Skip to main content
Back to MECHANICAL PROPERTIES OF SOLIDS

Your Progress

0 / 177 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 121-150 of 177 questions

Preparing practice and saved progress…

121 Medium
121 of 177
Understanding +4 | -1
If xx longitudinal strain is produced in a wire of Young’s modulus yy, then energy stored in the material of the wire per unit volume is
View answer and explanation
Correct option: D
12yx2\frac{1}{2}y{x^2}
Option D (12yx2\frac{1}{2}y{x^2}) is correct because it represents the energy stored per unit volume in a wire with longitudinal strain x and Young's modulus y.
122 Medium
122 of 177
Analyzing +4 | -1
Statement I: Two identical solid balls, one of ivory and the other of wet-clay are dropped from the same height on the floor. Both the balls will rise to same height after bouncing.
Statement II: Ivory and wet-clay have same elasticity.
View answer and explanation
Correct option: D
Statement I is false and statement II is false
Option D is correct because Statement I is false as the ivory ball will bounce higher due to its higher elasticity, and Statement II is false because ivory and wet-clay do not have the same elasticity.
123 Medium
123 of 177
Remembering +4 | -1
Thermal stress, If developed in a solid on heating is given by
View answer and explanation
Correct option: A
yΔlly\frac{{\Delta l}}{l}
Option A (yΔlly\frac{{\Delta l}}{l}) is correct because thermal stress is given by Young's modulus times the strain.
124 Easy
124 of 177
Application +4 | -1
On all the six surfaces of a unit cube, equal tensile force of FF is applied. The increase in length of each side will be (Y=(Y = Young’s modulus, σ=\sigma = Poisson’s ratio)
View answer and explanation
Correct option: C
F(1−2σ)Y\frac{{F\left( {1 - 2\sigma } \right)}}{Y}
Option C (F(1−2σ)Y\frac{{F\left( {1 - 2\sigma } \right)}}{Y}) is correct because it represents the increase in length of each side when equal tensile force is applied on all six surfaces of a unit cube.
125 Medium
125 of 177
Understanding +4 | -1
What is the Young's modulus of elasticity for a perfectly rigid body?
View answer and explanation
Correct option: A
Infinity
Option A is correct because a perfectly rigid body does not deform under any stress, thus its Young's modulus is infinite.
126 Easy
126 of 177
Remembering +4 | -1
Rubber is an example of
View answer and explanation
Correct option: C
Elastomer
Option C (Elastomer) is correct because rubber exhibits high elasticity and can undergo large deformations under stress, characteristic of elastomers.
127 Medium
127 of 177
Application +4 | -1
A tensile force of 2×103 N2 \times {10^3}\,\mathrm{N} doubles the length of a rubber band of cross-sectional area 2×10−4 m22 \times {10^{ - 4}}\,{\mathrm{m}^2}. The Young’s modulus of elasticity of the rubber band is
View answer and explanation
Correct option: C
107 Nm−2{10^7}\,\mathrm{N}{\mathrm{m}^{ - 2}}
Option C is correct. Young's modulus is calculated using the formula Y = (F/A) / (ΔL/L), where the length doubles, meaning ΔL = L.
128 Hard
128 of 177
Application +4 | -1
A steel wire of length 2 m and Young's modulus 2.0×1011Nm−22.0 \times 10^{11} \mathrm{Nm}^{-2} is stretched by a force. If Poisson ratio and transverse strain for the wire are 0.2 and 10−310^{-3} respectively, then the elastic potential energy density of the wire is _____ ×105\times 10^5 (in SI units)
View answer and explanation
Correct option: A
25
Option A (25) is correct because the elastic potential energy density is calculated using the formula involving Young's modulus and transverse strain.
129 Easy
129 of 177
Understanding +4 | -1
When a force is applied at one end of an elastic wire, it produces a strain EE in the wire. If YY is the Young's modulus of the material of the wire, the amount of energy stored per unit volume of the wire is given by
View answer and explanation
Correct option: D
12(Y×E2)\frac{1}{2}\left(Y \times E^2\right)
Option D, 12(Y×E2)\frac{1}{2}(Y \times E^2), is correct because it represents the energy stored per unit volume in an elastic material, derived from the area under the stress-strain curve.
130 Medium
130 of 177
Understanding +4 | -1
The general form of potential energy curve for atoms or molecules can be represented by the following equation U(R)=ARn−BRmU\left( R \right) = \frac{A}{{{R^n}}} - \frac{B}{{{R^m}}} . Here, R is the interatomic or molecular distance, A and B are coefficients, nn and mm are the exponents. In the above equation
View answer and explanation
Correct option: B
Second term represents the attractive part of the potential
