, and for metals, Young's modulus is generally greater than the shear modulus.
165 Easy
165 of 177
Application +4 | -1
If to break a wire of 1 m1 \mathrm{~m} length, minimum 40 kg40 \mathrm{~kg}-wt is required, then to break a wire of same material 6 m6 \mathrm{~m} in length and double in radius, the breaking weight required will be
View answer and explanation
Correct option: C
160 kg160 \mathrm{~kg}-wt
Option C (160 kg160 \mathrm{~kg}-wt) is correct because the breaking force is proportional to the cross-sectional area, which is proportional to the square of the radius.
166 Easy
166 of 177
Application +4 | -1
A wire of length '2 m2 \mathrm{~m}' is clamped horizontally between two fixed support. A mass m=5 kg\mathrm{m}=5 \mathrm{~kg} is hanged from middle of wire. The vertical and depression in wire (in cm\mathrm{cm}) in equilibrium is (Young modulus of wire =2.4×109 N/m2=2.4 \times 10^9 \mathrm{~N} / \mathrm{m}^2, cross-sectional area =1 cm2=1 \mathrm{~cm}^2)
View answer and explanation
Correct option: A
5
Option A is correct. The vertical depression in the wire is calculated using the formula for the sag of a wire under its own weight, considering Young's modulus and the wire's properties.
167 Medium
167 of 177
Application +4 | -1
To break a wire of one metre length, minimum 40  kg  wt40\;kg\;wt, is required. Then the wire of the same material of double radius and 6 m length will require breaking weight
View answer and explanation
Correct option: D
160  kg−wt160\;kg - wt
Option D is correct. The breaking weight is proportional to the cross-sectional area, which depends on the square of the radius. Doubling the radius and multiplying the length by 6 increases the breaking weight by a factor of 4.
168 Medium
168 of 177
Remembering +4 | -1
Which of the following relation is true?
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Correct option: D
(1+σ)2η=Y\left( {1 + \sigma } \right)2\eta = Y
Option D ((1+σ)2η=Y\left( {1 + \sigma } \right)2\eta = Y) is correct because it represents the correct relationship between Young's modulus (Y), shear modulus (η\eta), and Poisson's ratio (σ\sigma).
169 Hard
169 of 177
Application +4 | -1
A copper wire (Y=1011Nm−2)\left(Y=10^{11} \mathrm{Nm}^{-2}\right) of length 8 m8 \mathrm{~m} and a steel wire (Y=2×1011Nm−2)\left(Y=2 \times 10^{11} \mathrm{Nm}^{-2}\right) of length 4 m4 \mathrm{~m}, each of 0.5 cm20.5 \mathrm{~cm}^2 cross-section are fastened end-to-end and stretched with a tension of 500 N500 \mathrm{~N}. Choose the correct statement.
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because the elongation in each wire, the relationship between them, and the total elongation are all accurately calculated and consistent with the given information.
170 Medium
170 of 177
Remembering +4 | -1
The modulus of elasticity is dimensionally equivalent to
View answer and explanation
Correct option: B
Stress
Option B (Stress) is correct because both modulus of elasticity and stress have the same dimensional formula.
171 Medium
171 of 177
Analyzing +4 | -1
A: Equal amount of work is done when two identical springs of steel and copper are equally streched
R: Both springs have same spring constant.
View answer and explanation
Correct option: D
If both A and R are false
Option D (If both A and R are false) is correct because the work done depends on the spring constant, which is different for steel and copper, and thus the spring constants are not the same.
172 Medium
172 of 177
Understanding +4 | -1
In materials like aluminium and copper, the correct order of magnitude of various elastic modulii is:
View answer and explanation
Correct option: C
Shear modulii << Young's modulii << bulk modulii
Option C (Shear modulii << Young's modulii << bulk modulii) is correct because, for most materials, the shear modulus is the smallest, followed by Young's modulus, and the bulk modulus is the largest.
173 Medium
173 of 177
Understanding +4 | -1
If a wire is stretched such that its length becomes double then
View answer and explanation
Correct option: D
Young's modulus of wire is equal to stress
Option D (Young's modulus of wire is equal to stress) is correct because when the length is doubled, strain is 1, and Young's modulus equals stress.
174 Medium
174 of 177
Analyzing +4 | -1
Statement I: A steel wire of natural length 'ℓ\ell' breaks, when clongated by length 'xx'. If original length is halved and elongated by x/2x / 2 it breaks.
Statement II: Breaking force is directly proportional to the length of the wire.
View answer and explanation
Correct option: B
Statement I is true and statement II is false
Statement I is true and statement II is false because the breaking stress is a material property and independent of length, while the breaking force depends on the area of cross-section.
175 Medium
175 of 177
Understanding +4 | -1
Which one of the following quantities does not have the unit of force per unit area
View answer and explanation
Correct option: B
Strain
Option B (Strain) is correct because strain is a dimensionless quantity, representing the ratio of change in length to original length, and thus has no units of force per unit area.
176 Medium
176 of 177
Understanding +4 | -1
Steel is preferred for making spring over
copper. Why?
View answer and explanation
Correct option: B
Young's Modulus of steel is more than that of copper
Option B (Young's Modulus of steel is more than that of copper) is correct because a higher Young's modulus indicates greater stiffness, making steel a better choice for springs.
177 Medium
177 of 177
Remembering +4 | -1
Within proportional limit, the slope of the stress stain curve yields,
View answer and explanation
Correct option: B
Modulus of elasticity
Option B (Modulus of elasticity) is correct because the slope of the stress-strain curve within the proportional limit represents the modulus of elasticity, which quantifies the material's stiffness.
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