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NEET • PHYSICS • GRAVITATION

Gravitation practice · Mixed difficulty

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Showing 121-150 of 255 questions

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121 Easy
121 of 255
Remembering +4 | -1
The escape velocity of a projectile from the earth is approximately
View answer and explanation
Correct option: C
11.2 km/sec11.2 \mathrm{~km} / \mathrm{sec}
Option C (11.2 km/sec11.2 \mathrm{~km} / \mathrm{sec}) is correct because it is the approximate value of the escape velocity from Earth.
122 Medium
122 of 255
Remembering +4 | -1
Hubble's law is related with
View answer and explanation
Correct option: B
speed of galaxy
Option B is correct because Hubble's law describes the relationship between the distance of galaxies and their recessional velocity.
123 Easy
123 of 255
Remembering +4 | -1
The escape velocity of a particle from the surface of the earth is given by
View answer and explanation
Correct option: B
(2gR)1/2(2 g R)^{1 / 2}
Option B ((2gR)1/2(2 g R)^{1 / 2}) is correct because it represents the formula for escape velocity derived from equating kinetic and potential energy.
124 Medium
124 of 255
Remembering +4 | -1
According to Kepler, the period of revolution of a planet (TT) and its mean distance from the sun (rr) are related by the equation
View answer and explanation
Correct option: B
T2r−3={T^2}{r^{ - 3}} = constant
Option B (T2r−3={T^2}{r^{ - 3}} = constant) is correct because Kepler's Third Law states that the square of the period is proportional to the cube of the semi-major axis (mean distance).
125 Medium
125 of 255
Analyzing +4 | -1
Statement I: If ice on the pole melts, length of the day will shorten.

Statement II: Ice will flow towards equator and will result in the decrease in moment of inertia of earth resulting in decrease in frequency of rotation of earth.
View answer and explanation
Correct option: C
If Statement - I is true but Statement - II is false.
Option C is correct because Statement I is true (melting ice at the poles increases the moment of inertia, slowing rotation and lengthening the day), but Statement II is false (the moment of inertia increases, decreasing the frequency).
126 Easy
126 of 255
Understanding +4 | -1
Assertion: When a planet moves in elliptical orbit around sun, its angular momentum about sun remains conserved.
Reason: Total energy of the planet remains conserved
View answer and explanation
Correct option: B
Assertion is True, Reason is True; Reason is NOT a correct explanation for Assertion
Option B is correct because angular momentum and total energy are both conserved in a planet's elliptical orbit around the sun.
127 Medium
127 of 255
Analyzing +4 | -1
(A): The angular velocity of a planets orbiting around the sun increases when they are nearest to the sun.
(R): The angular momentum of body is proportional to angular velocity.
View answer and explanation
Correct option: B
Both (A) and (R) are true and (R) is not the correct explanation of (A)
Option B (Both (A) and (R) are true and (R) is not the correct explanation of (A)) is correct because planets move faster when closer to the sun due to conservation of angular momentum, and angular momentum is proportional to angular velocity, but the latter doesn't explain the former.
128 Medium
128 of 255
Remembering +4 | -1
For elliptical orbits, in the equation T2=(4π2GMs)R3,RT^2=\left(\frac{4 \pi^2}{{GM}_s}\right) R^3, R refers to
View answer and explanation
Correct option: D
Semi-major axis
Option D is correct because R in the equation refers to the semi-major axis of the elliptical orbit.
129 Medium
129 of 255
Application +4 | -1
Given that centripetal force F=−k/r2F = - k/{r^2}. The total energy is
View answer and explanation
Correct option: D
−k/2r- k/2r
Option D (−k/2r- k/2r) is correct because the total energy is the sum of kinetic and potential energy, where potential energy is -k/r and kinetic energy is k/2r.
130 Medium
130 of 255
Analyzing +4 | -1
Given below are two statements:

Statement I: If EE be the total energy of a satellite moving around the earth, then its potential energy will be E2\frac{E}{2}.

Statement II: The kinetic energy of a satellite revolving in an orbit is equal to the half the magnitude of total energy EE.