Option B (Second term represents the attractive part of the potential) is correct because the negative sign in front of the second term indicates an attractive force as the distance R increases.
131 Medium
131 of 177
Remembering +4 | -1
A metal wire of length L,L, area of cross section AA and Young's modulus YY behaves as a spring of spring constant kk given by:
View answer and explanation
Correct option: A
k=YA/Lk={YA} / {L}
Option A (k=YA/Lk={YA} / {L}) is correct because it represents the spring constant derived from Young's modulus definition.
132 Medium
132 of 177
Understanding +4 | -1
Which of the following statements is correct
View answer and explanation
Correct option: A
Hooke’s law is applicable only within elastic limit
Option A (Hooke’s law is applicable only within elastic limit) is correct because Hooke's law is only valid within the elastic limit of a material.
133 Easy
133 of 177
Remembering +4 | -1
The value of modulus of rigidity for ideal liquid is
View answer and explanation
Correct option: A
0
Option A (0) is correct because an ideal liquid cannot resist shear stress, hence its modulus of rigidity is zero.
134 Hard
134 of 177
Application +4 | -1
If compressibility of a material is 4×10−54 \times 10^{-5} per atm, pressure is 100 atm100 \mathrm{~atm} and volume is 100 cm3100 \mathrm{~cm}^3, then find the value of ΔV\Delta V.
View answer and explanation
Correct option: A
0.4 cm30.4 \mathrm{~cm}^3
Option A (0.4 cm30.4 \mathrm{~cm}^3) is correct because it is the correct change in volume calculated using the compressibility formula.
135 Easy
135 of 177
Understanding +4 | -1
A long piece of rubber is wider than it is thick. When is is stretched in length by some amount:
View answer and explanation
Correct option: D
Both its thickness and width decrease
Option D (Both its thickness and width decrease) is correct because when a rubber piece is stretched, its dimensions perpendicular to the direction of the force decrease due to Poisson's effect.
136 Medium
136 of 177
Application +4 | -1
A force FF is required to break a wire of length II and radius rr. What force is required to break a wire, of the same material, having twice the length and six times the radius ?
View answer and explanation
Correct option: D
36F
Option D (36F) is correct because the breaking force is proportional to the area, which is proportional to the square of the radius.
137 Medium
137 of 177
Analyzing +4 | -1
A metal wire of length LL is suspended vertically from a rigid support. When a body of mass MM is attached to the lower end of wire, the elongation of the wire is ℓ\ell, then the incorrect statement is
View answer and explanation
Correct option: D
The elastic potential energy in the wire is Mgℓ{Mg}\ell
Option D (The elastic potential energy in the wire is Mgℓ{Mg}\ell) is correct because the elastic potential energy stored is half the loss in gravitational potential energy, which is Mg\ell/2.
138 Medium
138 of 177
Understanding +4 | -1
Young’s modulus of perfectly rigid body material is
View answer and explanation
Correct option: A
Infinite
Option A is correct because a perfectly rigid body material has infinite Young's modulus as it does not deform under any stress.
139 Medium
139 of 177
Analyzing +4 | -1
A: To minimize the depression in a beam, it is designed as 'I{I}' shape girder.
R: The 'II' shape girders have large load bearing surface, which decreases the stress
View answer and explanation
Correct option: A
If both A &\& R are true and the R is the correct explanation of the A
Option A (If both A & R are true and the R is the correct explanation of the A) is correct because I-shaped girders are designed to minimize depression by having a large load-bearing surface, which reduces stress.
140 Medium
140 of 177
Understanding +4 | -1
The specific heat at constant pressure and at constant volume for an ideal gas are Cp{C_p} and Cv{C_v} and its adiabatic and isothermal elasticities are Eϕ{E_\phi } and Eθ{E_\theta } respectively. The ratio of Eϕ{E_\phi } to Eθ{E_\theta } is
View answer and explanation
Correct option: B
Cp/Cv{C_p}/{C_v}
Option B (Cp/Cv{C_p}/{C_v}) is correct because the adiabatic elasticity is γ\gamma times the isothermal elasticity, and γ=Cp/Cv\gamma = C_p/C_v.
141 Hard
141 of 177
Application +4 | -1
The density of a metal at normal pressure is ρ\rho. Its density when it is subjected to an excess pressure pp is ρ′\rho^{\prime}. If BB is the bulk modulus of the metal, then the ratio ρ′/ρ\rho^{\prime} / \rho is
View answer and explanation
Correct option: D
1(1−p/B)\frac{1}{(1-p / B)}
Option D (1(1−p/B)\frac{{1}}{{(1-p / B)}}) is correct because it relates the change in density to the applied pressure and the bulk modulus.
142 Medium
142 of 177
Understanding +4 | -1
Which of the following statements is/are wrong?
I. Hollow shaft is much stronger than a solid rod of same length and same mass
II. Reciprocal of bulk modulus of elasticity is called compressibility
III. It is difficult to twist a long rod as compared to small rod.
View answer and explanation
Correct option: C
III only
Option C (III only) is correct because statement III is wrong; it's easier to twist a long rod compared to a short rod of the same material and cross-section.
143 Medium
143 of 177
Understanding +4 | -1
Which one of the following statements is correct? In the case of
View answer and explanation
Correct option: B
Tensile stress there is no change in volume
Option B (Tensile stress there is no change in volume) is correct because tensile stress primarily causes a change in length, with a relatively small change in volume.
144 Medium
144 of 177
Understanding +4 | -1
On stretching a wire, the elastic energy stored per unit volume is
View answer and explanation
Correct option: A
Fl/2ALFl/2AL
Option A (Fl/2ALFl/2AL) is correct because it represents the elastic energy stored per unit volume in a stretched wire, where F is the force, l is the extension, A is the area, and L is the original length.
145 Medium
145 of 177
Analyzing +4 | -1
A load suspended by a massless spring produces an extension of x  cmx\,\,cm in equilibrium. When it is cut into two unequal parts, the same load produces an extension of 7.5  cm7.5\,\,cm when suspended by the larger part of length 60 cm. When it is suspended by the smaller part, the extension is 5.0 cm Then
View answer and explanation
Correct option: A
x=12.5x = 12.5
Option A (x=12.5x = 12.5) is correct because the extension is inversely proportional to the spring constant, which is inversely proportional to the length of the spring.
146 Medium
146 of 177
Analyzing +4 | -1
Given below are two statements : One is labelled as, Assertion (A) and the other is labelled as Reason (R)
Assertion (A) : The stretching of a spring is determined by the shear modulus of the material of the spring.
Reason (R) : A coil spring of copper has more tensile strength than a steel spring of same dimensions.
In the light of the above statements, choose the most, appropriate answer from the options given below
View answer and explanation
Correct option: D
(A) is true but (R) is false
Option D ((A) is true but (R) is false) is correct because the stretching of a spring is indeed determined by the shear modulus, but copper does not have more tensile strength than steel.
147 Hard
147 of 177
Application +4 | -1
A rigid bar of mass MM is supported symmetrically by three wires each of length LL. Those at each end are of copper and the middle one is of iron. The ratio of their diameters, if each is to have the same tension, is equal to
View answer and explanation
Correct option: B
Yiron Ycopper \sqrt{\frac{Y_{\text {iron }}}{Y_{\text {copper }}}}
Option B (Yiron Ycopper \sqrt{\frac{Y_{\text {iron }}}{Y_{\text {copper }}}}) is correct because the ratio of diameters is related to the square root of the ratio of Young's moduli to maintain the same tension in each wire.
148 Easy
148 of 177
Understanding +4 | -1
According to Hooke’s law of elasticity, if stress is increased, them the ratio of stress to strain
View answer and explanation
Correct option: B
Remains constant
Option B (Remains constant) is correct because Hooke's law states that the ratio of stress to strain is constant within the elastic limit.
149 Medium
149 of 177
Understanding +4 | -1
If the length of a wire is made double and radius is
halved of its respective values. Then, the Young's
modulus of the material of the wire will :
View answer and explanation
Correct option: A
remain same
Option A (remain same) is correct because Young's modulus is a material property and does not depend on the dimensions of the wire.
150 Medium
150 of 177
Analyzing +4 | -1
Assertion: If length of a rod is doubled, the breaking load remains the same.
Reason: Breaking load is equal to the elastic limit.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because the breaking load depends on the cross-sectional area and is independent of the length, and breaking load is not equal to the elastic limit.
Revision notes and key takeaways

Review MECHANICAL PROPERTIES OF SOLIDS in your textbook or class notes, then use this set to check your understanding.

Showing 121-150 of 177 questions

Your practice

0 / 177 answered · 177 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.