In the light of the above statements, choose the most appropriate answer from the options given below
View answer and explanation
Correct option: D
Both Statement I and Statement II are incorrect
Option D (Both Statement I and Statement II are incorrect) is correct because the potential energy of a satellite is −2E-2E and the kinetic energy is −E-E, where EE is the total energy.
131 Medium
131 of 255
Understanding +4 | -1
Which of the following statement is always correct about a planet revolving around sun?
View answer and explanation
Correct option: D
Areal velocity of planet is constant
Option D (Areal velocity of planet is constant) is correct because Kepler's second law states that the areal velocity of a planet revolving around the sun remains constant.
132 Medium
132 of 255
Analyzing +4 | -1
Assertion: Angular speed of a planet around the sun increases, when it is closer to the sun.

Reason: Total angular momentum of the system remains constant.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because angular momentum conservation leads to an increase in angular speed when the planet is closer to the sun.
133 Medium
133 of 255
Understanding +4 | -1
A planet revolving in elliptical orbit has
I. a constant velocity of revolution
II. has the least velocity when it is nearest to the sun
III. its areal velocity is directly proportional to its velocity.
IV. areal velocity is inversely proportional to its velocity.
V. to follow a trajectory such that the areal velocity is constant.
Choose the correct answer from the options given below.
View answer and explanation
Correct option: D
Only V
Option V is correct because a planet follows a trajectory such that its areal velocity is constant, as stated by Kepler's Second Law.
134 Medium
134 of 255
Application +4 | -1
Energy required to move an Earth’s satellite of mass m from an orbit of radius R to 5R is (M = mass of earth, R = radius of earth)
View answer and explanation
Correct option: B
2GMm3R\frac{{2GMm}}{{3R}}
Option D (2GMm3R\frac{{2GMm}}{{3R}}) is correct because it represents the difference in potential energy between the two orbits.
135 Medium
135 of 255
Application +4 | -1
Two particles of equal masses are revolving in circular paths of radii r1 and r2{r_1}\,and\,{r_2} respectively with the same speed. The ratio of their centripetal forces is
View answer and explanation
Correct option: A
r2r1\frac{{{r_2}}}{{{r_1}}}
Option A (r2r1\frac{{{r_2}}}{{{r_1}}}) is correct because the centripetal force is inversely proportional to the radius when mass and speed are constant.
136 Medium
136 of 255
Application +4 | -1
A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be
View answer and explanation
Correct option: C
1.6  π2m/s21.6\;{\pi ^2}m/{s^2}
Option C (1.6  π2m/s21.6\;{\pi ^2}m/{s^2}) is correct because it is the centripetal acceleration calculated using the formula a=rω2a = r\omega^2 where ω=2πf\omega = 2\pi f.
137 Medium
137 of 255
Understanding +4 | -1
If the earth stops rotating, the value of gg at the equator
View answer and explanation
Correct option: A
increases
Option A is correct because if the Earth stops rotating, the centrifugal force at the equator becomes zero, effectively increasing the value of g.
138 Easy
138 of 255
Understanding +4 | -1
A planet is revolving round the sun in an elliptical orbit, If v\mathbf{v} is the velocity of the planet when its position vector from the sun is r\mathbf{r}, then areal velocity of the planet is
View answer and explanation
Correct option: C
∣12(r×v)∣\left|\frac{1}{2}(\mathbf{r} \times \mathbf{v})\right|
Option C is correct because the areal velocity is half the magnitude of the cross product of the position vector and velocity.
139 Easy
139 of 255
Analyzing +4 | -1
Assertion: Satellite is put in an orbit at a height where air resistance is present, then orbital velocity of the satellite will decrease.
Reason: Due to air resistance a lot of heat will be produced which may burn satellite
View answer and explanation
Correct option: B
Assertion is True, Reason is True; Reason is NOT a correct explanation for Assertion
Option B is correct because the assertion is true (orbital velocity decreases due to air resistance), the reason is also true (heat is produced), but the reason doesn't correctly explain the assertion. The decrease in velocity is due to energy loss from friction, not directly from the heat produced.
140 Medium
140 of 255
Analyzing +4 | -1
The mass of the moon is 18\frac{1}{8} of the earth but the gravitational pull is 16\frac{1}{6} of the earth. It is due to the fact that
View answer and explanation
Correct option: C
The radius of the earth is 8/6\sqrt {8/6} of the moon
Option C (The radius of the earth is 8/6\sqrt {8/6} of the moon) is correct because it correctly relates the gravitational pull, masses, and radii of the Earth and Moon.
141 Medium
141 of 255
Analyzing +4 | -1
Two identical trains PP and QQ move with equal speeds on parallel tracks along the equator. PP moves from east to west and QQ from west to east
View answer and explanation
Correct option: D
Train PP exerts greater force on track
Option D (Train PP exerts greater force on track) is correct because the Coriolis force acts differently on objects moving in opposite directions on a rotating frame of reference like Earth.
142 Medium
142 of 255
Understanding +4 | -1
Acceleration due to gravity is maximum at (R is the radius of earth)
View answer and explanation
Correct option: C
The surface of the earth
Option C (The surface of the earth) is correct because the acceleration due to gravity is maximum at the surface of the Earth.
143 Medium
143 of 255
Application +4 | -1
A pallet of mass 1 g is moving with an angular velocity of 1 rads  −1\mathrm{rads}{\mathrm{\;}^{ - 1}} along a circle of radius 1 m the centrifugal force is
View answer and explanation
Correct option: D
100 dyne
Option D (100 dyne) is correct because the centrifugal force is calculated using the formula F=mrω2F = mr\omega^2 with the mass converted to grams and radius in cm.
144 Easy
144 of 255
Understanding +4 | -1
According to Newton's law of gravitation, the magnitude of the force FF on point masses m1m_1 and m2m_2 (say) is given by ∣F∣=Gm1m2r2|F|=\frac{G m_1 m_2}{r^2}.
I. This equation is not directly applicable for the gravitational force between extended object (like the earth) and a point mass.
II. This equation can be applied to find the gravitational force between an extended object and a point mass provided rr is the distance of the point mass from the geometric centre of the extended objects.
Which of the following statement(s) about this equation is/are correct?
View answer and explanation
Correct option: A
Only I
Option A is correct because Newton's law of gravitation is not directly applicable for extended objects without integration.
145 Medium
145 of 255
Analyzing +4 | -1
A rocket is intended to leave the Earth’s gravitational field. The
fuel in its main engine is a little less than the amount that is
necessary and an auxiliary engine, (only capable of operating
for a short time) has to be used as well. When is it best to switch
on: the auxiliary engine?
View answer and explanation
Correct option: A
At take-off
Option A (At take-off) is correct because maximizing velocity early allows the rocket to overcome gravity more effectively.
146 Medium
146 of 255
Understanding +4 | -1
If the angular speed of the earth is doubled, the value of acceleration due to gravity (g) at the north pole
View answer and explanation
Correct option: C
Remains same
Option C (Remains same) is correct because the acceleration due to gravity at the North Pole is not affected by the Earth's rotation.
147 Medium
147 of 255
Application +4 | -1
At what height from the surface of earth the total energy of a satellite is equal to its potential energy at a height of 2R from surface of earth…. (R = Radius of earth)
View answer and explanation
Correct option: B
R/2
Option B (R/2) is correct because the total energy of a satellite is half of its potential energy at a height of 2R.
148 Easy
148 of 255
Application +4 | -1
Given mass of the moon is 164\frac{1}{{64}} of the mass of the earth and corresponding radius is 116\frac{1}{{16}} of the earth. If the escape velocity on the earth surface is 11.2 km/s, the value of same on the surface of the moon is [km/s]
View answer and explanation
Correct option: C
5.6
Correct Answer: 5.6. The escape velocity is proportional to the square root of (mass/radius).
149 Medium
149 of 255
Analyzing +4 | -1
If gravitational constant is decreasing with time, what will remain unchanged in case of a satellite orbiting around earth
View answer and explanation
Correct option: C
tangential velocity
Option C (tangential velocity) is correct because the tangential velocity depends on the gravitational constant and the radius, but the product GMGM remains constant if GG decreases proportionally to an increase in MM.
150 Hard
150 of 255
Application +4 | -1
A particle of mass mm was transferred from infinity into the centre of the base of a uniform hemisphere of mass MM and radius R.R. What work was performed in the process by the gravitational force exerted on the particle by the hemisphere?
View answer and explanation
Correct option: B
3GmM2R\frac{3 G m M}{2 R}
Option B (3GmM2R\frac{{3 G m M}}{{{2 R}}}) is correct because it represents the work done by gravity in bringing the particle from infinity to the center of the hemisphere's base.
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